unique

问题 Service.startForeground() vs NotificationManager.notify(), give different behaviors. When using notify with two different notification ids, 2 notifications are created - Good . When doing the same with startForground , one notification overrides the other - Bad . Tested device: Nexus S(2.3.6) and Asus Transformer (4.0.3). Any ideas how I can run an Important (foreground) service that can have several (dynamic number) notifications? 回答1: Well, it's not the best solution, but you can always

问题 My dataframe looks like this: ID | value 1 | value 2 | value 3 | value 4 1 | M | D | F | A 2 | F | M | G | B 3 | M | D | F | A 4 | L | D | E | B I want to get something like this. value 1 | value 2 | value 3 | value 4| Number of combinations M | D | F | A | 2 F | M | G | B | 1 L | D | E | B | 1 e.g. to count the number of unique combinations of the columns value 1 - value 4. 回答1: count in plyr package will do that task. > df ID value.1 value.2 value.3 value.4 1 1 M D F A 2 2 F M G B 3 3 M D F

问题 I am trying to create a unique CD-KEY to put in our product's box, just like a normal CD-KEY found in standard software boxes that users use to register the product. However we are not selling software, we are selling DNA collection kit for criminal and medical purposes. Users will receive a saliva collection kit by mail with the CD-KEY on it and they will use that CD-KEY to create an account on our website and get their results. The results from the test will be linked to the CD-KEY. This is

问题 I have a string with repeated letters. I want letters that are repeated more than once to show only once. For instance I have a string aaabbbccc i want the result to be abc. so far my function works like this: if the letter doesn't repeat, it's not shown if it's repeated once, it's show only once (i.e. aa shows a) if it's repeated twice, shows all (i.e. aaa shows aaa) if it's repeated 3 times, it shows 6 (if aaaa it shows aaaaaa) function unique_char(string) { var unique = ''; var count = 0;

问题 I am in search of a data structure which enables me to quickly (prefarably O(1)-quickly) determine if a given GUID is a member of a Collection of GUIDs or not. My current approach is to use a TDictionary with 0 as values. While this works quickly, it seems to be a waste to use a Hashmap to rehash a GUID, which is by defintion considered to be unique, and to have the Dictionary handle values which are unneeded. There must be a better solution for this, but I can't find one. Can you? 回答1: I

问题 I would like to use a unique id for android device that works for phone and Tablet. (IMEI doesn't work with no SIM card device and sometime MAC Address return null) I'm not sure is android.os.Build.SERIAL unique or not. Does anyone know about this? Thanks, Regards. 回答1: Yes, but note that it was only added in API level 9, and it may not be present on all devices. To get a unique ID on earlier platforms, you'll need to read something like the MAC address or IMEI. Generally, try reading all the

问题 I defined some WTForms forms in an application that uses SQLALchemy to manage database operations. For example, a form for managing Categories: class CategoryForm(Form): name = TextField(u'name', [validators.Required()]) And here's the corresponding SQLAlchemy model: class Category(Base): __tablename__= 'category' id = Column(Integer, primary_key=True) name = Column(Unicode(255)) def __repr__(self): return '<Category %i>'% self.id def __unicode__(self): return self.name I would like to add a

问题 Suppose you have a list of values x <- list(a=c(1,2,3), b = c(2,3,4), c=c(4,5,6)) I would like to find unique values from all list elements combined. So far, the following code did the trick unique(unlist(x)) Does anyone know a more efficient way? I have a hefty list with a lot of values and would appreciate any speed-up. 回答1: This solution suggested by Marek is the best answer to the original Q. See below for a discussion of other approaches and why Marek's is the most useful. > unique

问题 How can I find the unique lines and remove all duplicates from a file? My input file is 1 1 2 3 5 5 7 7 I would like the result to be: 2 3 sort file | uniq will not do the job. Will show all values 1 time 回答1: uniq has the option you need: -u, --unique only print unique lines $ cat file.txt 1 1 2 3 5 5 7 7 $ uniq -u file.txt 2 3 回答2: Use as follows: sort < filea | uniq > fileb 回答3: uniq -u has been driving me crazy because it did not work. So instead of that, if you have python (most Linux

问题 I'm wondering what is the best way to display unique records from a has_many, through relationship in Rails3. I have three models: class User < ActiveRecord::Base has_many :orders has_many :products, :through => :orders end class Products < ActiveRecord::Base has_many :orders has_many :users, :through => :orders end class Order < ActiveRecord::Base belongs_to :user, :counter_cache => true belongs_to :product, :counter_cache => true end Lets say I want to list all the products a customer has