sort

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have this code to get all transaction between 2 dates. I would like to get a desc sorted list. What are the possibilities? @Override public List<Transaction> searchBySubmitDate(final Date startDate, final Date endDate) { return transactionRepository.findAll(new Specification<Transaction>() { @Override public Predicate toPredicate(Root<Transaction> transaction, CriteriaQuery<?> q, CriteriaBuilder cb) { Predicate between = cb.between(transaction.get(Transaction_.dateSubmit), startDate, endDate); return between; } }); 回答1: @Override public

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a Map<String, Long> map which I want to sort by the Long value in reversed order using the features of Java 8. With Google I found this thread which provides this solution Map<String, Long> sortedMap = map.entrySet().stream() .sorted(comparing(Entry::getValue)) .collect(toMap(Entry::getKey, Entry::getValue, (e1,e2) -> e1, LinkedHashMap::new)); If I want to have the order reversed in the comments it says to use comparing(Entry::getValue).reversed() instead of comparing(Entry::getValue) . However, the code doesn't work. But with this

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Can Breadth first Search be used for finding topological sorting of vertices and strongly connected components in a graph? If yes how to do that? and If not why not? we generally use Depth first search in these problems but What will be the problem if I try to implement using BFS? Will code like this work? def top_bfs(start_node): queue = [start_node] stack = [] while not queue.empty(): node = queue.dequeue() if not node.visited: node.visited = True stack.push(node) for c in node.children: queue.enqueue(c) stack.reverse() return stack 回答1:

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Beginning programmer here, just wanting to understand the process behind Ruby's sort method when using the spaceship operator <=> . Hope someone can help. In the following: array = [1, 2, 3] array.sort { |a, b| a <=> b } ... I understand that sort is comparing a pair of numbers at a time and then returning -1 if a belongs before b , 0 if they're equal, or 1 if a should follow b . But in the case of sorting in descending order, like so: array.sort { |a, b| b <=> a } ... what exactly is happening? Does sort still compare a <=> b and then flip

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Probably best illustrated with a small example. Given the relations A < B < C A < P < Q Correct outputs would be ABCPQ or APQBC or APBCQ ... etc. In other words, any ordering is valid in which the given relationships hold. I am most interested in the solution that is easiest to implement, but the best O(n) in speed and time is interesting as well. 回答1: This is called topological sorting . The standard algorithm is to output a minimal element, then remove it and repeat until done. 回答2: Do several sorts. First sort according to the first rule,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm taking a Data Mining course at university right now, but I'm a wee bit stuck on a multi-index sorting problem. The actual data involves about 1 million reviews of movies, and I'm trying to analyze that based on American zip codes, but to test out how to do what I want, I've been using a much smaller data set of 250 randomly generated ratings for 10 movies and instead of zip codes, I'm using age groups. So this is what I have right now, it's a multiindexed DataFrame in Pandas with two levels, 'group' and 'title' rating group title Alien 4

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have multiple arrays, and I want to sort all of them based on the sorted order of one of them, like so: var myArr = ["b", "a", "c"] var myArr2 = ["letter b", "letter a", "letter c"] var myArr3 = ["b is the second letter", "a is the first letter", "c is the third letter"] func sortMultipleArraysBasedOnOne(alphabeticallyArray:Array, arrays:[Array]){ //order myArr alphabetically for array in arrays{ //change all arrays indexes like in myArr } } sortMultipleArraysBasedOnOne(myArr, [myArr2, myArr3]) I expect after function execution the arrays

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm taking a Data Mining course at university right now, but I'm a wee bit stuck on a multi-index sorting problem. The actual data involves about 1 million reviews of movies, and I'm trying to analyze that based on American zip codes, but to test out how to do what I want, I've been using a much smaller data set of 250 randomly generated ratings for 10 movies and instead of zip codes, I'm using age groups. So this is what I have right now, it's a multiindexed DataFrame in Pandas with two levels, 'group' and 'title' rating group title Alien 4

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have two linux machines, on which unix sort seems to behave differently. I believe I've narrowed it down to the treatment of the underscore character. If I run sort tmp , where tmp contains the following two lines: aa_d_hh aa_dh_ey one machine outputs aa_d_hh aa_dh_ey (i.e. '_' precedes 'h') while the other outputs aa_dh_ey aa_d_hh (i.e. 'h' precedes '_'). I need these machines to behave together (as I use sort -m later, to merge very large files). Is there any way I can force sort to behave in one way or the other? Thanks. 回答1:

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to group my dataframe by two columns and then sort the aggregated results within the groups. In [167]: df Out[167]: count job source 0 2 sales A 1 4 sales B 2 6 sales C 3 3 sales D 4 7 sales E 5 5 market A 6 3 market B 7 2 market C 8 4 market D 9 1 market E In [168]: df.groupby(['job','source']).agg({'count':sum}) Out[168]: count job source market A 5 B 3 C 2 D 4 E 1 sales A 2 B 4 C 6 D 3 E 7 I would now like to sort the count column in descending order within each of the groups. And then take only the top three rows. To get something