time

问题 In the example bellow the result is always "[date] 05:00:00 +0000 UTC" regardless the timezone you choose for the parseAndPrint function. What is wrong with this code? The time should change depending on the timezone you choose. (Go Playground servers are apparently configured in UTC timezone). http://play.golang.org/p/wP207BWYEd package main import ( "fmt" "time" ) func main() { now := time.Now() parseAndPrint(now, "BRT") parseAndPrint(now, "EDT") parseAndPrint(now, "UTC") } func

问题 This is the "algorithm", but when I want to measure the execution time it gives me zero. Why? #define ARRAY_SIZE 10000 ... clock_t start, end; start = clock(); for( i = 0; i < ARRAY_SIZE; i++) { non_parallel[i] = vec[i] * vec[i]; } end = clock(); printf( "Number of seconds: %f\n", (end-start)/(double)CLOCKS_PER_SEC ); So What should i do to measure the time? 回答1: Two things: 10000 is not a lot on a modern computer. Therefore that loop will run in probably less than a millisecond - less than

问题 I was hoping someone could send me in the direction of a regularily updating time zone database. I have found one, but apologies i cant remember where it was from, however with the current GMT clock change fast approaching, i fear all my data will be incorrect, ie the differences from UK to New Yrok will change from 5 hours behind to 6 hours behind. Any help on this matter would be much appreciated. Cameron 回答1: Do you mean like the Olson database ? For instance, the fleegix.js javascript

问题 I have two times - For eg- the current time - 08:24 and date is 02/01/2013 in dd/mm/yyyy format and I have another time at 13:46 and date is 31/12/2012 . So, how can I calculate the difference between the 2 times in hours using PHP. (i.e. 42.63 hours) Thanks in advance. 回答1: Convert them both to timestamp values, and then subtract to get the difference in seconds. $ts1 = strtotime(str_replace('/', '-', '02/01/2013 08:24')); $ts2 = strtotime(str_replace('/', '-', '31/12/2012 13:46')); $diff =

问题 In MS Reporting Services 2008, I have a field that is a duration stored as seconds. Is there a slick way to get it into hh:mm:ss format in a group section of the report? 回答1: If you just want to display it, convert in an expression for the Value of the textbox: =Format(DateAdd("s", Fields!MySecondsField.Value, "00:00:00"), "HH:mm:ss") If you want to do calculations on it, convert the seconds to a DateTime in your dataset. Using SQL: SELECT DATEADD(ss, MySecondsField, '1900-01-01') AS

问题 I want to store the current date generated from PHP into MongoDB collection as an ISO date formate. ISODate("2012-11-02T08:40:12.569Z") However I am not able to generate such Kind of date in php which will be stored in MongoDB as an ISODate format. This is what I ve done. $d = new MongoDate(time()); echo $d; and it is outputting something like, 0.00000000 1353305590 which is not the format I need. How to do this? 回答1: You could run the __toString function, or use the sec field __toString will

问题 I want to store the current date generated from PHP into MongoDB collection as an ISO date formate. ISODate("2012-11-02T08:40:12.569Z") However I am not able to generate such Kind of date in php which will be stored in MongoDB as an ISODate format. This is what I ve done. $d = new MongoDate(time()); echo $d; and it is outputting something like, 0.00000000 1353305590 which is not the format I need. How to do this? 回答1: You could run the __toString function, or use the sec field __toString will

问题 I'm working on a simple program to tell an individual how long they have been alive. I know how to get the current date, and get their birthday. The only problem is I have no way of subtracting the two, I know a way of subtracting two dates, but unfortunately it does not include hours, minutes, or seconds. I am looking for a method that can subtract two dates and return the difference down to the second, not merely the day. 回答1: from datetime import datetime birthday = datetime(1988, 2, 19,

问题 I'm working on a simple program to tell an individual how long they have been alive. I know how to get the current date, and get their birthday. The only problem is I have no way of subtracting the two, I know a way of subtracting two dates, but unfortunately it does not include hours, minutes, or seconds. I am looking for a method that can subtract two dates and return the difference down to the second, not merely the day. 回答1: from datetime import datetime birthday = datetime(1988, 2, 19,

问题 I'm working on a simple program to tell an individual how long they have been alive. I know how to get the current date, and get their birthday. The only problem is I have no way of subtracting the two, I know a way of subtracting two dates, but unfortunately it does not include hours, minutes, or seconds. I am looking for a method that can subtract two dates and return the difference down to the second, not merely the day. 回答1: from datetime import datetime birthday = datetime(1988, 2, 19,