tuples

问题 I have a config file like this. [rects] rect1=(2,2,10,10) rect2=(12,8,2,10) I need to loop through the values and convert them to tuples. I then need to make a tuple of the tuples like ((2,2,10,10), (12,8,2,10)) 回答1: To turn the strings into tuples of ints (which is, I assume, what you want), you can use a regex like this: x = "(1,2,3)" t = tuple(int(v) for v in re.findall("[0-9]+", x)) And you can use, say, configparser to parse the config file. 回答2: Instead of using a regex or int/string

问题 I'm implementing a multi-index map in C++11, which I want to be optimized for specific features. The problem I'm currently trying to solve, is to not store key elements more then once. But let me explain. The problem arose from sorting histograms to overlay them in different combinations. The histograms had names, which could be split into tokens (properties). Here are the features I want my property map to have: Be able to loop over properties in any order; Be able to return container with

问题 I have DataFrame with 66 columns to process (almost each column value needs to be changed someway) so I'm running following statement val result = data.map(row=> ( modify(row.getString(row.fieldIndex("XX"))), (...) ) ) till 66th column. Since scala in this version has limit to max tuple of 22 pairs I cannot perform this like that. Question is, is there any workaround for it? After all line operations I'm converting it to df with specific column names result.toDf("c1",...,"c66") result

问题 I am still learning Python and currently solving a question on Hackerrank where I am thinking of converting input(String type) to tuple by using built-in function(tuple(input.split(" ")). For example, myinput = "2 3", and I want to convert it to tuple,such as (2,3). However,if I do that, it will, of course, give me a tuple with String type, like ('2', '3'). I know that there are a lot of ways to solve the problem, but I'd like to know how to convert elements(str) in tuple to integer(in Python

问题 Named tuples are easy to create, lightweight object types. namedtuple instances can be referenced using object-like variable deferencing or the standard tuple syntax. If these data structures can be accessed both by object deferencing & indexes, how are they implemented internally? Is it via hash tables? 回答1: Actually, it's very easy to find out how a given namedtuple is implemented: if you pass the keyword argument verbose=True when creating it, its class definition is printed: >>> Point =

问题 Using Python 2.4, how do I print a list in a nice tabular format? My list is in the below format. mylist=[(('VAL1', 'VAL2', 'VAL3', 'VAL4', 'VAL5', 'VAL6'), AGGREGATE_VALUE)] I have tried pprint , but it does not print the result in a tabular format. EDIT : I would like to see the output in the below format: VAL1 VAL2 VAL3 VAL4 VAL5 VAL6 AGGREGATE_VALUE This table, should account for variable item lengths and still print with proper indentation. 回答1: mylist = [ ( ('12', '47', '4', '574862',

问题 In this example, is it possible to allow the deduction of the template parameters type of the tuple ? #include<tuple> #include<string> template<class T1, class T2> void fun(std::tuple<T1, T2> t, std::string other){} int main(){ fun(std::tuple<double, int>(2.,3), std::string("other")); // ok fun(std::make_tuple(2.,3), std::string("other")); // ok, but trying to avoid `make_tuple` fun({2.,3},std::string("other")); // desired syntax but // giving compilation error: candidate template ignored:

问题 Is it possible to enforce the size of a Vector passed in to a method at compile time? I want to model an n-dimensional Euclidean space using a collection of points in the space that looks something like this (this is what I have now): case class EuclideanPoint(coordinates: Vector[Double]) { def distanceTo(desination: EuclieanPoint): Double = ??? } If I have a coordinate that is created via EuclideanPoint(Vector(1, 0, 0)) , it is a 3D Euclidean point. Given that, I want to make sure the

问题 Is it possible to enforce the size of a Vector passed in to a method at compile time? I want to model an n-dimensional Euclidean space using a collection of points in the space that looks something like this (this is what I have now): case class EuclideanPoint(coordinates: Vector[Double]) { def distanceTo(desination: EuclieanPoint): Double = ??? } If I have a coordinate that is created via EuclideanPoint(Vector(1, 0, 0)) , it is a 3D Euclidean point. Given that, I want to make sure the

问题 What I am actually doing is more complex but it comes down to being able to implement function to detect that something is a tuple, regardless of what the are the types of its elements. This is my approch that does not work (see comment on last line) : func isTuple(b: Any) -> Bool { return b is (Any, Any) } let myString = "aa" let myDouble = 1.2 isTuple((myString, myDouble)) //returns false Why doesn't it work? Shouln't Any act as a "wildcard" in tuples as well? Is it a known Swift bug (if