tuples

Haskell: create a tuple of lists from an input list

微笑、不失礼 提交于 2021-01-05 04:13:29
问题 I am trying to set up some functions to help with a current project I am working on. I am new to Haskell and struggling to implement my desired functions. I have a list [a] and would like it to output a tuple of four different lists ([b],[b],[b],[b]) where each item in list [a] is successively placed in to the next list in the output tuple. So the first element in the input list [a] goes to the first list [b] , the second element in [a] goes to the second list [b] , the third element in [a]

How to merge two tuples in a list if the first tuple elements match?

一世执手 提交于 2020-12-30 04:14:01
问题 I've got two lists of tuples of the form: playerinfo = [(ansonca01,4,1871,1,RC1),(forceda01,44,1871,1,WS3),(mathebo01,68,1871,1,FW1)] idmatch = [(ansonca01,Anson,Cap,05/06/1871),(aaroh101,Aaron,Hank,04/13/1954),(aarot101,Aaron,Tommie,04/10/1962)] What I would like to know, is how could I iterate through both lists, and if the first element in a tuple from "playerinfo" matches the first element in a tuple from "idmatch", merge the matching tuples together to yield a new list of tuples? In the

How to merge two tuples in a list if the first tuple elements match?

我的梦境 提交于 2020-12-30 04:13:36
问题 I've got two lists of tuples of the form: playerinfo = [(ansonca01,4,1871,1,RC1),(forceda01,44,1871,1,WS3),(mathebo01,68,1871,1,FW1)] idmatch = [(ansonca01,Anson,Cap,05/06/1871),(aaroh101,Aaron,Hank,04/13/1954),(aarot101,Aaron,Tommie,04/10/1962)] What I would like to know, is how could I iterate through both lists, and if the first element in a tuple from "playerinfo" matches the first element in a tuple from "idmatch", merge the matching tuples together to yield a new list of tuples? In the

Dictionary of (named) tuples in Python and speed/RAM performance

强颜欢笑 提交于 2020-12-30 03:14:20
问题 I'm creating a dictionary d of one million of items which are tuples, and ideally I'd like to access them with: d[1634].id # or d[1634]['id'] d[1634].name # or d[1634]['name'] d[1634].isvalid # or d[1634]['isvalid'] rather than d[1634][0] , d[1634][1] , d[1634][2] which is less explicit. According to my test: import os, psutil, time, collections, typing Tri = collections.namedtuple('Tri', 'id,name,isvalid') Tri2 = typing.NamedTuple("Tri2", [('id', int), ('name', str), ('isvalid', bool)]) t0 =

Dictionary of (named) tuples in Python and speed/RAM performance

ⅰ亾dé卋堺 提交于 2020-12-30 03:10:46
问题 I'm creating a dictionary d of one million of items which are tuples, and ideally I'd like to access them with: d[1634].id # or d[1634]['id'] d[1634].name # or d[1634]['name'] d[1634].isvalid # or d[1634]['isvalid'] rather than d[1634][0] , d[1634][1] , d[1634][2] which is less explicit. According to my test: import os, psutil, time, collections, typing Tri = collections.namedtuple('Tri', 'id,name,isvalid') Tri2 = typing.NamedTuple("Tri2", [('id', int), ('name', str), ('isvalid', bool)]) t0 =

Scala 3 - Extract Tuple of wrappers and InverseMap on First Order Type

点点圈 提交于 2020-12-29 07:59:59
问题 I am trying to create a function, which takes a tuple of higher-kinded types and applies a function to the types within the higher-kinded types. In the example below, there is a trait Get[A] which is our higher-kinded type. There is also a tuple of Get's: (Get[String],Get[Int]) as well as function from (String,Int) => Person . Scala-3 has a Match-Type called InverseMap which converts the type (Get[String], Get[Int]) into what is essentially the type (String,Int). So the ultimate goal is to

Make names of named tuples appear in serialized JSON responses

好久不见. 提交于 2020-12-28 13:20:41
问题 Situation : I have multiple Web service API calls that deliver object structures. Currently, I declare explicit types to bind those object structures together. For the sake of simplicity, here's an example: [HttpGet] [ProducesResponseType(typeof(MyType), 200)] public MyType TestOriginal() { return new MyType { Speed: 5.0, Distance: 4 }; } Improvement : I have loads of these custom classes like MyType and would love to use a generic container instead. I came across named tuples and can

Make names of named tuples appear in serialized JSON responses

倖福魔咒の 提交于 2020-12-28 13:13:31
问题 Situation : I have multiple Web service API calls that deliver object structures. Currently, I declare explicit types to bind those object structures together. For the sake of simplicity, here's an example: [HttpGet] [ProducesResponseType(typeof(MyType), 200)] public MyType TestOriginal() { return new MyType { Speed: 5.0, Distance: 4 }; } Improvement : I have loads of these custom classes like MyType and would love to use a generic container instead. I came across named tuples and can

Make names of named tuples appear in serialized JSON responses

早过忘川 提交于 2020-12-28 13:13:15
问题 Situation : I have multiple Web service API calls that deliver object structures. Currently, I declare explicit types to bind those object structures together. For the sake of simplicity, here's an example: [HttpGet] [ProducesResponseType(typeof(MyType), 200)] public MyType TestOriginal() { return new MyType { Speed: 5.0, Distance: 4 }; } Improvement : I have loads of these custom classes like MyType and would love to use a generic container instead. I came across named tuples and can

C++ Transform a std::tuple<A, A, A…> to a std::vector or std::deque

风流意气都作罢 提交于 2020-12-28 07:51:23
问题 In the simple parser library I am writing, the results of multiple parsers is combined using std::tuple_cat . But when applying a parser that returns the same result multiple times, it becomes important to transform this tuple into a container like a vector or a deque. How can this be done? How can any tuple of the kind std::tuple<A> , std::tuple<A, A> , std::tuple<A, A, A> etc be converted into a std::vector<A> ? I think this might be possible using typename ...As and sizeof ...(As) , but I