ram

I am creating a simple script that outputs the current user logged in, CPU usage for the current system and the available memory? I have managed to get the current user/s logged on but is it possible to get the cpu usage and memory as well? This is my code so far. @echo off for /f "tokens=3 delims=\" %%i in ("%USERPROFILE%") do (set USER=%%i) 2>&1 echo "Logged On User: %USER%" echo. pause To get the cpu usage i have tried this command but it doesn't seem to be working. for /f "skip=1" %p in ('wmic cpu get loadpercentage') do echo %p% Monacraft You could always utilise the systeminfo command,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I need to get the ram memory and CPU usage during execution of a process (the process can run sometimes and over 30 minutes). I am able to get the free RAM but the CPU usage it's not correct, compared with the value from task manager. Am I doing something wrong? Here is my code: class Program { static List <float> AvailableCPU = new List <float> (); static List <float> AvailableRAM = new List <float> (); protected static PerformanceCounter cpuCounter ; protected static PerformanceCounter ramCounter ; static void Main ( string []

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have DDR2 RAM on my windows XP SP 2 Machine, but on WMI explorer (win32_physicalMemory) I am getting Memory Type = 0(Unknown) instead of 21(the code for DDR2). NameSpace is CIMV2. Can you please tell me how to get DDR2 Memory Type From WMI? 回答1: One of the most reliable ways to get such info is reading the SMBIOS Tables, you must look for the Memory Device (Type 17) Structure (this structure describes a single memory device installed on the system), and the Memory Type Field. These are the possible values of this field. 01h Other

I don't know very well about RAM and HDD architecture, or how electronics deals with chunks of memory, but this always triggered my curiosity: Why did we choose to stop at 8 bits for the smallest element in a computer value ? My question may look very dumb, because the answer are obvious, but I'm not very sure... Is it because 2^3 allows it to fit perfectly when addressing memory ? Are electronics especially designed to store chunk of 8 bits ? If yes, why not use wider words ? It is because it divides 32, 64 and 128, so that processor words can be be given several of those words ? Is it just

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I've got one very specific problem with a project that has been haunting me for days now. I have the following Verilog code for a RAM module: module RAM_param(clk, addr, read_write, clear, data_in, data_out); parameter n = 4; parameter w = 8; input clk, read_write, clear; input [n-1:0] addr; input [w-1:0] data_in; output reg [w-1:0] data_out; reg [w-1:0] reg_array [2**n-1:0]; integer i; initial begin for( i = 0; i < 2**n; i = i + 1 ) begin reg_array[i] <= 0; end end always @(negedge(clk)) begin if( read_write == 1 ) reg_array[addr] <= data

选择distributed memory generator和block memorygenerator标准： Dram和bram区别： 补充： 在Xilinx Asynchronous FIFO CORE的使用时，有两种RAM可供选择，Block memory和Distributed memory。 差别在于，前者是使用FPGA中的整块双口RAM资源，而后者则是拼凑起FPGA中的查找表形成。 块RAM是比较大块的RAM，即使用了它的一小部分，那么整个Block RAM就不能再用了。所以，当您要用的RAM是小的，时序要求不高的要用Distributed RAM，节省资源。 FPGA中的资源位置是固定的，例如BRAM就是一列一列分布的，这就可能造成用户逻辑和BRAM之间的route延时比较长。举个最简单的例子，在大规模FPGA中，如果用光所有的BRAM，性能一般会下降，甚至出现route不通的情况，就是这个原因。 原文：https://www.cnblogs.com/tubujia/p/9241714.html

/* GNU linker script for STM32F405 */ /* Specify the memory areas */ MEMORY { FLASH (rx) : ORIGIN = 0x08000000 , LENGTH = 0x100000 /* entire flash, 1 MiB */ FLASH_ISR (rx) : ORIGIN = 0x08000000 , LENGTH = 0x004000 /* sector 0, 16 KiB */ FLASH_TEXT (rx) : ORIGIN = 0x08020000 , LENGTH = 0x080000 /* sectors 5,6,7,8, 4*128KiB = 512 KiB (could increase it more) */ CCMRAM (xrw) : ORIGIN = 0x10000000 , LENGTH = 0x010000 /* 64 KiB */ RAM (xrw) : ORIGIN = 0x20000000 , LENGTH = 0x020000 /* 128 KiB */ } /* top end of the stack */ _estack = ORIGIN(RAM) + LENGTH(RAM); /* RAM extents for the garbage

tmpfs是一种虚拟内存文件系统正如这个定义它最大的特点就是它的存储空间在VM里面，这里提一下VM(virtual memory)，VM是由linux内核里面的vm子系统管理，现在大多数操作系统都采用了虚拟内存管理机制。linux下面VM的大小由RM(Real Memory)和swap组成，RM的大小就是物理内存的大小，而Swap的大小是由你自己决定的。Swap是通过硬盘虚拟出来的内存空间，因此它的读写速度相对RM(Real Memory）要慢许多，我们为什么需要Swap呢？当一个进程申请一定数量的内存时，如内核的vm子系统发现没有足够的RM时，就会把RM里面的一些不常用的数据交换到Swap里面，如果需要重新使用这些数据再把它们从Swap交换到RM里面。如果你有足够大的物理内存，根本不需要划分Swap分区。 通过上面的说明，你该知道tmpfs使用的存储空间VM是什么了吧？前面说过VM由RM+Swap两部分组成，因此tmpfs最大的存储空间可达（The size of RM + The size of Swap）。 但是对于tmpfs本身而言，它并不知道自己使用的空间是RM还是Swap，这一切都是由内核的vm子系统管理的。 重启电脑之后就一切OK了。 测试过程： [root@localhost shm]# df -h [root@localhost shm]# [root