upload

问题 Does anyone know of a good way to automatically run certain file types through a processing script on upload? I'm trying to accomplish automatically minifying CSS and Javascript when I upload them to the server, keeping a nice, human-readable version on the local side while keeping a minified one on the server. I'm currently using WinSCP on Windows, which is scriptable to some degree but might not be scriptable enough. I'd probably need some kind of cobbled-together solution, so don't be

问题 I am using jQuery to do AJAX uploading with additional data. The Stackoverflow code I am following it this one How can I upload files asynchronously? and the code I am using is the following: var formData = new FormData($('form')[0]); $.ajax({ type: "POST", url: "ajax/register.php", dataType: "text", data: { name: $("#name").val(), city: $("#city").val(), image: formData }, success: function(text) { if(text == "data ok pic ok") { window.location = "reg3.php"; } else { errorMessage(text); } },

问题 I am using jQuery to do AJAX uploading with additional data. The Stackoverflow code I am following it this one How can I upload files asynchronously? and the code I am using is the following: var formData = new FormData($('form')[0]); $.ajax({ type: "POST", url: "ajax/register.php", dataType: "text", data: { name: $("#name").val(), city: $("#city").val(), image: formData }, success: function(text) { if(text == "data ok pic ok") { window.location = "reg3.php"; } else { errorMessage(text); } },

问题 I'm trying to upload image to Google Cloud Storage for a couple days. I tried to use Google APIs Client Library for Objective-C from this link https://code.google.com/p/google-api-objectivec-client/wiki/Introduction. Here is my code implementation: _serviceStorage = [GTLServiceStorage new]; _serviceStorage.APIKey = API_KEY; _serviceStorage.additionalHTTPHeaders = @{@"x-goog-project-id": PROJECT_ID}; GTLUploadParameters *uploadParam = [GTLUploadParameters uploadParametersWithData:_imageData

问题 I'm trying to upload image to Google Cloud Storage for a couple days. I tried to use Google APIs Client Library for Objective-C from this link https://code.google.com/p/google-api-objectivec-client/wiki/Introduction. Here is my code implementation: _serviceStorage = [GTLServiceStorage new]; _serviceStorage.APIKey = API_KEY; _serviceStorage.additionalHTTPHeaders = @{@"x-goog-project-id": PROJECT_ID}; GTLUploadParameters *uploadParam = [GTLUploadParameters uploadParametersWithData:_imageData

问题 I have some code working that uploads a video file up to YouTube: $yt = new Zend_Gdata_YouTube($httpClient); // create a new VideoEntry object $myVideoEntry = new Zend_Gdata_YouTube_VideoEntry(); // create a new Zend_Gdata_App_MediaFileSource object $filesource = $yt->newMediaFileSource('file.mov'); $filesource->setContentType('video/quicktime'); // set slug header $filesource->setSlug('file.mov'); I have videos in S3 and I want to upload them to YouTube. The video in our S3 account is public

问题 This question already has answers here : PHP: How to generate a random, unique, alphanumeric string? (27 answers) Closed 6 years ago . How would I go about creating a random string of text for use with file names? I am uploading photos and renaming them upon completion. All photos are going to be stored in one directory so their filenames need to be unique. Is there a standard way of doing this? Is there a way to check if the filename already exists before trying to overwrite? This is for a

问题 I try to upload an ear created by maven to an application server using scp. When I tried to run mvn wagon:upload-single But I get the following error: [ERROR] Failed to execute goal org.codehaus.mojo:wagon-maven-plugin:1.0-beta-3:upload-single (default-cli) on project de.volkswagen.dps.ear: Unable to create a Wagon instance for null: url can not be null -> [Help 1] org.apache.maven.lifecycle.LifecycleExecutionException: Failed to execute goal org.codehaus.mojo:wagon-maven-plugin:1.0-beta-3

问题 Is there a web2py way of displaying images from a database table? Example: The model: db.define_table=('images',Field('picture', 'upload' )) The controller: def somefunction(): to get the image. How exactly should I "read" a picture from the database? The view: <img src="{{somefunction}}" /> 回答1: As is, your model will not store the image in the database -- instead, it will store the image on the filesystem, with its new filename stored in the database (in the 'picture' field). If you want to

问题 At moment I want to implement picture upload without using any plug-ins. My upload form looks like this <form action="/Member/UploadPicture" enctype="multipart/form-data" id="uploadform" method="post"> <span> <div class="upload" id="imgUpl"> <h3>Upload profile picture</h3> <div class="clear5"></div> <input type="file" name="file" id="file" /> <button class="btn-bl" id="upComplete"><span>Upload</span></button> </div> </span> </form> And my jQuery code is: $('#upComplete').click(function () { $