syntax-error

JavaScript: {}==false is a SyntaxError?

蹲街弑〆低调 提交于 2019-11-28 06:56:06
In Firefox 3.5, I type this in the Firebug console : false=={} // => evals to false {}==false // syntax error What is the explanation for this ? bobince { at the start of a statement signals a ‘statement block’ (see ECMA-262-3 section 12.1), which contains a list of statements. } immediately ends the statement block with no statements in it. That's fine. But now the parser is looking for the next statement: ==false Huh? That's not a statement; syntax error. What are statement blocks for? Well, you are writing a statement block every time you say: if (something) { ... } JavaScript defines these

SyntaxError: Generator expression must be parenthezised / python manage.py migrate

我怕爱的太早我们不能终老 提交于 2019-11-28 06:44:34
I'm really new in programming and I wanted to follow the Djangogirls tutorial, but I'm stucked now. In the tutorial, I am here : To create a database for our blog, let's run the following in the console: python manage.py migrate (we need to be in the djangogirls directory that contains the manage.py file). If that goes well, you should see something like this: ... There is no option to fail in the tutorial but I have an error message: (myvenv) C:\Users\Julcsi\djangogirls> python manage.py migrate Traceback (most recent call last): File "manage.py", line 22, in <module> execute_from_command

Oracle PL/SQL select into variables

回眸只為那壹抹淺笑 提交于 2019-11-28 05:35:09
问题 I am trying to run the following query in SQL Developer, but I am receiving an error. I am trying to declare two local variables (var_num1 and payDate) and then set the variables. Does anyone know what I can be doing incorrectly? I know Oracle SQL is a little different than SQL Server. DECLARE var_num1 number; payDate date; BEGIN var_num1 := 100; payDate := '10/1/2013' BEGIN SELECT * FROM Paycode WHERE PaycodeID = var_num1 and PaycodeDate = payDate; End; END; Error report: ORA-06550: line 6,

'Syntax Error: invalid syntax' for no apparent reason

守給你的承諾、 提交于 2019-11-28 05:23:36
I've been trying to get a fix and can't find why the error keeps appearing. Pmin,Pmax,w,fi1 and fi2 have all been assigned finite values guess=Pmin+(Pmax-Pmin)*((1-w**2)*fi1+(w**2)*fi2) When i remove this line from the code, the same error appears at the next line of code, again for no reason I can think of Edit: Here is the chunk of code I was referring to: def Psat(self, T): pop= self.getPborder(T) boolean=int(pop[0]) P1=pop[1] P2=pop[2] if boolean: Pmin = float(min([P1, P2])) Pmax = float(max([P1, P2])) Tr=T/self.typeMolecule.Tc w=0.5*(1+scipy.tanh((10**5)*(Tr-0.6))) fi1=0.5*(1-scipy.tanh(8

How do I fix this missing semicolon syntax error in Javascript?

放肆的年华 提交于 2019-11-28 04:50:49
A friend wrote some code for me, and there was one file with a weird syntax error in it. After a bit of hunting, I narrowed it down to this section of code, which should reproduce the error: var say = functіon(message) { alert(message); return message; }; say(say("Goodbye!")); When I run this, I see an error in the Internet Explorer console that says SCRIPT1004: Expected ';' . I don't see a semicolon missing anywhere, and I can't imagine where it wants me to put one. Where does it expect a semicolon and why does it expect a semicolon there? Your issue is the fact that the i in function is the

syntax error near unexpected token `$'in\\r''

瘦欲@ 提交于 2019-11-28 04:40:15
I'm trying to compile the NIST Biometric Image Software, and I have been having trouble all day. I finally got the source checked out right, and I installed cygwin with no problems (I have used it in the past), but when I went to compile, I get this error: $ sh setup.sh </cygdrive/c/NBIS> [--without-X11] setup.sh: line 94: syntax error near unexpected token `$'in\r'' 'etup.sh: line 94: ` case $1 in Now I'm sure any advanced coder would head to the setup.sh and look for problems, but I'm not really much of a coder (I'm only compiling this because there are no pre-compiled packages) so I don't

LibCurl CURLOPT_URL not accepting string? C++

时间秒杀一切 提交于 2019-11-28 04:34:06
问题 So basically what I want to do is use libcurl to fetch slightly different urls, e.g.: http://foo.com/foo.asp?name=*NAMEHERE* What I would like to do is iterate through a vector of names and get each one, e.g.: http://foo.com/foo.asp?name=James Then http://foo.com/foo.asp?name=Andrew And so on. However, when I try doing this: int foo (){ CURL *curl; CURLcode success; char errbuf[CURL_ERROR_SIZE]; int m_timeout = 15; if ((curl = curl_easy_init()) == NULL) { perror("curl_easy_init"); return 1; }

PHP Notice: Undefined offset: 1 with array when reading data

こ雲淡風輕ζ 提交于 2019-11-28 04:17:24
I am getting this PHP error: PHP Notice: Undefined offset: 1 Here is the PHP code that throws it: $file_handle = fopen($path."/Summary/data.txt","r"); //open text file $data = array(); // create new array map while (!feof($file_handle) ) { $line_of_text = fgets($file_handle); // read in each line $parts = array_map('trim', explode(':', $line_of_text, 2)); // separates line_of_text by ':' trim strings for extra space $data[$parts[0]] = $parts[1]; // map the resulting parts into array //$results('NAME_BEFORE_:') = VALUE_AFTER_: } What does this error mean? What causes this error? GGio Change

Long Int literal - Invalid Syntax?

和自甴很熟 提交于 2019-11-28 03:36:32
问题 The Python tutorial book I'm using is slightly outdated, but I've decided to continue using it with the latest version of Python to practice debugging. Sometimes there are a few things in the book's code that I learn have changed in the updated Python, and I'm not sure if this is one of them. While fixing a program so that it can print longer factorial values, it uses a long int to solve the problem. The original code is as follows: #factorial.py # Program to compute the factorial of a number

Why is new int (*)[3] an error?

旧巷老猫 提交于 2019-11-28 03:31:00
问题 typedef int (*A)[3]; int (**p)[3] = new A; // OK int (**q)[3] = new (int(*)[3]); // OK int (**r)[3] = new int (*)[3]; // error The error from GCC is error: expected primary-expression before ')' token . Why are the extra parentheses required in this expression? 回答1: The standard defines new-type-id as the longest sequence of new-declarators . There is also a note, which illustrates a similar situation (although it allocates pointers to functions): 5.3.4 New [expr.new] .... new-type-id: type