range

问题 I have a container std::vector and I would like to efficiently split it into sub-ranges with x items in each. The original container is not needed so the items should be moved and not copied into the sub-ranges. I've managed to do the splitting using copying, however I'm unsure how to do it with move assignments? range.insert(range.end(), new_items.begin(), new_items.end()); while(range.size() >= x) { sub_ranges.push_back(std::vector<int>(range.begin(), range.begin() + x)); range = std:

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 24 days ago . my code looks like: list_var = ['rh','temp','tl','Tt','DPD','PAR'] for L in range(1, len(list_var)): for subset in itertools.combinations(list_var, L): f = 'inf ~ {} + C(area)'.format(' * '.join(list(subset))) error 'range' object is not callable jumped up even I changed len(list_var) into a number. Can you

问题 I am trying to get a report where you can select a date range and get some counts. My table is something like this -------------------------------------- RecID|AgentID|date -------------------------------------- 1 |00123 | 05/09/2012 16:28:49 2 |00123 | 05/09/2012 17:28:49 3 |00124 | 05/09/2012 18:28:49 4 |00124 | 06/09/2012 19:28:49 5 |00125 | 06/09/2012 20:28:49 I want something like -------------------------------------- AgentID|05/09/2012|06/09/2012 --------------------------------------

问题 What is wrong with this piece of code for constructing a range that should then serve in a call to substringWithRange ? let range = Range<String.Index>(start: 0, end: 3) The Swift compiler (in Xcode 7.1.1) marks it with this error message: Cannot invoke initializer for type 'Range<Index>' with an argument list of type '(start: Int, end: Int)' 回答1: You need to reference the startIndex of a specific string, then advance: let longString = "Supercalifragilistic" let startIndex = longString

问题 I have found the following code after a lot of research and it does a little of what I want it to do except I don't know how to specify the criteria to reference a range of cells instead of just one single criteria. I am also trying to copy the records and append them to the end of the rows of the matching records in Sheet1. This code only copies the records to Sheet3 so they aren't pasted with their corresponding rows in Sheet1 like I want. Sub copytosheet() Dim sRng As Range, cell As Range

问题 In [1]: range(-100, 100, 20) Out[1]: [-100, -80, -60, -40, -20, 0, 20, 40, 60, 80] What's the easiest way to create Array like above using standard libraries of Java instead of writting own function? There is IntStream.range(-100, 100) , but step is hardcoded to 1. THIS IS NOT A DUPLICATE of Java: Equivalent of Python's range(int, int)?, because I need a step (offset) between numbers and want to use java built-in libraries instead of 3rd-party libraries. I've checked that question and answers

问题 Is it possible to plot two ranges which are far apart each other? I mean, if I have a dataset like [ 1, 2, 3, 1001, 1001, 1003 ], can I draw a plot like this? | 1003 | x 1002 | x 1001 | x 1000 | | ===================== omission | 4 | 3 | x 2 | x 1 | x ------------- 回答1: You may want to check out this link: Gnuplot surprising - Broken axes graph in gnuplot. The author presents three examples of plotting a grqph with a broken x axis. 回答2: Three helpful examples: http://gnuplot-surprising

问题 So I thought I had an OK grasp of VBA but now this error is really bugging me and I can't figure out the problem. Here is an incredibly short subroutine (run from a module): Sub test() Dim lr lr = Sheets(1).Range("a1", Cells(65, 1)) MsgBox lr.Address End Sub For whatever reason this throws up an "application defined/object defined error" can anyone explain? Edit: This also throws up the same error: MsgBox Sheets(1).Range("a1", Cells(65, 1)).Address Edit2: I'm going to change my question a bit

问题 So I thought I had an OK grasp of VBA but now this error is really bugging me and I can't figure out the problem. Here is an incredibly short subroutine (run from a module): Sub test() Dim lr lr = Sheets(1).Range("a1", Cells(65, 1)) MsgBox lr.Address End Sub For whatever reason this throws up an "application defined/object defined error" can anyone explain? Edit: This also throws up the same error: MsgBox Sheets(1).Range("a1", Cells(65, 1)).Address Edit2: I'm going to change my question a bit

问题 I am trying to do a very simple range lookup in MS Access. I basically have two tables: I am looking for a query that will be able to go find the appropriate range of the salary and return the correct tax rate. I started off with this as my base: SELECT IIf(Salary Between 1000 And 2000,10,20) FROM Employees; But I am not making any sort of progress. Any assistance will be greatly appreciated. 回答1: One possible method is to use a correlated subquery, e.g.: select e.*, (select top 1 t.taxrate