slice

I have a NSMutableArray whose count is 10 and I want to extract the last 5 values and store them in another array. How can I do this? I think that - (NSArray *) subarrayWithRange:(NSRange)range ( doc ) might help you. NSRange theRange; theRange.location = [wholeArray count] - 5; theRange.length = 5; NSArray *result = [wholeArray subarrayWithRange:theRange]; EDIT : Be careful to check that your array has at least five elements, else, subarrayWithRange will throw an exception. Use following way : NSMutableArray *first = [[NSMutableArray alloc] initWithObjects:@"1",@"2",@"3",@"4",@"5",@"6",@"7",@

Please help me to get the counter for the list SS2 in list SS1 in PYTHON using from collections import Counter or any other fastest way SS1 = [(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)] SS2=[(1, 2, 3), (1, 2, 4), (1, 2, 5), (1, 2, 6), (1, 3, 4), (1, 3, 5), (1, 3, 6), (1, 4, 5), (1, 4, 6), (1, 5, 6), (2, 3, 4), (2, 3, 5), (2, 3, 6), (2, 4, 5), (2, 4, 6), (2, 5, 6), (3, 4, 5), (3, 4, 6), (3, 5, 6), (4, 5, 6)] Here is what i have tried and i don't know how to get the count for (1,2,4) th elements of the each tuple SS1=[(1, 2, 3, 4, 5), (1

This question already has an answer here: How to change struct variable content? 1 answer Why can't I append to a slice that's the property of a struct in golang? 1 answer I have a struct "Guest" which contains metadata of a party guest (a unique ID, name, surname and a list of the unique IDs of the guests who are friends of this guest. type Guest struct { id int name string surname string friends []int } I have the following code to remove an ID from the list of friends: func (self Guest) removeFriend(id int) { for i, other := range self.friends { if other == id { self.friends = append(self

题目地址： https://leetcode-cn.com/problems/height-checker/ 思路：将乱序数组排序后，遍历对比两数组有多少处不同 代码： /** * @param {number[]} heights * @return {number} */ var heightChecker = function(heights) { let sortArr = heights.slice(0,heights.length); let number = 0; sortArr.sort(function(a, b) {return a - b}); for(let i = 0; i < heights.length; i++){ if(heights[i] !== sortArr[i] ){ number++; } } return number; }; 收获： arrayObject.slice(start,end)：start：必需。　　　　规定从何处开始选取。如果是负数，那么它规定从数组尾部开始算起的位置。也就是说，-1 指最后一个元素，-2 指倒数第二个元素，以此类推。end:可选。　　　　规定从何处结束选取。该参数是数组片断结束处的数组下标。如果没有指定该参数，那么切分的数组包含从 start 到数组结束的所有元素。　　　　如果这个参数是负数

I have some code where I repeatedly need to repeatedly broadcast arrays in complex ways, for example: a = b[np.newaxis, ..., :, np.newaxis] * c[..., np.newaxis, np.newaxis, :] Is there an object to which I can store these slicing specifications? i.e. (but obviously this doesn't work): s1 = magic([np.newaxis, ..., :, np.newaxis]) s2 = magic([..., np.newaxis, np.newaxis, :]) Edit: perhaps this could be done with numpy.broadcast_to , but it's unclear how exactly while making sure that the correct axes are broadcast over... You can construct the index tuple manually, but NumPy includes a helper

I have written some tests where I need to assert that two arrays are equal. Some arrays are [u8; 48] while others are [u8; 188] : #[test] fn mul() { let mut t1: [u8; 48] = [0; 48]; let t2: [u8; 48] = [0; 48]; // some computation goes here. assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1); } I get multiple errors here: error[E0369]: binary operation `==` cannot be applied to type `[u8; 48]` --> src/main.rs:8:5 | 8 | assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1); | ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ | = note: an implementation of `std::cmp: