How can I denote unused function arguments?

问题

When "deconstructing" a tuple, I can use _ to denote tuple elements I'm not interested in, e.g.

>>> a,_,_ = (1,2,3)
>>> a
1

Using Python 2.x, how can I express the same with function arguments? I tried to use underscores:

>>> def f(a,_,_): return a
...
  File "<stdin>", line 1
SyntaxError: duplicate argument '_' in function definition

I also tried to just omit the argument altogether:

>>> def f(a,,): return a
  File "<stdin>", line 1
    def f(a,,): return a
        ^
SyntaxError: invalid syntax

Is there another way to achieve the same?

回答1:

Here's what I do with unused arguments:

def f(a, *unused):
    return a

回答2:

A funny way I just thought of is to delete the variable:

def f(foo, unused1, unused2, unused3):
    del unused1, unused2, unused3
    return foo

This has numerous advantages:

The unused variable can still be used when calling the function both as a positional argument and as a keyword argument.
If you start to use it later, you can't since it's deleted, so there is less risk of mistakes.
It's standard python syntax.
PyCharm does the right thing!
PyLint won't complain and using del is the solution recommended in the PyLint manual.

回答3:

The underscore is used for things we don't care about and the * in *args denotes a list of arguments. Therefore, we can use *_ to denote a list of things we don't care about:

def foo(bar, *_):
    return bar

It even passes PyCharm's checks.

回答4:

You can use '_' as prefix, so that pylint will ignore these parameters:

def f(a, _b, _c):

回答5:

If you have both args and keyword arg you should use

def f(a, *args, **kwargs):
    return a

回答6:

I think the accepted answer is bad, but it can still work, if you use what I should call "Perl way" of dealing with arguments (I don't know Perl really, but I quit trying to learn it after seeing the sub syntax, with manual argument unpacking):

Your function has 3 arguments - this is what it gets called with (Duck typing, remember?). So you get:

def funfun(a, b, c):
    return b * 2

2 unused parameters. But now, enter improved larsmans' approach:

def funfun(*args):
    return args[1] * 2

And there go the warnings...

However, I still enjoy more the boxed's way:

def funfun(a, b, c):
    del a, c
    return b * 2

It keeps the self-documenting quality of parameter names. They're a feature, not a bug.

But, the language itself doesn't force you there - you could also go the other way around, and just let all your function have the signature (*args, **kwargs), and do the argument parsing manually every time. Imagine the level of control that gives you. And no more exceptions when being called in a deprecated way after changing your "signature" (argument count and meaning). This is something worth considering ;)

来源：https://stackoverflow.com/questions/10025680/how-can-i-denote-unused-function-arguments

标签

python

python-2.x