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可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I need to get the files in a directory in an array. Only files that end in .markdown The files should be sorted by date created Efficiency is not a huge deal, but I always like to make things as efficient as possible. There will be multiple directories with up to a couple hundred files in each. I know I use the scandir function to get the files into an array, but I'm not sure where to go from there. I could throw it in a loop to check if the files end in .markdown , but is there some sort of regex I could pass in to the scan? Thanks 回答1: You

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Source: .foo { line-height: 150px; font-size: 24px; clear: both; } vim magic here, probably something visual selection based Result: .foo { clear: both; font-size: 24px; line-height: 150px; } What do you suggest for the vim magic part? 回答1: :s/\([{;]\)\s*/\1\r/g | '[+1,']sort | '[,']join Split the line on { or ; to get each rule into a separate line, :sort them (omitting the first line containing the CSS definition), then join them back together. 回答2: Very quick answer: :s/[{;] /\0\r vi{ :!sort va{ J 回答3: Another one-liner: s/{\s*\zs.\{-}\ze

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a table of venues which I'm displaying on the venues index page as partials. I also have a table of reviews where one venue can have many reviews and each review has a rating 1-5. I'm trying to get the venues to display on the index page with the ones with the highest average rating at the top and descending. The controller code looks like this: Venues controller def index if @venues = Venue.with_type(params[:venuetypes]).with_area(params[:areas]).joins(:reviews).order("reviews.rating DESC") else @venues = Venue.all end end This gives

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm looking for some pointers here as I don't quite know where to start researching this one. I have a 2D matrix with 0 or 1 in each cell, such as: 1 2 3 4 A 0 1 1 0 B 1 1 1 0 C 0 1 0 0 D 1 1 0 0 And I'd like to sort it so it is as "upper triangular" as possible, like so: 4 3 1 2 B 0 1 1 1 A 0 1 0 1 D 0 0 1 1 C 0 0 0 1 The rows and columns must remain intact, i.e. elements can't be moved individually and can only be swapped "whole". I understand that there'll probably be pathological cases where a matrix has multiple possible sorted results

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a list of data that is not in alphabetical or numerical order. I want to sort a second list of the same date to match the first list. I cannot change the order of the data. My goal is to paste additional data from the second set back into the first data set. **DATA SET A** **DATA SET B** 22350 ____ BH160 100 22355 ____ 22350 125 BH160 ____ BH190 200 BH190 ____ 22355 150 I would like to get the numerical value from column 2 of DATA SET B to show up in a new column of DATA SET A. For example, I want 125 to show up in line 1, column 2 of

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am doing a search in two text fields called Subject and Text for a specific keyword. To do this I use the LIKE statement. I have encountered a problem when trying to sort the results by the number of occurrences. my search query looks like this: SELECT * FROM Table WHERE (Text LIKE '%Keyword%' OR Subject LIKE '%Keyword%') I tried to add a count() statement and sort it by the number of occurrences, but the count() statement just keep returning the number of rows in my table. Here is the query with count statement: SELECT *, COUNT(Text LIKE

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: So I've been trying to understand Big O notation as well as I can, but there are still some things I'm confused about. So I keep reading that if something is O(n), it usually is referring to the worst-case of an algorithm, but that it doesn't necessarily have to refer to the worst case scenario , which is why we can say the best-case of insertion sort for example is O(n). However, I can't really make sense of what that means. I know that if the worst-case is O(n^2), it means that the function that represents the algorithm in its worst case

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a record in erlang: -record(myrec, { id = 0, price = 0, quantity = 0 }). I then have a list of records that I want to sort by id and price, both in descending and ascending order, where price is the first key and if two records have the same price I want to sort those by id. How can I define a fun for this? I'm a newb at Erlang :) thanks, nisbus 回答1: This is a shorter solution than what has been suggested so far. First define your record: 1> rd(myrec, {id=0, price=0, quantity=0}). myrec Then let's invent 3 of them: 2> A = #myrec{id=1,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am working on a personal project to learn Node.js + express + Bookshelf.js. Where do I build queries? In particular, how do I simply set an 'ORDER BY' or 'WHERE' in the following code? var Accounts = require('../collections/accounts').collection; new Accounts().fetch({ withRelated: ['folders'] }).then(function(collection) { // process results }); I would like to learn Bookshelf.js because it seems to offer the features I am used to with Laravel's Elequent (PHP), such as polymorphic relationships and sub expressions. However, I'm finding

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm using pyspark(Python 2.7.9/Spark 1.3.1) and have a dataframe GroupObject which I need to filter & sort in the descending order. Trying to achieve it via this piece of code. group_by_dataframe.count().filter("`count` >= 10").sort('count', ascending=False) But it throws the following error. sort() got an unexpected keyword argument 'ascending' 回答1: In PySpark 1.3 sort method doesn't take ascending parameter. You can use desc method instead: from pyspark.sql.functions import col (group_by_dataframe .count() .filter("`count` >= 10") .sort