range

Test if a range intersects another range of numbers

时光怂恿深爱的人放手 提交于 2019-12-19 10:29:39
问题 I have 2 range of numbers: $startTime to $endTime $offerStartTime to $offerEndTime Each of the above variables are integers. I want to see if the range offerStartTime to offerEndTime falls in the range startTime and endTime . For example, if the startTime and endTime range was: 10 to 20, then the following example ranges would return true : offerStartTime: 5, offerEndTime: 11 offerStartTime: 5, offerEndTime: 100 offerStartTime: 10, offerEndTime: 15 offerStartTime: 10, offerEndTime: 100

min max number in text input - Jquery/javascript

僤鯓⒐⒋嵵緔 提交于 2019-12-19 10:27:58
问题 I would like to set a minimum and maximum allowed number to be entered in text input I know I can do this with range input but will it still have the max and min when used in non compatible browsers? if not could you please point me in the right direction, thanks for reading. 回答1: Use jquery validator plugin. It has a nice set of features, and min max validation too. But checking values on server side is a must too. Here is an examples for min and max. 回答2: No; you can never rely on the

How to compare Range<String.Index> and DefaultBidirectionalIndices<String.CharacterView>?

这一生的挚爱 提交于 2019-12-19 09:24:40
问题 This comparison worked in Swift 2 but doesn't anymore in Swift 3: let myStringContainsOnlyOneCharacter = mySting.rangeOfComposedCharacterSequence(at: myString.startIndex) == mySting.characters.indices How do I compare Range and DefaultBidirectionalIndices? 回答1: From SE-0065 – A New Model for Collections and Indices In Swift 2, collection.indices returned a Range<Index> , but because a range is a simple pair of indices and indices can no longer be advanced on their own, Range<Index> is no

range(-8.00, 8.00, 0.05) acting very strange

狂风中的少年 提交于 2019-12-19 08:56:00
问题 Does anyone know why range(-8.00, 8.00, 0.05) seems fail? Array ( [0] => -8 [1] => -7.95 [2] => -7.9 [3] => -7.85 [4] => -7.8 [5] => -7.75 [6] => -7.7 [7] => -7.65 [8] => -7.6 [9] => -7.55 [10] => -7.5 [11] => -7.45 [12] => -7.4 [13] => -7.35 [14] => -7.3 [15] => -7.25 [16] => -7.2 [17] => -7.15 [18] => -7.1 [19] => -7.05 [20] => -7 [21] => -6.95 [22] => -6.9 [23] => -6.85 [24] => -6.8 [25] => -6.75 [26] => -6.7 [27] => -6.65 [28] => -6.6 [29] => -6.55 [30] => -6.5 [31] => -6.45 [32] => -6.4

Python range( ) is not giving me a list [duplicate]

牧云@^-^@ 提交于 2019-12-19 07:50:26
问题 This question already has answers here : Python 3 turn range to a list (8 answers) Closed 2 years ago . Having a beginner issue with Python range. I am trying to generate a list, but when I enter: def RangeTest(n): # list = range(n) return list print(RangeTest(4)) what is printing is range(0,4) rather than [0,1,2,3] What am I missing? Thanks in advance! 回答1: You're using Python 3, where range() returns an "immutable sequence type" instead of a list object (Python 2). You'll want to do: def

Generate integer random numbers from range (0:10^12)

本小妞迷上赌 提交于 2019-12-19 05:10:10
问题 I want to generate 10000 integer random numbers between 0 and 10^12. Usually, the code would look like this: x <- sample(0:1000000000000,10000,replace=T) But I get following error message: Error in 0:1000000000000 : result would be too long a vector Is there a more memory efficient method that doesn't have to put 10^12 integers in a vector just to get a sample of size 10000? If not, is there a way to increase the max size of the vector? I'm working on a 64bit OS with 12GB of free RAM. 回答1:

Oracle record history using as of timestamp within a range

放肆的年华 提交于 2019-12-19 04:06:35
问题 I recently learnt that oracle has a feature which was pretty useful to me - as the designer/implementator didn't care much about data history - I can query the historical state of a record if it's available yet in the oracle cache, like this: select * from ( select * from sometable where some_condition ) as of timestamp sysdate-1 But now I need to check the historical data within a range. Is it possible anyhow, using the cache? 回答1: Yes, like this: SQL> select sal from emp where empno=7369;

Interested in making a PHP script that increments IP address from defined starting address to defined ending address

孤者浪人 提交于 2019-12-19 03:51:08
问题 I know I can do this easily by converting the IP addresses to decimal notation first using PHP built in functions like up2long and long2ip . I just want to be able to do the same using the standard IP address notation as an exercise. The problem I am thinking goes like this: Given an starting IP address, say 192.168.1.100, and an ending IP address, say 201.130.22.10. Make the program that prints all the address numbers in that range (192.168.1.100, 192.168.1.101, … , 201.130.22.9, 201.130.22

How to select random values from a given range

别来无恙 提交于 2019-12-19 03:45:27
问题 I'm trying to create an android application which will generate random series of values (integer numbers in this case) in a given range (but NOT equal between them) and display them in a simple TextView Let's say we have the range R = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13] Each time I press the button "Generate" I want to randomly generate 5 different results Example for each "Generate": 4, 9, 2, 12, 10 5, 1, 6, 8, 13 10, 4, 6, 8, 2 etc... EDIT (works now) Thanks for all the help! public

In Bash, how to convert number list into ranges of numbers?

对着背影说爱祢 提交于 2019-12-19 02:42:10
问题 Currently I have a sorted output of numbers from a command: 18,19,62,161,162,163,165 I would like to condense these number lists into a list of single numbers or ranges of numbers 18-19,62,161-163,165 I thought about trying to sort through the array in bash and read the next number to see if it is +1... I have a PHP function that does essentially the same thing, but I'm having trouble transposing it to Bash: foreach ($missing as $key => $tag) { $next = $missing[$key+1]; if (!isset($first)) {