range

问题 My code currently runs through the first column and finds a certain key word. I want to do another search in the next column with another key word but only for the rows in which the word was found in the first column. I was wondering how I could do this. Here's my code so far: Set aCell = oRange.Find(What:=firstInput, LookIn:=xlValues, _ LookAt:=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, _ MatchCase:=False, SearchFormat:=False) If Not aCell Is Nothing Then Set bCell = aCell

问题 I had expected numpy's arange(start,end) to produce values in the range [start,end]. The following example demonstrates that that's not always true (the final value is larger than end ): import numpy as np start=2e9 end=start+321 step=0.066833171999 x=np.arange(start,end,step=step) print x[-1]>end # Prints "True" print x[-1]-end # Prints 0.00013661384582519531 The error seems far too large to be caused by machine precision (but perhaps I'm thinking about it incorrectly). What's going on? PS:

问题 This is a two part question, I have to make a selection of 2 indexes via a random range of any number of integers in a list. Can't return both if they're both in the same range as well Selection1 = random.randint(0,100) Selection2 = random.randint(0,100) For the sake of this argument, say: Selection1 = 10 Selection2 = 17 And the list would be like so [25, 50, 75, 100] Both would return the index of 0 because they fall between 0-25 So both would fall into the first index range, the problem is

问题 I had a question regarding how I should go about determining overlaps of three ranges in Python without using any existing libraries : For instance if I have three ranges as (10,20)(15,25)(18,30), how should I go about finding overlaps between them ? My answer should be (18,19,20) Any help would be much appreciated. Thanks ! 回答1: The overlap goes from the highest start point to the lowest end point: ranges = [(10,20), (15,25), (18,30)] starts, ends = zip(*ranges) result = range(max(starts),

问题 I am having trouble assigning values from one workbook range to a range in my current workbook. When I assign my range using Range("A1:C1") this code works fine, however when my range is defined using Range(Cells(1,1),Cells(1,3)) the function fails: Sub CopyRange() Dim inputExcel As Excel.Application, BookA As Workbook Path_A = ThisWorkbook.Path & "\Book_A.xlsx" Set inputExcel = New Excel.Application Set BookA = inputExcel.Workbooks.Open(Path_A, ReadOnly:=True) 'THIS WORKS: ThisWorkbook

问题 Right now I'm asking the user for two numbers. I'm trying to print the numbers in between $one and $two assuming $one is smaller than $two. 回答1: Just a simple for loop should do the trick: for($i=$a; $i<=$b; $i++) { echo $i; } 回答2: range gives an array containing all the numbers. You can iterate over that: foreach (range($one, $two) as $number) echo "$number <br>\n"; Or simply use a loop: for ($number = $one; $number <= $two; $number++) echo "$number <br>\n"; 回答3: <?php foreach (range($one,

问题 I was wondering why there is no value property for range object listed in locals window. The value2 is listed there. At the same time I use the Range.Value in the code and it works ok: Set Rng = Range("D6:D9") Set Rng2 = Range("B2:B5") Rng2.Value = Rng.Value Does it mean that excel stores Range values by default in value2? I'm just curious how it works. 回答1: I believe the .Value property is not listed separately in the debug windows as since Office version 2007, an optional argument was added

问题 I've seen lots of threads about date ranges in MySQL but I still don't seem to be able to find an answer for what I'm looking for so any help will be greatly received. I have a MySQL table with 3 columns, date - startTime - finishTime. The date is a MySQL 'date' type field and the start and finish times are both 'time' type fields. Say for example I have an entry in the database as follows, lets call this session 1; date = 2011-06-30, startTime = 09:00:00, finishTime = 11:00:00 If I come to

问题 I have 2 date ranges, start_date1..end_date1 and start_date2..end_date2 , is there an easy "ruby" way to find all the dates that are in both ranges? 回答1: You can use (start_date1..end_date1).to_set & (start_date2..end_date2).to_set here's a fully worked example: require 'date' require 'set' ((Date.today - 3)..(Date.today + 2)).to_set & (Date.today..(Date.today + 5)).to_set if you're counting characters, you can also just do (start_date1..end_date1).to_set & start_date2..end_date2 but I think

问题 I was wondering if there is something similar to the Range but not with integers but with ordered couples (x, y) . I am wondering if there is an easy way to do something like this: ((1,2)..(5,6)).each {|tmp| puts tmp} #=> (1,2) (3,4) (5,6) EDIT : Maybe I was not 100% clear in my question :) I'll try to ask it in a different way. If I had these couples: (3,4) and (5,6) I am looking for a way to help me generate: (3,4), (4,5), (5,6) if I had to exlpain it better : if the couples are (x,y)-> (x0