range

Find numbers not included in any range

非 Y 不嫁゛ 提交于 2020-01-05 04:49:01
问题 I understand why the difference operator for ranges fails if the result would be two disjoint ranges. But I'm not sure what the workaround is. A simple conceptual example would be if I was keeping a calendar and had a record for each meeting, with a timestamp range field storing the time of the meeting; what would be a simple way to generate a list of times that the person was free on a given day? It seems like a simple, basic thing to do with ranges, but I can't come up with a way to do it

Find numbers not included in any range

你。 提交于 2020-01-05 04:48:28
问题 I understand why the difference operator for ranges fails if the result would be two disjoint ranges. But I'm not sure what the workaround is. A simple conceptual example would be if I was keeping a calendar and had a record for each meeting, with a timestamp range field storing the time of the meeting; what would be a simple way to generate a list of times that the person was free on a given day? It seems like a simple, basic thing to do with ranges, but I can't come up with a way to do it

I want to have range filter in columns (not in templates filters which is ther in jqgrid) . Can anyone help on this

ε祈祈猫儿з 提交于 2020-01-05 04:12:08
问题 as u see in screenshot ,in existing dropdown I want to add an option of inbetween ,where either user can give two values for range selection in textbox or it can be a editabe dropdown. jQGRID DATA - IF user enter 34:09:0;90:08:8 he should get all values which are >=34:09:0 and <90:08:8 in duration filter $(function() { "use strict"; var mydata = [{ id: "1", invdate: "720:0:0", name: "test", note: "note", amount: "200.00", tax: "10.00", total: "210.00" }, { id: "2", invdate: "34:09:0", name:

Checking for a dictionary key which is a range of integers

|▌冷眼眸甩不掉的悲伤 提交于 2020-01-05 02:32:45
问题 I'm building a dictionary of manufacturers. It would look something like this: mfgs = {17491: 'DS', 6543: 'AC'} In this scenario, I need to represent a range of integers that all refer to the same manufacturer. (e.g. 1 - 99 are all manufactured by DC) I've seen that you can create a dictionary key in which a range is represented. mfgs = {17491: 'DS', 6543: 'AC', (1,99): 'DC'} Later on, I will have an integer grabbed from an external file. Depending upon the value encountered, I will log the

Force pandas to interpret (1,2) in column as string and not as range?

馋奶兔 提交于 2020-01-04 14:00:35
问题 I have this weird behaviour in a pandas Dataframe. I am using .apply(single_seats_comma) on a column with the following example content: (1,2) . However, it seems to return it as range(1,3) instead of a string (1,2) . Other rows have more than 2 entries as well, e.g. (30,31,32) . I have a function which splits on , and converts each value in brackets into a new row however with (x,x) it breaks. def single_seats_comma(row): strlist = str(row).split(',') strlist = filter(None, strlist) intlist

Is there a good way to calculate sum of range elements in ruby

泪湿孤枕 提交于 2020-01-04 11:02:15
问题 What is the good way co calculate sum of range? Input 4..10 Output 4 + 5 + 6 + 7 + 8 + 9 + 10 = 49 回答1: You can use Enumerable methods on Range objects, in this case use Enumerable#inject : (4..10).inject(:+) #=> 49 Now, in Ruby 2.4.0 you can use Enumerable#sum (4..10).sum #=> 49 回答2: I assume the ranges whose sums to to be computed are ranges of integers. def range_sum(rng) rng.size * (2 * rng.first + rng.size - 1) / 2 end range_sum(4..10) #=> 49 range_sum(4...10) #=> 39 range_sum(-10..10) #

Python, Bokeh: How to change range of datetime axis

感情迁移 提交于 2020-01-03 19:41:11
问题 I would like to set the range of a datetime axis using a button. However, the command f.x_range = Range1d(start=start_date, end=end_date) doesn't work. When clicking the button nothing happens. I don't get any errors, neither in the terminal windows running the Bokeh server, nor in the console output of my Chrome web browser. You find the entire code below. I'm grateful for any advice. Thanks, Julian # Import libraries from bokeh.io import curdoc from bokeh.models import ColumnDataSource,

Python, Bokeh: How to change range of datetime axis

独自空忆成欢 提交于 2020-01-03 19:41:04
问题 I would like to set the range of a datetime axis using a button. However, the command f.x_range = Range1d(start=start_date, end=end_date) doesn't work. When clicking the button nothing happens. I don't get any errors, neither in the terminal windows running the Bokeh server, nor in the console output of my Chrome web browser. You find the entire code below. I'm grateful for any advice. Thanks, Julian # Import libraries from bokeh.io import curdoc from bokeh.models import ColumnDataSource,

Finding groups of contiguous numbers in a list [duplicate]

余生颓废 提交于 2020-01-03 17:07:19
问题 This question already has answers here : Sequence length encoding using R (6 answers) Closed 6 years ago . This is a duplicate question to this, except for R rather than Python. I'd like to identify groups of contiguous (some people call them continuous) integers in a list, where duplicate entries are treated as existing within the same range. Therefore: myfunc(c(2, 3, 4, 4, 5, 12, 13, 14, 15, 16, 17, 17, 20)) returns: min max 2 5 12 17 20 20 Although any output format would be fine. My

Go: What does range or map return?

强颜欢笑 提交于 2020-01-03 15:32:19
问题 Go has very neat multiple return values paradigm. But It looks like v, ok := map[key] and v, k := range m use different mechanism with same notation. Here is a simple example: func f2() (k, v string) { return "Hello", "World" } func main(){ k := f2() // Doesn't work : multiple-value f2() in single-value context m := map[string]int{"One": 1} // It works v, ok := m["One"] // How it all work? v := m["One"] for k := range m {} } In above example, k := f2() gives error as f2 returns two values,