slice

How to show a subsection or “slice” of an SVG graphic?

北慕城南 提交于 2019-12-04 11:42:31
Is there any way to slice an SVG . I mean any already available lib . I need to implement this slicing component in Java. I mean , I have single SVG file and based rulers/scales i choose graphically , I want to slice the single SVG into different SVG files. Hope I am clear Yes, although, you'd think this was classified information - or just simply impossible - based on how hard it is to find this basic fact.... Apparently , all you need to do is reference the viewBox from a URI "fragment". . I have confirmed, it does indeed work. Take the following example... The lesson of the story, in case

Why does slice capacity with odd numbers differ from behavior with even numbers

夙愿已清 提交于 2019-12-04 11:31:58
问题 I noticed that the capacity of slices behaves in a different way, when the capacity is an odd number. More specifically: When an element is added to a slice, the capacity of the slice is doubled when the original capacity was an even number. But when the original capacity was an odd number, the capacity is incremented by one and then doubled . Example: s := make([]int, 28, 28) s = append(s, 1) fmt.Println("len=", len(s), " cap=", cap(s)) // len = len + 1, cap = 2 * cap pri := make([]int, 27,

Is returning a slice of a local array in a Go function safe?

邮差的信 提交于 2019-12-04 11:28:35
What happens if I return a slice of an array that is a local variable of a function or method? Does Go copy the array data into a slice create with make() ? Will the capacity match the slice size or the array size? func foo() []uint64 { var tmp [100]uint64 end := 0 ... for ... { ... tmp[end] = uint64(...) end++ ... } ... return tmp[:end] } icza This is detailed in Spec: Slice expressions . The array will not be copied, but instead the result of the slice expression will be a slice that refers to the array. In Go it is perfectly safe to return local variables or their addresses from functions

How do you use a variable as an index when slicing strings in Python?

感情迁移 提交于 2019-12-04 11:26:43
I've been trying to slice two characters out of a string using a loop, but instead of grabbing two characters, it only grabs one. I've tried: input[i:i+1] and input[i:(i+1)] but neither seems to work. How do I use a variable for slicing? The full routine: def StringTo2ByteList(input): # converts data string to a byte list, written for ascii input only rlist = [] for i in range(0, len(input), 2): rlist.append(input[i:(i+1)]) return rlist The slice values aren't the start and end characters of the slice, they're the start and end points . If you want to slice two elements then your stop must be

How to get the underlying array of a slice in Go?

﹥>﹥吖頭↗ 提交于 2019-12-04 10:31:21
问题 Let's say I have the following array of ints of length 3: nums := [3]int{1,2,3} Then I grab the slice of just the first two items numSlice := nums[:2] Invoking cap on numSlice and nums yields 3 in both cases, and len yields 2 and 3 respectively. If I then append to that slice ( numSlice = append(numSlice, 10) ), the underlying array ( nums ) is now [1 2 10] . cap remains at 3 for both, as the underlying array of the slice is the same, and len for the slice is now 3. However, if I append to

How do I initialize an array without using a for loop in Go?

巧了我就是萌 提交于 2019-12-04 09:49:51
I have an array A of boolean values, indexed by integers 0 to n , all initially set to true . My current implementation is : for i := 0; i < n; i++ { A[i] = true } icza Using a for loop is the simplest solution. Creating an array or slice will always return you a zeroed value. Which in case of bool means all values will be false (the zero value of type bool ). Note that using a Composite literal you can create and initialize a slice or array, but that won't be any shorter: b1 := []bool{true, true, true} b2 := [3]bool{true, true, true} If you don't want to use a for loop, you can make it a

How can I slice an object in Javascript?

本秂侑毒 提交于 2019-12-04 09:03:26
问题 I was trying to slice an object using Array.prototype, but it returns an empty array, is there any method to slice objects besides passing arguments or is just my code that has something wrong? Thx!! var my_object = { 0: 'zero', 1: 'one', 2: 'two', 3: 'three', 4: 'four' }; var sliced = Array.prototype.slice.call(my_object, 4); console.log(sliced); 回答1: I was trying to slice an object using Array.prototype , but it returns an empty array That's because it doesn't have a .length property. It

go中的数据结构切片-slice

两盒软妹~` 提交于 2019-12-04 08:56:51
1.部分基本类型   go中的类型与c的相似,常用类型有一个特例:byte类型,即字节类型,长度为,默认值是0; 1 bytes = [5]btye{'h', 'e', 'l', 'l', 'o'}   变量bytes的类型是[5]byte,一个由5个字节组成的数组。它的内存表示就是连起来的5个字节,就像C的数组。 1.1字符串   字符串在Go语言内存模型中用一个2字长(64位,32位内存布局方式下)的数据结构表示。它包含一个指向字符串数据存储地方的指针,和一个字符串长度数据如下图:   s是一个string类型的字符串,因为string类型不可变,对于多字符串共享同一个存储数据是安全的。切分操作 str[i:j] 会得到一个新的2字长结构t,一个可能不同的但仍指向同一个字节序列(即上文说的存储数据)的指针和长度数据。所以字符串切分不涉及内存分配或复制操作,其效率等同于传递下标。 1.2数组   数组类型定义了长度和元素类型。如, [4]int 类型表示一个四个整数的数组,其长度是固定的,长度是数组类型的一部分( [4]int 和 [5]int 是完全不同的类型)。 数组可以以常规的索引方式访问,表达式 s[n] 访问数组的第 n 个元素。数组不需要显式的初始化;数组的零值是可以直接使用的,数组元素会自动初始化为其对应类型的零值。 1 var a [4]int 2 a[0] =

how to get the last part of a string before a certain character?

孤街浪徒 提交于 2019-12-04 07:40:13
问题 I am trying to print the last part of a string before a certain character. I'm not quite sure whether to use the string .split() method or string slicing or maybe something else. Here is some code that doesn't work but I think shows the logic: x = 'http://test.com/lalala-134' print x['-':0] # beginning at the end of the string, return everything before '-' Note that the number at the end will vary in size so I can't set an exact count from the end of the string. 回答1: You are looking for str

Converting nested lists of data into multidimensional Numpy arrays

柔情痞子 提交于 2019-12-04 06:53:48
In the code below I am building data up in a nested list. After the for loop what I would like is to cast it into a multidimensional Numpy array as neatly as possible. However, when I do the array conversion on it, it only seems to convert the outer list into an array. Even worse when I continue downward I wind up with dataPoints as shape (100L,) ...so an array of lists where each list is my data (obviously I wanted a (100,3) ). I have tried fooling with numpy.asanyarray() also but I can't seem to work it out. I would really like a 3d array from my 3d list from the outset if that is possible.