split

问题 I am using a data set like: 1 48434 14566 1 56711 6289 1 58826 4174 2 56626 6374 2 58888 4112 2 59549 3451 2 60020 2980 2 60468 2532 3 56586 6414 3 58691 4309 3 59360 3640 3 59941 3059 . . . 10 56757 6243 10 58895 4105 10 59565 3435 10 60120 2880 10 60634 2366 I need a plot in R of 3rd column for each value of first column i.e. for above data there would be 10 different plots of (each group 1-10) of values of 3rd column. x-axis is number of Iterations and Y-axis is the values with max 63000.

问题 i've got a problem.I want to remove digits from the end of a string,but i have no idea.Can the split() method work?How can i make that work?The initial string is like 'asdfg123',and i only want 'asdfg' instead.Thanks for your help! 回答1: No, split would not work, because split only can work with a fixed string to split on. You could use the str.rstrip() method: import string cleaned = yourstring.rstrip(string.digits) This uses the string.digits constant as a convenient definition of what needs

问题 I have a regular expression /\s*,\s*/ that matches left spaces followed by comma then right spaces. Example: var str = "john,walker james , paul"; var arr = str.split(/\s*,\s*/); Values in arr = [john,walker james,paul] // Size: 3 Example with Chinese characters: var str = "继续，取消 继续 ，取消"; var arr = str.split(/\s*,\s*/); Values in arr = ["继续，取消 继续 ，取消"] // Size: 1, All values at index 0 no splitting happened Tried splitting characters with unicodes: var str = "john,walker james , paul"; var

问题 I have a regular expression /\s*,\s*/ that matches left spaces followed by comma then right spaces. Example: var str = "john,walker james , paul"; var arr = str.split(/\s*,\s*/); Values in arr = [john,walker james,paul] // Size: 3 Example with Chinese characters: var str = "继续，取消 继续 ，取消"; var arr = str.split(/\s*,\s*/); Values in arr = ["继续，取消 继续 ，取消"] // Size: 1, All values at index 0 no splitting happened Tried splitting characters with unicodes: var str = "john,walker james , paul"; var

问题 Hi I am trying to split json string using possibly pipe? or I don't really know how to do it. Right now I have json string of "www.youtube.com||djlajdalksd.png||somethingsomething" (These are just made up) And I want to only get .png part. How could I achieve this? 回答1: Write a pipe: @Pipe({ name: "splitAndGet" }) export class SplitAndGetPipe implements PipeTransform { transform(input: string, separator: string,index:number): string { return input.split(separator)[index]; } } then in template

问题 In the following examples, I am splitting an empty string by a space. However, in the first example I explicitly used a space and in the second example, I didn't. My understanding was that .split() and .split(' ') were equivalent. Why do these two examples give different outputs? In [1]: "".split(' ') Out[1]: [''] In [2]: "".split() Out[2]: [] 回答1: From the python's documentation - If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace

问题 I have this dataframe CC.Number Date Time Accident.Type Location.1 1 12T008826 07/01/2012 1630 PD (39.26699, -76.560642) 2 12L005385 07/02/2012 1229 PD (39.000549, -76.399312) 3 12L005388 07/02/2012 1229 PD (39.00058, -76.399267) 4 12T008851 07/02/2012 445 PI (39.26367, -76.56648) 5 12T008858 07/02/2012 802 PD (39.240862, -76.599017) 6 12T008860 07/02/2012 832 PD (39.27022, -76.63926) I want to split the column Location.1 to "alt" and "lng" columns to be like CC.Number Date Time Accident.Type

问题 Sorry for the lack of better title. Hopefully the explanation below help. Given the following string: f=' Sleep stage W\\x14\\x00+26070\\x1590\\x14 Sleep stage W\\x14\\x00+26070\\x1590\\x14 Movement time\\x14\\x00+28110\\x15120\\x14 Sleep stage 3\\x14\\x00+28230\\x1530\\x14' and are to be split as below ' W\\x14\\x00+26070\\x1590\\x14 ' ' W\\x14\\x00+26070\\x1590\\x14 ' ' \\x14\\x00+28110\\x15120\\x14 ' ' 3\\x14\\x00+28230\\x1530\\x14' To realise this, the following code was drafted f=' Sleep

问题 This is continuation from the following OP1. While the suggestion by @Rakesh is awesomely compact, but the same solution cannot function properly when used with an open file which is accessible from the edf_file link. The code below file= 'edfx\\SC4002EC-Hypnogram.edf' # Please change according to the location of you file with open(file, mode='rb') as f: raw_hypno = re.split(r"Sleep stage|Movement time", f) will ouput an error of TypeError: expected string or bytes-like object Appreciate for

问题 This question was migrated from Cross Validated because it can be answered on Stack Overflow. Migrated 12 days ago . What I am trying to do? I am trying to use StratifiedKFold() in GridSearchCV() . Then, what does confuse me? When we use K Fold Cross Validation, we just pass the number of CV inside GridSearchCV() like the following. grid_search_m = GridSearchCV(rdm_forest_clf, param_grid, cv=5, scoring='f1', return_train_score=True, n_jobs=2) Then, when I will need to use StratifiedKFold() ,