python-2.x

I've tried from mock import Mock import __builtin__ __builtin__.print = Mock() But that raises a syntax error. I've also tried patching it like so @patch('__builtin__.print') def test_something_that_performs_lots_of_prints(self, mock_print): # assert stuff Is there any way to do this? print is a keyword in python 2.x, using it as attribute raises a SyntaxError. You can avoid that by using from __future__ import print_function in the beginning of the file. Note: you can't simply use setattr , because the print function you modified doesn't get invoked unless the print statement is disabled.

When performing pip install pandas on a Digital Ocean 512MB droplet, I get the error UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 41: ordinal not in range(128) . Any ideas what may have caused it? I'm running Ubuntu 12.04 64bit. [Full Error] jfs It looks like gcc being killed due to insufficient memory (see @Blender's comment) exposed a bug in pip. It mixes bytestrings and Unicode while logging that leads to: >>> '\n'.join(['bytestring with non-ascii character ☺', u'unicode']) Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeDecodeError:

Lets say, there is a nested list, like: my_list = [[1, 2, 21], [1, 3], [1, 2]] When the function min() is called on this: min(my_list) The output received is [1, 2] Why and How does it work? What are some use cases of it? Bhargav Rao How are lists and other sequences compared in Python? Lists (and other sequences) in Python are compared lexicographically and not based on any other parameter. Sequence objects may be compared to other objects with the same sequence type. The comparison uses lexicographical ordering: first the first two items are compared, and if they differ this determines the

In my project, I have a bunch of strings that are read in from a file. Most of them, when printed in the command console, exceed 80 characters in length and wrap around, looking ugly. I want to be able to have Python read the string, then test if it is over 75 characters in length. If it is, then split the string up into multiple strings, then print one after the other on a new line. I also want it to be smart, not cutting off full words. i.e. "The quick brown <newline> fox..." instead of "the quick bro<newline>wn fox..." . I've tried modifying similar code that truncates the string after a

I'm doing Zed Shaw's fantastic Learn Python The Hard Way , but an extra question has me stumped: Line 9--10 could be written in one line, how? I've tried some different thoughts, but to no avail. I could move on, but what would the fun in that be? from sys import argv from os.path import exists script, from_file, to_file = argv print "Copying from %s to %s" % (from_file, to_file) # we could do these two on one line too, how? input = open(from_file) indata = input.read() print "The input file is %d bytes long" % len(indata) print "Does the output file exist? %r" % exists(to_file) print "Ready,

I get the following results on my machine: Python 3.2.2 (default, Sep 4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win 32 Type "help", "copyright", "credits" or "license" for more information. >>> import timeit >>> timeit.timeit('factorial(10000)', 'from math import factorial', number=100) 1.9785256226699202 >>> Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win 32 Type "help", "copyright", "credits" or "license" for more information. >>> import timeit >>> timeit.timeit('factorial(10000)', 'from math import factorial', number=100) 9.403801111593792 >>> I

I have found documentation about subprocess.check_output() but I cannot find one with arguments and the documentation is not very in depth. I am using Python 3 (but am trying to run a Python 2 file through Python 3) I am trying to run this command: python py2.py -i test.txt -i is a positional argument for argparse, test.txt is what the -i is, py2.py is the file to run I have tried a lot of (non working) variations including: py2output = subprocess.check_output([str('python py2.py '),'-i', 'test.txt']) py2output = subprocess.check_output([str('python'),'py2.py','-i', test.txt']) abarnert The

I have this: d1 = OrderedDict([('a', '1'), ('b', '2')]) If I do this: d1.update({'c':'3'}) Then I get this: OrderedDict([('a', '1'), ('b', '2'), ('c', '3')]) but I want this: [('c', '3'), ('a', '1'), ('b', '2')] without creating new dictionary. There's no built-in method for doing this in Python 2. If you need this, you need to write a prepend() method/function that operates on the OrderedDict internals with O(1) complexity. For Python 3.2 and later, you should use the move_to_end method. The method accepts a last argument which indicates whether the element will be moved to the bottom ( last