slice

iOS Frameworks with x86 Slice for Simulator + Appstore Approval

匿名 (未验证) 提交于 2019-12-03 01:47:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am building and distributing an iOS Framework library for consumption by other developers. Recently I ran into a bug (feature?) of the Apple Store whereby if an iOS Framework is built with the x86 Architecture (for the simulator) then the entire app fails App Store approval with the error: [Transporter Error Output]: ERROR ITMS-90087: "Unsupported Architectures. The executable for blah.app/Frameworks/MyLib.framework contains unsupported architectures '[x86_64, i386]'." What is the best practice here? Should I: Include debug (with simulator

How do I initialize values in a hash without a loop?

萝らか妹 提交于 2019-12-03 01:46:22
I am trying to figure out a way to initialize a hash without having to go through a loop. I was hoping to use slices for that, but it doesn't seem to produce the expected results. Consider the following code: #!/usr/bin/perl use Data::Dumper; my %hash = (); $hash{currency_symbol} = 'BRL'; $hash{currency_name} = 'Real'; print Dumper(%hash); This does work as expect and produce the following output: $VAR1 = 'currency_symbol'; $VAR2 = 'BRL'; $VAR3 = 'currency_name'; $VAR4 = 'Real'; When I try to use slices as follows, it doesn't work: #!/usr/bin/perl use Data::Dumper; my %hash = (); my @fields =

GoLang: How to delete an element from a 2D slice?

匿名 (未验证) 提交于 2019-12-03 01:39:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I've recently been messing around with Go and I wanted to see how it would be to delete an element from a two-dimensional slice. For deleting an element from a one-dimensional slice, I can successfully use: data = append(data[:i], data[i+1:]...) However, with a two-dimensional slice, using: data = append(data[i][:j], data[i][j+1:]...) throws the error: cannot use append(data[i][:j], data[i][j+1:]...) (type []string) as type [][]string in assignment Would tackling this require a different approach? 回答1: A 2D slice in Go is nothing more than a

Typescript subtract two numbers at compile time

匿名 (未验证) 提交于 2019-12-03 01:39:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Original question I need an utility type Subtract<A, B> where A and B are numbers. For example: type Subtract<A extends number, B extends number> = /* implementation */ const one: Subtract<2, 1> = 1 const two: Subtract<4, 2> = 2 const error: Subtract<2, 1> = 123 // Error here: 123 is not assignable to type '1'. Arguments to the Subtract<A, B> are always number literals or compile time constants. I do not need let foo: Subtract<number, number> // 'foo' may have 'number' type. Edited question Ok, I think that above text probably is the XY

Multiprocessing pool with an iterator

匿名 (未验证) 提交于 2019-12-03 01:27:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I would like to use multiprocessing pool with an iterator in order to execute a function in a thread splitting the iterator in N elements until the iterator is finish. import arcpy from multiprocessing import Pool def insert(rows): with arcpy.da.InsertCursor("c:\temp2.gdb\test" fields=["*"]) as i_cursor: #i_cursor is an iterator for row in rows: i_cursor.insertRow(row) input_rows = [] count = 0 pool = Pool(4) with arcpy.da.SearchCursor("c:\temp.gdb\test", fields=["*"]) as s_cursor: #s_cursor is an iterator for row in s_cursor: if (count My

Understanding pythons reverse slice ( [::-1] )

匿名 (未验证) 提交于 2019-12-03 01:26:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I always thought that omitting arguments in the python slice operation would result into: start = 0 end = len(lst) step = 1 That holds true if the step is positive, but as soon as the step is negative, like in the "reverse slice" [::-1] , omitting start/end results in: start = len(lst)-1 end = None Is this a special case, or am I missing something? 回答1: The default is always None ; it is up to the type to determine how to handle None for any of the 3 values. The list object is simply passed a slice(None, None, -1) object in this

selecting a range of elements in an array spark sql

匿名 (未验证) 提交于 2019-12-03 01:26:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I use Spark-shell to do the below operations Recently loaded a table with an array column in spark-sql . Here is the ddl for the same: create table test_emp_arr{ dept_id string, dept_nm string, emp_details Array } the data looks something like this +-------+-------+-------------------------------+ |dept_id|dept_nm| emp_details| +-------+-------+-------------------------------+ | 10|Finance|[Jon, Snow, Castle, Black, Ned]| | 20| IT| [Ned, is, no, more]| +-------+-------+-------------------------------+ i can query the emp_details column

How to get list name and slice name with pipe and purrr

匿名 (未验证) 提交于 2019-12-03 01:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I wonder how to get the list name or group name as a flag when using pipe operation with purrr. for example: I want to use a dynameic parameter of each list name pass to the ggsave function. require ( purrr ) require ( ggplot2 ) lst = list ( a1 = data . frame ( x = 1 : 10 , y = 2 : 11 ), a2 = data . frame ( x = 1 : 10 , y =- 1 * 2 : 11 )) df = rbind ( transform ( lst [[ 1 ]], id = "a1" ), transform ( lst [[ 2 ]], id = "a2" )) lst %>% map (~ ggsave ( plot = qplot ( data =., x = "x" , y = "y" , geom = "line" ), file = paste (

Is there any convenient way to get JSON element without type assertion?

混江龙づ霸主 提交于 2019-12-03 01:19:56
问题 There is some inconvenience while processing JSON response from a web server. For example, I don't know the data structure (and don't want to model it) of the JSON in advance, and just want to get the value from it! So, for Python, I can just write value = response["body"][4]["data"]["uid"] //response is a dictionary But for Golang, I need to do the assertion for every element! value := response["body"].([]interface{})[4].(map[string]interface{})["data"].(map[string]interface{})["uid"] /

Why is this list slice treating 0 and 1 as the same in Python? [duplicate]

前提是你 提交于 2019-12-03 01:13:51
问题 This question already has answers here : Understanding slice notation (32 answers) Closed 5 years ago . I'm a bit confused about slicing a list and the numbering here. Python tends to start from 0 instead of 1, and it's shown below to work in that way well enough. But if we're starting from 0, and going until 3, why am I not getting exam instead of exa ? After all, 0 - 3 is 4 numbers. >>> test = "example string" >>> print test[:3] exa >>> print test[0:3] exa >>> print test[1:3] xa 回答1: This