ram

Get total available system memory with PHP on Windows

試著忘記壹切 提交于 2019-12-03 12:10:05
Using PHP, I'd like to get the total memory available to the system (not just the free or used memory). On Linux it's quite straight forward. You can do: $memory = fopen('/proc/meminfo'); and then parse the file. Is anyone aware of an equivalent method for Windows? I'm open to any suggestions. Edit: We have a solution (but StackOverflow won't let me answer my own question): exec( 'systeminfo', $output ); foreach ( $output as $value ) { if ( preg_match( '|Total Physical Memory\:([^$]+)|', $value, $m ) ) { $memory = trim( $m[1] ); } Not the most elegant solution, and it's very slow, but it suits

Limiting node.js's memory usage

人盡茶涼 提交于 2019-12-03 11:36:56
I am trying to limit a node.js application from using to much memory and I've found out about the --max-stack-size & --max_executable_size options that are available within V8 to pass when invoking the file, but how should I combine these and possible other arguments to limit max memory usage to 1GB? Josh https://github.com/joyent/node/wiki/FAQ What is the memory limit on a node process? Currently, by default v8 has a memory limit of 512mb on 32-bit systems, and 1gb on 64-bit systems. The limit can be raised by setting --max_old_space_size to a maximum of ~1gb (32-bit) and ~1.7gb (64-bit), but

Why are 8 and 256 such important numbers in computer sciences?

蹲街弑〆低调 提交于 2019-12-03 11:13:05
问题 I don't know very well about RAM and HDD architecture, or how electronics deals with chunks of memory, but this always triggered my curiosity: Why did we choose to stop at 8 bits for the smallest element in a computer value ? My question may look very dumb, because the answer are obvious, but I'm not very sure... Is it because 2^3 allows it to fit perfectly when addressing memory ? Are electronics especially designed to store chunk of 8 bits ? If yes, why not use wider words ? It is because

Immediately stop MATLAB if RAM usage exceeds a specified amount. Is there a way?

牧云@^-^@ 提交于 2019-12-03 11:07:39
Title says it all. Basically, I am getting tired of having to reset my comp every time I mistakenly make MATLAB use a large amount of RAM for a simulation with many parameters I am creating. Is there a way to make it stop/error out if the RAM usage starts to exceed a specified percentage of my total RAM? I know that I am put try/catches every where I allocate memory, but this is for a program that is already written, and also, for future reference, I want to be able to just set a parameter in the beginning and be done with it. Is there a way? Thanks! Ben Voigt You can set virtual memory quota

[RAM] FPGA的学习笔记——RAM

牧云@^-^@ 提交于 2019-12-03 10:59:22
1、RAM——随机存取存储器, 分为SRAM和DRAM。 SRAM:存和取得速度快,操作简单。然而,成本高,很难做到很大。FPGA的片内存储器,就是一种SRAM,用来存放程序,以及程序执行过程中,产生的中间数据、运算结果等; DRAM:与SRAM特点相反,但速度慢只是相对SRAM慢,其实也算是很快了,比如DDR3,DDR4; 2、Altern的RAM ip核,在生成时,可以选择单还是双口RAM,如果是单端口RAM,那么同一时间只能对同一个地址进行读or写;而如果是双口RAM,那么可以在同一时间读A地址, 写B地址; 3、 来源: https://www.cnblogs.com/zf007/p/11792267.html

RAM嵌入式项目实战开发

不羁岁月 提交于 2019-12-03 07:03:06
对于有嵌入式技术基础的初学者来说,嵌入式项目实战是具有很大吸引力和挑战性的。同时,通过项目实践可以快速提升自己的实战技术,编程能力和项目开发能力。为了记录自己的学习历程,特写此文以回顾。 (一)arm嵌入式实战开发,从嵌入式系统的介绍开始。嵌入式系统以应用为中心、软硬件可裁剪的、适应应用系统对功能、可靠性、成本、体积、功耗等综合性严格要求的专业计算机系统。(集软硬件于一体,软件代码小、高度自动化、响应速度快等特点,特别适合要求实时和多任务的体系)嵌入式系统由嵌入式处理器、相关软硬件、嵌入式操作系统及应用软件系统等组成。 嵌入式系统的几个重要特征: (1)系统内核小。(2)专用性强(3)系统精简(4)高实时性(5)多任务处理 嵌入式系统的体系架构从下往上,一般分为:硬件、驱动程序、操作系统、api接口、应用程序。而对于使用广泛的linux嵌入式系统而言,其软件组成主要有: (1)bootloader:u-boot;(2)linux kernel:可裁剪;(3)根文件系统:yaffs(4)系统应用程序:web server ...;(5)图形界面系统:Qt/E、MinGUI 嵌入式的发展经历了四个阶段: (1)以单片机位核心的可编程控制器形式的系统。(2)以嵌入式cpu为基础、以简单操作系统为核心的嵌入系统。(3)以嵌入式操作系统为标志的嵌入式系统。能运行于不同类型的cpu上,兼容性好

How to get CPU, RAM and Network-Usage of a Java7 App

夙愿已清 提交于 2019-12-03 05:19:10
问题 I found this older article how-to-monitor-the-computers-cpu-memory-and-disk-usage-in-java and wated to ask, if there is something new in java 7. I want to get the current CPU-, RAM- and netzwork-Usage of my App periodically. It has to work for linux (mac) and windows. The data must not be extremely detailed, 3 values would be enough (cpu: 10%, Ram 4%, Network 40%). Would be cool if the data is just for the app and not the whole os-system, however this would work, too. Thank's for help 回答1:

How to see Linux' view of the RAM in order to determinate the fragmentation

烈酒焚心 提交于 2019-12-03 04:41:08
问题 The only program relevant I know of is pmap , but this only prints the memory of one process. I would like to see how the physical memory is occupied and by which processes/library, including the kernel, of the entire physical RAM (as opposed to that from the process' POV with pmap ). Ideally also with a graphical interface. Do you know if there's any such tool? I know about the ambiguity introduced by libraries. If it's the case, it could display a 1-pixel wide line and an arrow to the real

How is RAM able to acess any place in memory at O(1) speed

别来无恙 提交于 2019-12-03 03:50:51
We are taught that the abstraction of the RAM memory is a long array of bytes. And that for the CPU it takes the same amount of time to access any part of it. What is the device that has the ability to access any byte out of the 4 gigabytes (on my computer) in the same time? As this does not seem as a trivial task for me. I have asked colleagues and my professors, but nobody can pinpoint to the how this task can be achieved with simple logic gates, and if it isn't just a tricky combination of logic gates, then what is it? My personal guess is that you could achieve the access of any memory in

Arduino: Is the command Serial.print(“some string text”) occupying SRAM?

你说的曾经没有我的故事 提交于 2019-12-03 03:44:26
I have quite a big Arduino project (in eclipse) going on with a lot of debug messages using the Serial.print("some string text") commands so that I can debug along the way. One thing that I have noticed is that I reach a limit for how many of these I can have in the project. If i put too many, the program halts at very strange places. Ie: often long before my newest addition of a print command is supposed to execute. My project .hex file is around 20k at the moment. The Arduino Uno limits around 30kb right? So it should not be too big. So I feel that the actual problem is probably that maybe