syntax-error

TypeError: list indices must be integers, not tuple, whats wrong [duplicate]

北慕城南 提交于 2019-12-02 01:42:29
问题 This question already has answers here : Python 'list indices must be integers, not tuple" error (6 answers) Closed 3 years ago . New in Python, help. Why i get this error: "TypeError: list indices must be integers, not tuple," imheight = [] for i in range(0,len(tables)): for j in range(0,len(tables)): hij = computeHeight(imp[i],imp[j],'Meter') imheight[i,j] = hij imheight[j,i] = hij 回答1: This syntax is wrong: imheight[i,j] = hij imheight[j,i] = hij Perhaps you meant this? imheight[i][j] =

Syntax error when defining a function on the Python command line

爷,独闯天下 提交于 2019-12-02 01:40:06
I am trying to define a function on the Python REPL. Every time I try to run the below code, I get a syntax error. Code: def hello(): print ("Hello!") hello() Error: C:\Users\~\Desktop>python Python 3.6.5 (v3.6.5:f59c0932b4, Mar 28 2018, 16:07:46) [MSC v.1900 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> def hello(): ... print ("Hello!") ... hello() File "<stdin>", line 3 hello() ^ SyntaxError: invalid syntax A possible explanation I've come across on stackoverflow is this post Python Error : File "<stdin>" where it says I can't run scripts

Cause of “return outside of function” syntax error in Python?

∥☆過路亽.° 提交于 2019-12-02 01:28:57
I have problem in this code; 'return' outside function (<module1>, line 4) <module1> 4 This code from book called Learn the python hard way ; "Exercise 25: Even More Practice" def break_words(stuff): """This function will break up words for us.""" words = stuff.split(' ') return words def sort_words(words): """Sorts the words.""" return storred(words) def print_first_word(words): """Prints the first word after popping it off.""" word = words.php(0) print word def sort_last_word(words): """prints the last word after popping it off.""" word = words.pop(-1) print word def sort_sentence(sentence):

Variable '<variablename>' hides a variable in an enclosing block

筅森魡賤 提交于 2019-12-02 00:57:09
问题 When copying and pasting a bit of sample code from MSDN, I came up with the error in the title - Variable '' hides a variable in an enclosing block, All I copied was a very basic example of a try loop. As it says in the suggestion "A common cause for this error is the use of Catch e As Exception inside an event handler. If this is the case, name the Catch block variable ex rather than e." So, I did that, changed both e to ex and it worked, however, I don't understand why this doesn't cause

need help to export table from sql server 2008 to text file

五迷三道 提交于 2019-12-02 00:52:45
I am trying to export a table present in ms sql server 2008 to a text file on my system. I am writing the following command in sql server query window SELECT * FROM [AdventureWorks].[Person].[AddressType] INTO OUTFILE 'C:/filename.csv' FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n'; Now whenever I write this command the sql help gives me error that incorrect syntax near 'INTO' then I tried interchanging from and into keywords as follows SELECT * INTO OUTFILE 'C:/filename.csv' FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n' FROM [AdventureWorks].[Person].[AddressType] ; Now it gives me

MySQL Java Update Syntax

烂漫一生 提交于 2019-12-02 00:49:40
I just trying to use a update in my application, but i just can't. A the console, this mysql command works, but here, doesn't. Well, I use this in my program: conexao = poolMySQL.connect(); final String sql = "UPDATE professor SET codlocal = ? WHERE codprof = ?"; pstmt = conexao.prepareStatement(sql); pstmt.setInt(1, local); pstmt.setInt(2, id); try { pstmt.executeUpdate(sql); } catch (SQLException ex) { Logger.getLogger(ProfessorDAO.class.getName()).log(Level.SEVERE, null, ex); } Just reminding, codlocal is a foreign key from another table, named Localidade. I saw some examples about join,

SyntaxError when accessing column named “class” in pandas DataFrame

牧云@^-^@ 提交于 2019-12-02 00:12:50
问题 I have pandas DataFrame named 'dataset' and it contains a column named 'class' when I execute the following line I get SyntaxError: invalid syntax print("Unique values in the Class column:", dataset.class.unique()) It works for another column names but not working with 'class' How to use a keyword as column name in pandas ? 回答1: class is a keyword in python. A rule of thumb: whenever you're dealing with column names that cannot be used as valid variable names in python, you must use the

SQLite syntax error near “CREATE TABLE”

耗尽温柔 提交于 2019-12-02 00:10:25
Here's my code: String CREATE_DATABASE = "CREATE TABLE " + TABLE_NAME + "(" + KEY_ID + " INTEGER PRIMARY KEY AUTOINCREMENT, " + "title TEXT, "+ "author TEXT, "+ "state TEXT);"; db.execSQL(CREATE_DATABASE); The LogCat says : 12-11 23:43:50.553: E/AndroidRuntime(3706): android.database.sqlite.SQLiteException: near "CREATE TABLE": syntax error (code 1): , while compiling: CREATE TABLE PapersTable(_id INTEGER PRIMARY KEY AUTOINCREMENT, title TEXT, author TEXT, state TEXT); The CREATE TABLE syntax is all right as you've posted it. I suspect there's a non-breaking space (ASCII 0xA0) between CREATE

Variable '<variablename>' hides a variable in an enclosing block

廉价感情. 提交于 2019-12-01 22:21:56
When copying and pasting a bit of sample code from MSDN, I came up with the error in the title - Variable '' hides a variable in an enclosing block , All I copied was a very basic example of a try loop. As it says in the suggestion "A common cause for this error is the use of Catch e As Exception inside an event handler. If this is the case, name the Catch block variable ex rather than e." So, I did that, changed both e to ex and it worked, however, I don't understand why this doesn't cause the same error. Can someone please explain better what the error is and why e causes it, and ex doesn't?

PostgreSQL subquery with syntax error gives a valid result

流过昼夜 提交于 2019-12-01 22:19:36
What is happening here? I got two tables, test1 and test2: create table test1 (id1 int4 primary key); create table test2 (id2 int4 primary key); As expected, this query: select id1 from test2; produces a syntax error: ERROR: column "id1" does not exist LINE 1: select id1 from test2; However, when I try to execute this query: select * from test1 where id1 in (select id1 from test2); PostgreSQL doesn't complain, executes the query and gives me: id1 ----- (0 rows) Is there any logic in this? Or should I file a bug report? Columns from outer select are visible in sub-select. Your query is