time

Display a time clock in the R command line

不想你离开。 提交于 2020-01-08 13:54:20
问题 I wonder if there is a way to display the current time in the R command line, like in MS DOS, we can use Prompt $T $P$G to include the time clock in every prompt line. Something like options(prompt=paste(format(Sys.time(), "%H:%M:%S"),"> ")) will do it, but then it is fixed at the time it was set. I'm not sure how to make it update automatically. 回答1: Chase points the right way as options("prompt"=...) can be used for this. But his solutions adds a constant time expression which is not what

Estimating when it's done in excel

烈酒焚心 提交于 2020-01-07 08:31:32
问题 Can I, somehow, based on time stamp and how much is done, estimate time and date for when a job is complete? I got this log that a bot I've made writes in column A time [yyy-mm-dd hh:mm], and in column B it wrights how much is done. It sorts it all with newest on top. 回答1: Gary's answer is correct, but for convenience if the 2nd row of data can be an arbitrary progress status (not just start of task = implicitly 0%), and if you use percentage number format (or decimals) and you would like to

【转】linux下杀死进程(kill)的N种方法

假如想象 提交于 2020-01-07 05:39:36
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 【转】linux下杀死进程(kill)的N种方法 转载一篇,最原始的出处已不可考,望见谅! 常规篇:  首先,用ps查看进程,方法如下: $ ps -ef …… smx 1822 1 0 11:38 ? 00:00:49 gnome-terminal smx 1823 1822 0 11:38 ? 00:00:00 gnome-pty-helper smx 1824 1822 0 11:38 pts/0 00:00:02 bash smx 1827 1 4 11:38 ? 00:26:28 /usr/lib/firefox-3.6.18/firefox-bin smx 1857 1822 0 11:38 pts/1 00:00:00 bash smx 1880 1619 0 11:38 ? 00:00:00 update-notifier …… smx 11946 1824 0 21:41 pts/0 00:00:00 ps -ef 或者: $ ps -aux …… smx 1822 0.1 0.8 58484 18152 ? Sl 11:38 0:49 gnome-terminal smx 1823 0.0 0.0 1988 712 ? S 11:38 0:00 gnome-pty-helper smx

Adding Time in HH:MM Format -SQL Query

我们两清 提交于 2020-01-07 04:39:04
问题 Sir/Mam, I am using Oracle 11g.I have the following table by the name "Timeduration". It contains time specified in hours and minutes.I want to get the total time in hour and minutes. Timeduration 05:37 06:40 03:45 02:50 07:58 I want the total time as 25:30. How can i write the code for this?? Please help me out." 回答1: with t as ( select '05:37' as timeduration from dual union all select '06:40' as timeduration from dual union all select '03:45' as timeduration from dual union all select '02

Difference between two dates, in days, varies

和自甴很熟 提交于 2020-01-07 04:26:05
问题 Date d = new Date(today.getTimeInMillis()); Date d1 = new Date(dueDate.getTimeInMillis()); int daysUntil = (int) ((d1.getTime() - d.getTime())/ (1000 * 60 * 60 * 24)); Using the above code, where today is a calendar set to 00:00 on the current day, and dueDate is set to 00:00 on the date I am comparing today to, my results from this differ. There is something in this which varies, making my output either x or x+1 where x is the correct answer. What is the issue here, and what can I do to make

Strange date picker behaviour Xcode, swift 3

隐身守侯 提交于 2020-01-07 03:52:19
问题 My current project is a timer which uses a date picker to set the amount of time the user wants before the timer goes off (say 1 minute, 6 hours and two minutes etc.). The problem lies in the amount of time that the date picker believes it has been set for. Below is the code which I am using to set the time. @IBOutlet weak var datePicker: UIDatePicker! var timeAmount:Double = 0 @IBAction func startButton() { timeAmount = Double(datePicker.countDownDuration) let trigger =

Get the next time that respect a time format and not a pervious one

断了今生、忘了曾经 提交于 2020-01-07 03:42:49
问题 I am trying to get the time to the next "6:00:00", I am using moment: let shiftEnd = moment("06:00:00", "HH:mm:ss") console.log(shiftEnd.inspect()) It gets me the previous 6:00:00, the one with the same day as now() . moment("2017-07-31T06:00:00.000") now() is: moment("2017-07-31T12:20:57.076") What's the best way to get the next 6am that's not passed yet? 回答1: You are getting a moment object for the current day because, as moment Default section states: You can create a moment object

time difference is zero sec

岁酱吖の 提交于 2020-01-07 03:15:35
问题 Here i am trying to count to calculate time required to complete merge sort.But the difference between start and end is showing zero secend.I don't know what is the problem.For convenience i am posting only the main function where time is calculated. #include<stdio.h> #include<time.h> int main(){ clock_t start,end,diff; start=clock(); int arr[4]={12,2,56,1}; int i; printf("beforn sort\n"); printf("\n-------------\n"); for(i=0;i<4;i++){ printf("%d ",arr[i]); } printf("\n \n"); Merge_sort(arr,0

Zend Date DST Bug: Test whether a date is a “time change” date

房东的猫 提交于 2020-01-07 02:27:07
问题 I found a workaround for Zend Date's DST Bug, but the workaround introduces another bug. The workaround simply sets the time twice. This introduces another bug, if the resulting date crosses the date boundary, the the day get incremented or decremented. I am wondering if there's a way to determine that the date at hand is a "time change" date, so that I can come up with a solid workaround to the Zend Date DST bug. 回答1: It turns out that PHP's function localtime() returns whether or not the

Excel: track number of employees at a given moment

╄→гoц情女王★ 提交于 2020-01-07 00:47:50
问题 I am trying to come up with an Excel sheet where I have a set of 30-minute intervals throughout the day (starting at 10:00 and ending at 20:00) and I would like to calculate how many employees are available during each of them. The data I have is their shift start/end and the start-end times of their lunch breaks (normally 1 hour, but for part-timers these last 30 minutes). Here's a sample file: http://www.mediafire.com/download/op3rarsiqj1sm77/time-tracker.xlsx Do you have any suggestions?