split

问题 I'm trying to split a list into the items before a specific element (specifically the word "stop") as well as the items after this element. I know you can use split to do this, but I'm new to prolog and so I'm trying to manipulate things without using these functions currently, and so I'd really like to know if this is possible? (and maybe some pointers in the right direction) i.e. with the list; L = [tea,coffee,sugar,cake,stop,meat,fish,eggs,flour] I'd ideally want to split the list at 'stop

问题 I am getting below exception with Camel Route Caused by: com.fasterxml.jackson.databind.JsonMappingException: No serializer found for class org.apache.camel.converter.stream.InputStreamCache and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS) at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:284) at com.fasterxml.jackson.databind.SerializerProvider.mappingException(SerializerProvider

问题 Those who use, know, how useful automation tool AHK is.. The AHK has function StringSplit or StrSplit() which does very fast split string into array elements. This is very useful if you want to manipulate some parts of well formed string, but unfortunately it appears there is no way around! I spend time searching and there was a mess of samples with old syntax which just does not work. All I wanted is Final_Concatenated_String := StrConcat(My_Array_Of_Strings, "\") which obviously does not

问题 This is a spin-off from In Python, how do I split a string and keep the separators? rawByteString = b'\\!\x00\x00\x00\x00\x00\x00\\!\x00\x00\x00\x00\x00\x00' How can I split this rawByteString into parts using "\\!" as the delimiter without dropping the delimiters, so that I get: [b'\\!\x00\x00\x00\x00\x00\x00', b'\\!\x00\x00\x00\x00\x00\x00'] I do not want to use [b'\\!' + x for x in rawByteString.split(b'\\!')][1:] as that would use string.split() and is just a workaround, that is why this

问题 In my pandas dataframe, I have 100 news articles under the article column. Each news article is a string. I want to only keep the first 3 sentences of each string, but I don't know how. (I noticed each sentence is separated by \n ). Please suggest possible solutions. The dataframe looks like this: print("Reading data from csv file") print(read) Reading data from csv file Unnamed: 0 article 0 0 \nChina’s ambassador to the US wants American ... 1 1 \nMissouri has become the first state to file

问题 Would it be possible to take a string and set a different variable for every character of the string? In other words.. string='Hello' #Do some thing to split up the string here letter_1= #The first character of the variable 'string' letter_2= #The second character of the variable 'string' #... letter_5= #The fifth character of the variable 'string' 回答1: In Python, strings are immutable, so you can't change their characters in-place. However if you try to access by index then you get:

问题 This is the result when I apply split() against an empty string with default delimiter and with a "," as delimiter in Python. >>> print "".split(',') [''] >>> print "".split() [] Can somebody please explain why we should expect this behavior? 回答1: The behavior is as documented (emphasis added): split(...) S.split([sep [,maxsplit]]) -> list of strings Return a list of the words in the string S, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done. If sep is

问题 I am using split() and split(" ") on the same string. But why is split(" ") returning less number of elements than split() ? I want to know in what specific input case this would happen. 回答1: str.split with the None argument (or, no argument) splits on all whitespace characters, and this isn't limited to just the space you type in using your spacebar. In [457]: text = 'this\nshould\rhelp\tyou\funderstand' In [458]: text.split() Out[458]: ['this', 'should', 'help', 'you', 'understand'] In [459

问题 This question already has answers here : Python splitting a list based on a delimiter word (4 answers) Closed 2 years ago . I am trying to split a list that I have into individual lists whenever a specific character or a group of characters occur. eg. Main_list = [ 'abcd 1233','cdgfh3738','hryg21','**L**','gdyrhr657','abc31637','**R**','7473hrtfgf'...] I want to break this list and save it into a sublist whenever I encounter an 'L' or an 'R' Desired Result: sublist_1 = ['abcd 1233','cdgfh3738

问题 I am using a data set like: 1 48434 14566 1 56711 6289 1 58826 4174 2 56626 6374 2 58888 4112 2 59549 3451 2 60020 2980 2 60468 2532 3 56586 6414 3 58691 4309 3 59360 3640 3 59941 3059 . . . 10 56757 6243 10 58895 4105 10 59565 3435 10 60120 2880 10 60634 2366 I need a plot in R of 3rd column for each value of first column i.e. for above data there would be 10 different plots of (each group 1-10) of values of 3rd column. x-axis is number of Iterations and Y-axis is the values with max 63000.