tuples

问题 I'm trying to write a haskell function that takes in two lists of integers and generates a list with elements that have been taken alternatingly from the two lists. I have the function: blend xs ys An example: blend [1,2,3] [4,5,6] should return [1,4,2,5,3,6] My logic is to zip the two lists together, generating the pairs of alternate elements, then somehow remove them from their tuples. It's removing them from their tuples that I can't figure out how to implement. 回答1: How about exchanging

问题 In Rust, is there any way to use trait s and impl s to (recursively) flatten tuples? If it helps, something that works with N nested pairs is a good start trait FlattenTuple { fn into_flattened(self) -> /* ??? */ } // such that assert_eq!((1, (2, 3)).into_flattened(), (1, 2, 3)) It would be even better if it could be extended work with any kind of nested tuple such that: assert_eq!(((1, 2), 2, (3, (4, 5))).into_flattened(), (1, 2, 2, 3, 4, 5)) 回答1: Maybe for certain small definitions of

问题 In Rust, is there any way to use trait s and impl s to (recursively) flatten tuples? If it helps, something that works with N nested pairs is a good start trait FlattenTuple { fn into_flattened(self) -> /* ??? */ } // such that assert_eq!((1, (2, 3)).into_flattened(), (1, 2, 3)) It would be even better if it could be extended work with any kind of nested tuple such that: assert_eq!(((1, 2), 2, (3, (4, 5))).into_flattened(), (1, 2, 2, 3, 4, 5)) 回答1: Maybe for certain small definitions of

问题 I have a list of strings in this format: ['5,6,7', '8,9,10'] I would like to convert this into the format: [(5,6,7), (8,9,10)] So far I have tried this: [tuple(i.split(',')) for i in k] And I obtain: [('5','6','7'), ('8','9','10')] I am a bit stuck on how to simply convert the strings into tuples of integers. Thank you 回答1: If your strings are strings representation of number, then: [tuple(int(s) for s in i.split(',')) for i in k] 回答2: The following solution is for me the most readable,

问题 I have a list of strings in this format: ['5,6,7', '8,9,10'] I would like to convert this into the format: [(5,6,7), (8,9,10)] So far I have tried this: [tuple(i.split(',')) for i in k] And I obtain: [('5','6','7'), ('8','9','10')] I am a bit stuck on how to simply convert the strings into tuples of integers. Thank you 回答1: If your strings are strings representation of number, then: [tuple(int(s) for s in i.split(',')) for i in k] 回答2: The following solution is for me the most readable,

问题 Variadic Zip Function Swift 4.1, Xcode 9.4 I have been using Apple's native zip(_:_:) recently and I ran into a situation whereby I needed to zip more than two sequences. So I looked for and found the declaration of zip(_:_:) on Swift's GitHub page. I took that information and was able to overload zip(_:_:) to accept four parameters, zip(_:_:_:_:) . I am aware that I can painstakingly overload zip to support whatever number of arguments I chose one at a time, but this is inflexible, time

问题 I have a list of lists of tuples, where every tuple is of equal length, and I need to convert the tuples to a Pandas dataframe in such a way that the columns of the dataframe are equal to the length of the tuples, and each tuple item is a row entry across the columns. I have consulted other questions on this topic (e.g., Convert a list of lists of tuples to pandas dataframe, List of list of tuples to pandas dataframe, split list of tuples in lists of list of tuples) unsuccessfully. The

问题 I have a list of lists of tuples, where every tuple is of equal length, and I need to convert the tuples to a Pandas dataframe in such a way that the columns of the dataframe are equal to the length of the tuples, and each tuple item is a row entry across the columns. I have consulted other questions on this topic (e.g., Convert a list of lists of tuples to pandas dataframe, List of list of tuples to pandas dataframe, split list of tuples in lists of list of tuples) unsuccessfully. The

问题 I am trying to set up some functions to help with a current project I am working on. I am new to Haskell and struggling to implement my desired functions. I have a list [a] and would like it to output a tuple of four different lists ([b],[b],[b],[b]) where each item in list [a] is successively placed in to the next list in the output tuple. So the first element in the input list [a] goes to the first list [b] , the second element in [a] goes to the second list [b] , the third element in [a]

问题 I am trying to set up some functions to help with a current project I am working on. I am new to Haskell and struggling to implement my desired functions. I have a list [a] and would like it to output a tuple of four different lists ([b],[b],[b],[b]) where each item in list [a] is successively placed in to the next list in the output tuple. So the first element in the input list [a] goes to the first list [b] , the second element in [a] goes to the second list [b] , the third element in [a]