For loop only executes 1 time, though given a range of 5

社会主义新天地 提交于 2019-12-01 14:20:30

your return statement is indented too much, causing the function to return on the first iteration. It needs to be outside of the for block. This code works:

def input_scores():
    scores = []
    y = 1
    for num in range(5):
        score = int(input('Please enter your score for test %d: ' %y))
        while score < 0 or score > 100:
            print ('Error --- all test scores must be between 0 and 100 points')
            score = int(input('Please try again: '))
        scores.append(score)
        y += 1
    return scores

You return from inside the loop. Move return scores one indent left.

You indentation of the code seems whacky. It looks like the return statement is inside the scope of the for loop. So after the first iteration the return statement takes you out of the function completely.

You're returning scores at the end of each loop iteration (so in other words, after the first loop iteration finishes, you return all the scores thereby exiting the function, and the loop).

Change your code to be:

for num in range(5):
    # ...
return scores    # Note the indentation is one tab less than the loop's contents

Others have correctly pointed out that the indentation of your return statement was causing the problem. Also, you might want to try it like this, using len(scores) to control the loop, as @max suggested:

def input_scores(num_tests=5, max=100, min=0):
    scores = []
    while len(scores) < num_tests:
        score = int(input('Please enter your score for test {0}: '.format(len(scores)+1)))
        if score < min or score > max: 
            print ('Error --- all test scores must be between 0 and 100 points.')
        else:
            scores.append(score)
    return scores
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