range

For loop only executes 1 time, though given a range of 5

社会主义新天地 提交于 2019-12-01 14:20:30
I have the following code: def input_scores(): scores = [] y = 1 for num in range(5): score = int(input(print('Please enter your score for test %d: ' %y))) while score < 0 or score > 100: print ('Error --- all test scores must be between 0 and 100 points') score = int(input('Please try again: ')) scores.append(score) y += 1 return scores When I run it, the output is as follows: Please enter your score for test 1: None Then I'll enter the test score next to None, as, say 95 It then runs through the rest of the program without prompting me for the next test score to add to the scores list. I'm

VBA Run-time error 1004 when trying to copy paste cells in a separate sheet

本秂侑毒 提交于 2019-12-01 14:17:28
I am currently getting the following error in my VBA Excel 2007 code: Run-time error '1004': Method 'Range'of object '_Worksheet' failed. Having peeled through quite a few questions with this error in the title I haven't quite found a similar situation or a solution to my problem. That is, without declaring my variables as public, which, I don't want to do as I use the same variables multiple times in different subroutines. The error is raised on line: AccDnn.Range(Cells(2, 71), Cells(RangéeFinAcc - 1, 87)).Copy My code: Private Sub SaveRedButton_Click() Dim SaveRedMssg As String, SaveRedTitre

php check multiple dates in array are within a date range

半腔热情 提交于 2019-12-01 14:14:12
I have an array structured like this: Array ( [0] => 24-12-2013 [1] => 25-12-2013 [2] => 26-12-2014 [3] => 27-12-2013 [4]) I would like to check if any of the dates in the array are within a given date range. The date range is structured like this: $start = (date("d-m-Y", strtotime('25-12-2013'))); $end = (date("d-m-Y", strtotime('26'12'2013'))); I would like to know which dates in the array are within the date range. Couple things: Use timestamps or DateTime objects to compare dates, not strings Use date format YYYY-MM-DD to avoid potential ambiguity about your date format (d/m/y or m/d/y)

How can I use jQuery to apply css to savedRange text selection?

心已入冬 提交于 2019-12-01 14:09:43
Is it possible to apply css or wrap tags around savedRange text selection. I'm using jquery. this doesn't work: $(savedRange).css(...); $(savedRange).wrap(...); Matt Zukowski If by "savedRange" you mean something like this: selection = window.getSelection() savedRange = selection.getRangeAt(0) Then you will have to create a wrapper for the range first, like so: wrapper = document.createElement('span') savedRange.surroundContents(wrapper) selection.selectAllChildren(wrapper) You can then apply style: $(wrapper).css(...) It won't work around selected text but this would put an HTML tag with some

CakePHP Increase Year Range in Drop Down

江枫思渺然 提交于 2019-12-01 13:57:32
问题 In CakePHP, if i keep a table field type as date , then it shows dropdown with month, day and year. However, the year range starts from 1990 only, how can I change it to start from 1900 ? 回答1: You can use minYear and maxYear options of an input like this: <?php echo $this->Form->input('birth_dt', array( 'label' => 'Date of birth', 'dateFormat' => 'DMY', 'minYear' => date('Y') - 70, 'maxYear' => date('Y') - 18 )); ?> Reference to cakePHP Cookbook FYI: If current year is 2017 date('Y') - 70

php check multiple dates in array are within a date range

[亡魂溺海] 提交于 2019-12-01 13:13:41
问题 I have an array structured like this: Array ( [0] => 24-12-2013 [1] => 25-12-2013 [2] => 26-12-2014 [3] => 27-12-2013 [4]) I would like to check if any of the dates in the array are within a given date range. The date range is structured like this: $start = (date("d-m-Y", strtotime('25-12-2013'))); $end = (date("d-m-Y", strtotime('26'12'2013'))); I would like to know which dates in the array are within the date range. 回答1: Couple things: Use timestamps or DateTime objects to compare dates,

Python: range function for decimal numbers

家住魔仙堡 提交于 2019-12-01 12:42:38
Is there any range() function in python for float numbers for example a=0.6 if a in range(0,1): a=3 How can i implement this? If I'm reading correctly, you want to test if a number is between two other numbers, so use: a = 0.6 if 0 <= a < 1: # change to `<= 1` to be inclusive a = 3 You don't need to generate a range and do membership testing - unless you have a discrete set of values that your a should match - the builtin range in Python 3.x can do efficient lookups for int s as it can optimise membership testing. If you have a large amount of discrete values in a large range, then you'd be

VBA Run-time error 1004 when trying to copy paste cells in a separate sheet

萝らか妹 提交于 2019-12-01 12:40:28
问题 I am currently getting the following error in my VBA Excel 2007 code: Run-time error '1004': Method 'Range'of object '_Worksheet' failed. Having peeled through quite a few questions with this error in the title I haven't quite found a similar situation or a solution to my problem. That is, without declaring my variables as public, which, I don't want to do as I use the same variables multiple times in different subroutines. The error is raised on line: AccDnn.Range(Cells(2, 71), Cells

For loop only executes 1 time, though given a range of 5

做~自己de王妃 提交于 2019-12-01 12:26:53
问题 I have the following code: def input_scores(): scores = [] y = 1 for num in range(5): score = int(input(print('Please enter your score for test %d: ' %y))) while score < 0 or score > 100: print ('Error --- all test scores must be between 0 and 100 points') score = int(input('Please try again: ')) scores.append(score) y += 1 return scores When I run it, the output is as follows: Please enter your score for test 1: None Then I'll enter the test score next to None, as, say 95 It then runs

Python: range function for decimal numbers

断了今生、忘了曾经 提交于 2019-12-01 11:16:55
问题 Is there any range() function in python for float numbers for example a=0.6 if a in range(0,1): a=3 How can i implement this? 回答1: If I'm reading correctly, you want to test if a number is between two other numbers, so use: a = 0.6 if 0 <= a < 1: # change to `<= 1` to be inclusive a = 3 You don't need to generate a range and do membership testing - unless you have a discrete set of values that your a should match - the builtin range in Python 3.x can do efficient lookups for int s as it can