syntax-error

Possible Duplicate: Unexpected token ILLEGAL in webkit I wrote a simple script for a hover over effect here http://jsfiddle.net/paDmg/368/ for this site http://avuedesigns.com/new/ - It works on jsfiddle, but I am getting Uncaught SyntaxError: Unexpected token ILLEGAL in my JavaScript when I put it live. It's on line 29 it is telling me which is the closing marks });​ $('#hover-grid .indiv-cell').hover(function() { //set variables to current cell attributes var cellHeader = $(this).attr('data-hoverheader'); var cellText = $(this).attr('data-hovertext'); var replacementImg = $(this).find('a img

I created a playground in Xcode 6.3 (6D570) and input these following code: import UIKit var randum_num = arc4random_uniform(13) + 1 String(format: "card%i", arguments: randum_num) And I got this error: cannot find an initializer for type 'String' that accepts an argument list of type '(format: String, argument: UInt32 Sorry I'm complete new in Swift, thanks for any advices! P.S. I'm following this tutorial: link You just have to omit "arguments:". Try like this: let randum_num = arc4random_uniform(13) + 1 String(format: "card%i", randum_num) or simply String(format: "card%i", arc4random

I am writing some classes using Generics but I can't find a solution for the class SolutionsSubset and so I a getting the error "type parameter S is not within its bound". I have read previous questions about the same error but I can't solve it for my case. Could anybody help me to improve my knowledge about generics? Any reference to a good book (I can find in google a lot of information but if someone can reccommend a book, tutorial, etc. will be welcome). Although I tried to keep in mind the rules to ask a question but I apologize if my question doesn't fulfill these rules. I have the

So basically what I want to do is use libcurl to fetch slightly different urls, e.g.: http://foo.com/foo.asp?name=*NAMEHERE* What I would like to do is iterate through a vector of names and get each one, e.g.: http://foo.com/foo.asp?name=James Then http://foo.com/foo.asp?name=Andrew And so on. However, when I try doing this: int foo (){ CURL *curl; CURLcode success; char errbuf[CURL_ERROR_SIZE]; int m_timeout = 15; if ((curl = curl_easy_init()) == NULL) { perror("curl_easy_init"); return 1; } std::vector<std::string> names; names.push_back("James"); names.push_back("Andrew"); for (std::vector

The Python tutorial book I'm using is slightly outdated, but I've decided to continue using it with the latest version of Python to practice debugging. Sometimes there are a few things in the book's code that I learn have changed in the updated Python, and I'm not sure if this is one of them. While fixing a program so that it can print longer factorial values, it uses a long int to solve the problem. The original code is as follows: #factorial.py # Program to compute the factorial of a number # Illustrates for loop with an accumulator def main(): n = input("Please enter a whole number: ") fact

typedef int (*A)[3]; int (**p)[3] = new A; // OK int (**q)[3] = new (int(*)[3]); // OK int (**r)[3] = new int (*)[3]; // error The error from GCC is error: expected primary-expression before ')' token . Why are the extra parentheses required in this expression? The standard defines new-type-id as the longest sequence of new-declarators . There is also a note, which illustrates a similar situation (although it allocates pointers to functions): 5.3.4 New [expr.new] .... new-type-id: type-specifier-seq new-declarator opt new-declarator: ptr-operator new-declarator opt noptr-new-declarator noptr

def RandomString (length,distribution): string = "" for t in distribution: ((t[1])/length) * t[1] += string return shuffle (string) This returns a syntax error as described in the title. In this example, distribution is a list of tuples, with each tuple containing a letter, and its distribution, with all the distributions from the list adding up to 100, for example: [("a",50),("b",20),("c",30)] And length is the length of the string that you want. Python is upset because you are attempting to assign a value to something that can't be assigned a value. ((t[1])/length) * t[1] += string When you

Well, I keep getting Parse error: syntax error, unexpected T_STRING in /path/to/index.php on line 2 Googled my arse off and still nuthing, so far the index.php contains: <?php namespace Infire; # Line 2 ... I am using PHP 5.1 Any ideas? The PHP namespace is only supported in PHP 5.3+ version Check this PHP 5.3.0 Release Announcement I've found namespaces introduced in PHP 5.3 to suffer from multiple usability problems due to performance trade-offs, limitations of PHP's parser, collisions with other PHP features and unfortunate design decisions. 来源： https://stackoverflow.com/questions/12650836