stringr

This question already has an answer here: How to escape backslashes in R string 3 answers I'm working in R and having troubles escaping the backslash. I am using the library stringr . install.packages("stringr", repos='http://cran.us.r-project.org') library("stringr") I would like to do str = str_replace_all(str, "\", "") So I tried str = str_replace_all(str, "\\", "") but it won't work. What should I do? I found a solution that works str = gsub("([\\])","", str) Use Hmisc::escapeRegex and Hmisc::escapeBS which automatically escapes backslashes and other regex special characters. 来源： https:/

Suppose I have some text like this, text<-c("[McCain]: We need tax policies that respect the wage earners and job creators. [Obama]: It's harder to save. It's harder to retire. [McCain]: The biggest problem with American healthcare system is that it costs too much. [Obama]: We will have a healthcare system, not a disease-care system. We have the chance to solve problems that we've been talking about... [Text on screen]: Senators McCain and Obama are talking about your healthcare and financial security. We need more than talk. [Obama]: ...year after year after year after year. [Announcer]: Call

I am trying to find a simple way to extract an unknown substring (could be anything) that appear between two known substrings. For example, I have a string: a<-" anything goes here, STR1 GET_ME STR2, anything goes here" I need to extract the string GET_ME which is between STR1 and STR2 (without the white spaces). I am trying str_extract(a, "STR1 (.+) STR2") , but I am getting the entire match [1] "STR1 GET_ME STR2" I can of course strip the known strings, to isolate the substring I need, but I think there should be a cleaner way to do it by using a correct regular expression. You may use str