range

问题 I am having a problem with a particular line of code: ActiveSheet.Range("A" & rowCount & ":" & Mid(alphabet, totHdrLngth, 1) & belowRowCount) Where alphabet is a string containing uppercase letters A to Z. I keep getting the following error: Run-time error '5': Invalid Procedure call or argument I tried creating a String "inRange" and changing the code to this: inRange = "A" & rowCount & ":" & Mid(alphabet, totHdrLngth, 1) & belowRowCount curRange = ActiveSheet.Range(inRange) But that did not

问题 I'm trying to set a range for a jquery datepicker that I have on my form but when I open the form it allows me to select any date. <input class="span2 datepicker" name="tw#local#changeRequest#DeliveryDate" type="text" id="dp1"> <!-- jQuery --> <script type="text/javascript" src="<#=tw.system.model.findManagedFileByPath('jquery-1.7.2.min.js', TWManagedFile.Types.Web).url;#>"></script> <!-- Datepicker Script --> <script type="text/javascript" src="<#=tw.system.model.findManagedFileByPath(

问题 I need to check if a string contains only characters from ranges: 'A'..'Z', 'a'..'z', '0'..'9' , so I wrote this function: function GetValueTrat(aValue: string): string; const number = [0 .. 9]; const letter = ['a' .. 'z', 'A' .. 'Z']; var i: Integer; begin for i := 1 to length(aValue) do begin if (not(StrToInt(aValue[i]) in number)) or (not(aValue[i] in letter)) then raise Exception.Create('Non valido'); end; Result := aValue.Trim; end; but if for example, aValue = 'Hello' the StrToInt

问题 I've written a for_each for tuple s: template <typename Tuple, typename F, size_t begin, size_t end> enable_if_t<begin == end || tuple_size<Tuple>::value < end> for_each(Tuple&, F&&) { } template <typename Tuple, typename F, size_t begin = 0U, size_t end = tuple_size<Tuple>::value> enable_if_t<begin < end && tuple_size<Tuple>::value >= end> for_each(Tuple& t, F&& f) { f(get<begin>(t)); for_each<Tuple, F, begin + 1, end>(t, forward<F>(f)); } [Live Example] But Yakk's answer to this question

问题 I currently have two arrays each of which contain ranges. How would you go about getting the intersection of these two arrays. In other words, I would like to get an array of ranges that only contains the ranges that are contained in both of the two original arrays. I tried .Intersect but that does not work on arrays as I learned. array1: (Range("A1"),Range("B1"),Range("C1")) array2: (Range("A1"),Range("A2"), Range("A3")) Result: (Range("A1")) 回答1: you can use this code. The idea is to merge

问题 What's the most idiomatic way to convert a set of integers into a set of ranges? E.g. given the set {0, 1, 2, 3, 4, 7, 8, 9, 11} I want to get { {0,4}, {7,9}, {11,11} }. Let's say we are converting from std::set<int> into std::vector<std::pair<int, int>> . I treat Ranges as inclusive on both sides, since it's more convenient in my case, but I can work with open-ended ranges too if necessary. I've written the following function, but I feel like reinventing the wheel. Please tell maybe there's

问题 I know that floats can lead to odd behavior in ranges due to their imprecise nature. I would expect the possibility of imprecise values. For instance: [0.1,0.3..1] might give [0.1,0.3,0.5,0.7,0.8999999999999999] instead of [0.1,0.3,0.5,0.7,0.9] In addition to the precision loss, however, I get an extra element: ghci> [0.1,0.3..1] [0.1,0.3,0.5,0.7,0.8999999999999999,1.0999999999999999] This is weird, but explained here. I could work around it like this, I suppose: ghci> [0.1,0.3..0.99] [0.1,0

问题 I know that floats can lead to odd behavior in ranges due to their imprecise nature. I would expect the possibility of imprecise values. For instance: [0.1,0.3..1] might give [0.1,0.3,0.5,0.7,0.8999999999999999] instead of [0.1,0.3,0.5,0.7,0.9] In addition to the precision loss, however, I get an extra element: ghci> [0.1,0.3..1] [0.1,0.3,0.5,0.7,0.8999999999999999,1.0999999999999999] This is weird, but explained here. I could work around it like this, I suppose: ghci> [0.1,0.3..0.99] [0.1,0

问题 In Python, how can I map from a range of values to one concrete value? Basically, I want a dictionary, which I can fill with ranges and index with numbers: rd = rangedict() rd[(0, 10)] = 5 print rd[4] # prints 5 print rd[6] # prints 5 rd[(5, 15)] = 20 print rd[4] # prints 5 print rd[6] # prints 20 回答1: You could use an interval tree pip install intervaltree from intervaltree import Interval, IntervalTree rd = IntervalTree() rd[0:10] = 5 print rd[4] print rd[5] https://pypi.python.org/pypi

问题 In Python, how can I map from a range of values to one concrete value? Basically, I want a dictionary, which I can fill with ranges and index with numbers: rd = rangedict() rd[(0, 10)] = 5 print rd[4] # prints 5 print rd[6] # prints 5 rd[(5, 15)] = 20 print rd[4] # prints 5 print rd[6] # prints 20 回答1: You could use an interval tree pip install intervaltree from intervaltree import Interval, IntervalTree rd = IntervalTree() rd[0:10] = 5 print rd[4] print rd[5] https://pypi.python.org/pypi