touch-event

问题 Layout !* Container is a relative layout contains two custom views: OuterView1 and InnerView2 * Outer View1 is a custom view, matching the parent’s size (full screen) * Inner View2 is also a custom view, laid on top of OuterView1 overlapping it. Container is a relative layout contains two custom views: OuterView1 and InnerView2 Outer View1 is a custom view, matching the parent’s size (full screen) Inner View2 is also a custom view, laid on top of OuterView1 overlapping it. On both OuterView1

问题 In the Apple documentation here Advanced Scene Processing it describes the update method and how a scene is rendered, but it does not mention when input is processed. It is not clear if this is in in the same thread as the rendering loop, or whether it is concurrent with it. If I have an object that I update from both the SKScene update method and the touchesBegan method (in this case of a SKSpriteNode ) do I have to worry about synchronising the two accesses to my object? 回答1: So after a few

问题 I add a UITapGestureRecognizer:tapGesture , I want that when I click(touch) the label, klikPlay() will run its actions. when I run the code and click/touch the label, it gives this error: unrecognized selector sent to instance. It is about the label Player(named: label) , the UITapGestureRecognizer(named:tapGesture) and the function klikPlay What am I doing wrong? override func didMoveToView(view: SKView) { let background = SKSpriteNode(imageNamed: "bgStart2") background.position = CGPoint(x

问题 I'm using the following Javascript to create ontouchstart/move/end callbacks on div elements for an iOS web app. The only problem at the moment is that when you try to scroll up and down the page, it triggers the ontouchstart element and changes the CSS of the div. I want the CSS of the div to change only when a user selects the item. I'm fairly basic with Javascript but if anyone knows any way of getting the Javascript to only trigger when a user is selecting an item it would be greatly

问题 I am working with small application for display bubbles images on android screen.I have displayed all bubbles images from resource directory.I have implemented code as follows in view class. onDraw method: @Override protected void onDraw(Canvas canvas) { super.dispatchDraw(canvas); drawImages(canvas); } I have implemented drawImages() method as follows: BitmapFactory.Options opts = new BitmapFactory.Options(); private void drawImages(Canvas canvas) { for(int i = 0; i<MAX_ROWS; i++){ for(int j

问题 What is the difference between a view's onTouchEvent : public class MyCustomView extends View { // THIS : @Override public boolean onTouchEvent(MotionEvent event) { return super.onTouchEvent(event); } } and its onTouchListener : MyCustomView myView = (MyCustomView) findViewById(R.id.customview); myView.setOnTouchListener(new View.OnTouchListener() { @Override public void onClick(View arg0) { // do something } }); or public class MyCustomView extends View { public MyCustomView(Context context,

问题 I've searched all across the web to find a simple way of adding touch gestures to a simple button. Basically I'm trying to find a simple way of getting the back button (which you usually see on the task-bar at the top of an iOS device) to change CSS classes from 'normal' state to 'pressed' state when pressed. Although I'm very new to Javascript, I would prefer to use standard DOM methods rather than jQuery (or any other library). Would anyone have some complete code and explain how the

问题 I am developing Android library which needs to track all touch events on app that uses it. For now Users should override theirs Activity’s dispatchTouchEvent() on their’s every activity. as shown below @Override public boolean dispatchTouchEvent(MotionEvent event) { MyLib.dispatchTouchEvent(event); return super.dispatchTouchEvent(event); } But Appsee detects touch events with Appsee.start(“key”); on onCreate method integrated in First activity where app starts. How is this possible. Any help?

问题 As the touchend event is bind to the element where the touchstart is fired, how can I get the element at the position where the finger leaves, when this is outside of the element where the event was binded to. 回答1: You could use the document.elementFromPoint method, passing it the coordinates of the event: $('#element').on("touchend",function(event){ var endTarget = document.elementFromPoint( event.originalEvent.touches[0].pageX, event.originalEvent.touches[0].pageY ); }); EDIT: Found some

问题 I'm developing a jquery component which works primarily for ipad. So is there anyway to simulate 'touchstart and 'touchend' events in desktop rather than having the device itself to check the events. 回答1: You can author your own custom events within jQuery: var event = $.Event( "touchstart", { pageX:200, pageY:200 } ); And you can issue them against any element in the DOM: $("body").trigger( event ); Demo: http://jsbin.com/ezoxed/edit#javascript,html Further reading: http://api.jquery.com