sql-order-by

mysql order varchar field as integer

旧城冷巷雨未停 提交于 2019-12-02 21:51:46
I have a varchar field in my table and I want to sort it. But I need to handle this field as integer. Meaning if sort as text the order is "19,2,20" but I want to get the right order "2,19,20". Can anyone help me? I somehow didn't manage to run the query with CAST . I was always getting Error Code: 1064 near "DECIMAL" (or other numeric type that I chose). So, I found another way to sort varchar as numbers: SELECT * FROM mytable ORDER BY ABS(mycol) A bit simpler and works in my case. SELECT * FROM mytable ORDER BY CAST(mycol AS DECIMAL) Here is the solution SELECT * FROM MyTable ORDER BY ABS

MySQL multiple column asc order

拈花ヽ惹草 提交于 2019-12-02 20:57:05
I am trying to run this query in ascending order: SELECT title,project_index FROM projectdetail WHERE project_index BETWEEN 1 AND 6 ORDER BY title, project_index ASC; I need two columns in ascending order, but the above query returns results with only one column in ASC order. Lieven Keersmaekers Ascending order is the default for most (if not all) DBMS's so your statement is kind of weird in that respect but nevertheless, you can specify an order for each individual column by adding the specifier ASC or DESC to it. Your statement then would become SELECT title , project_index FROM

select sql data order by date

↘锁芯ラ 提交于 2019-12-02 20:41:37
问题 I have a table with a column called date , as a varchar. The contents are specifically formatted like 'March 11, 2011'. How can I select the results have them correctly ordered by date? 回答1: I'm blindly assuming MySQL here, because it makes sense in the context of this question. Nobody using another database engine would dare create this problem in the first place. STR_TO_DATE to the rescue! Given the format "March 01, 2000", the following conversion should work. SELECT STR_TO_DATE(column

Is MySQL LIMIT applied before or after ORDER BY?

这一生的挚爱 提交于 2019-12-02 20:10:06
Which one comes first when MySQL processes the query? An example: SELECT pageRegions FROM pageRegions WHERE(pageID=?) AND(published=true) AND (publishedOn<=?) ORDER BY publishedON DESC LIMIT 1'; Will that return the last published pageRegion even if the record does not match the revision datetime IF LIMIT is applied after ORDER BY? Yes, it's after the ORDER BY. For your query, you'd get the record with the highest publishedOn, since you're ordering DESC , making the largest value first in the result set, of which you pick out the first one. The limit is always applied at the end of result

Can you sort Typed DataSet DataTables with Linq OrderBy?

人走茶凉 提交于 2019-12-02 18:31:00
问题 I have a Typed DataSet DataTable which inherits TypedTableBase<T> , which in turn implements IEnumerable<T> . I can't seem to get this to work. myDataTable.OrderBy(x => x.ID).ThenBy(y => y.ID2); Instead I have to assign this statement to an IEnumerable (or List), then refill my DataTable manually with the newly ordered IEnumerable before I commit. Is this how it is intended to be? I've thought about creating my own extension method that will empty/refill my DataTables, but would this be wise?

ORDER BY items must appear in the select list if SELECT DISTINCT is specified

半城伤御伤魂 提交于 2019-12-02 17:51:07
问题 I have sql query in which i want return rows with distinct value order by particular column. like say,i want disntict batchno from ordertable order by locationid. i have tried google also but not able to find out solution ORDER BY items must appear in the select list if SELECT DISTINCT is specified. that what i got every time i tried. when not using distinct i got output but with duplicate rows using this query Select Batchno,LocationId from Ordertbl order by case when[LocationId] =3 THEN 0

How to sum the duplicate values from mysql table

笑着哭i 提交于 2019-12-02 17:44:04
问题 i wanted to retrieve the sum of duplicate USD amount from below table with respect to date and ref_nr columns uid date USD Ref_Nr 1 2018-04-11 1 7 1 2018-04-11 2 7 1 2018-04-11 3 8 1 2018-04-11 4 8 1 2018-04-11 6 6 1 2018-04-11 6 6 1 2018-04-10 3 7 1 2018-04-10 5 7 1 2018-04-10 2 8 1 2018-04-10 2 8 Here is my sql query and what i tried, but iam not getting proper output, please help me SELECT uid , date , SUM(USD) AS USD , Ref_Nr FROM my_table GROUP BY `date`; Here is expected output uid date

SQL - How To Order Using Count From Another Table

空扰寡人 提交于 2019-12-02 17:12:51
1. Bloggers blogger_id 1 2 3 2. Posts post_from_blogger_id 1 1 1 2 2 3 As you can see blogger №1 posted more than the others and blogger №3 less. The question is how to build a query that selects all bloggers and sorts them by the number of their posts? SELECT bloggers.*, COUNT(post_id) AS post_count FROM bloggers LEFT JOIN blogger_posts ON bloggers.blogger_id = blogger_posts.blogger_id GROUP BY bloggers.blogger_id ORDER BY post_count (Note: MySQL has special syntax that lets you GROUP BY without aggregating all values, it's intended for exactly this situation). Use subqueries. select * from (

Where should I be limiting my results?

邮差的信 提交于 2019-12-02 16:21:39
问题 What I have done is created an XML file with a list of several thousand search terms that I need to perform on a document. I then created this query, from a sample set of search terms, as a test, to perform against a test document, with some samples from the actual document: let $keywords := ("best clients", "Very", "20") for $keyword in $keywords let $matches := doc('test')/set/entry[matches(comment, $keyword, 'i')] return (<re> {subsequence($matches/comment, 1, 1), subsequence($matches

JPA @OrderBy() Through Relational Table

我的梦境 提交于 2019-12-02 15:42:56
问题 I need some help with the JPA Framework. I've read some answers "kind of" about this topic but I couldn't reach any conclusion. First heres an examplo of the design i'm wooking with. @BusinessObject public class ClassA { @Column(name = "ID", nullable = false) private Long id; @OneToMany(mappedBy = "classAAttr") private Collection<ClassAB> classABCollection; //STUFF AND OTHER COLUMNS..... } public class ClassAB { @Column(name = "ID", nullable = false) private Long id; @JoinColumn(name = "TABLE