process

Does Process.Start terminate the child program when the parent terminates?

情到浓时终转凉″ 提交于 2021-01-27 08:01:28
问题 Do programs started with Process.Start(exepath); terminate when the parent process ends? I'm getting some strange behavior with it and believe that could be the issue. 回答1: The short answer to your question is No, they don't. You will have to kill them explicitly.If you want to kill the process that you have started then you can use the handle returned by process.start. Something like this Process p = Process.Start("someprocess"); if (p != null) p.Kill(); 回答2: On Windows child processes

Does Process.Start terminate the child program when the parent terminates?

跟風遠走 提交于 2021-01-27 07:59:22
问题 Do programs started with Process.Start(exepath); terminate when the parent process ends? I'm getting some strange behavior with it and believe that could be the issue. 回答1: The short answer to your question is No, they don't. You will have to kill them explicitly.If you want to kill the process that you have started then you can use the handle returned by process.start. Something like this Process p = Process.Start("someprocess"); if (p != null) p.Kill(); 回答2: On Windows child processes

Does Process.Start terminate the child program when the parent terminates?

天涯浪子 提交于 2021-01-27 07:58:13
问题 Do programs started with Process.Start(exepath); terminate when the parent process ends? I'm getting some strange behavior with it and believe that could be the issue. 回答1: The short answer to your question is No, they don't. You will have to kill them explicitly.If you want to kill the process that you have started then you can use the handle returned by process.start. Something like this Process p = Process.Start("someprocess"); if (p != null) p.Kill(); 回答2: On Windows child processes

Multiple instances or processes of visual studio code in task manager for single application window

自作多情 提交于 2021-01-27 06:09:36
问题 I'm using Visual Studio Code. I'm facing a performance issue on my machine. I went to task manager and saw that there are several instances of Code.exe in the process tab even though there is only one window of Visual Studio Code running/active on my PC. I can see that in all there are eight instances of Code.exe . Although, I can see that all eight instances are taking RAM memory in the range of few KBs to a maximum of 55 MB. So one thing was sure that these few processes are not eating up

Multiple instances or processes of visual studio code in task manager for single application window

拜拜、爱过 提交于 2021-01-27 06:08:31
问题 I'm using Visual Studio Code. I'm facing a performance issue on my machine. I went to task manager and saw that there are several instances of Code.exe in the process tab even though there is only one window of Visual Studio Code running/active on my PC. I can see that in all there are eight instances of Code.exe . Although, I can see that all eight instances are taking RAM memory in the range of few KBs to a maximum of 55 MB. So one thing was sure that these few processes are not eating up

Multiple instances or processes of visual studio code in task manager for single application window

只谈情不闲聊 提交于 2021-01-27 06:08:12
问题 I'm using Visual Studio Code. I'm facing a performance issue on my machine. I went to task manager and saw that there are several instances of Code.exe in the process tab even though there is only one window of Visual Studio Code running/active on my PC. I can see that in all there are eight instances of Code.exe . Although, I can see that all eight instances are taking RAM memory in the range of few KBs to a maximum of 55 MB. So one thing was sure that these few processes are not eating up

DeadLock Issues in Process.StandardOutput.ReadToEnd();

╄→гoц情女王★ 提交于 2021-01-26 08:00:27
问题 I read that this portion of code can cause deadlock: Process p = new Process(); p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.FileName = "Write500Lines.exe"; p.Start(); p.WaitForExit(); string output = p.StandardOutput.ReadToEnd(); Because A deadlock condition can result if the parent process calls p.WaitForExit before p.StandardOutput.ReadToEnd and the child process writes enough text to fill the redirected stream. The parent process would wait

DeadLock Issues in Process.StandardOutput.ReadToEnd();

社会主义新天地 提交于 2021-01-26 08:00:11
问题 I read that this portion of code can cause deadlock: Process p = new Process(); p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.FileName = "Write500Lines.exe"; p.Start(); p.WaitForExit(); string output = p.StandardOutput.ReadToEnd(); Because A deadlock condition can result if the parent process calls p.WaitForExit before p.StandardOutput.ReadToEnd and the child process writes enough text to fill the redirected stream. The parent process would wait

Using fork(), how can I make child process run always first?

我的未来我决定 提交于 2021-01-15 06:38:42
问题 Child and parent process execution is parallel and which starts first depends on OS scheduling. But what can be done to start child always before the parent? This is the pseudo code for my problem, int start_test() { pid_t pid; pid = fork(); if(pid == 0) { execv("XXX", XXX); } else if(pid > 0) { pid = fork(); if(pid == 0) { execv("XXX", XXX); } else { // Do something } } return 0; } int main() { start_test(); return 0; } I wants to make first execv execute first than parent creates new

Using fork(), how can I make child process run always first?

扶醉桌前 提交于 2021-01-15 06:36:26
问题 Child and parent process execution is parallel and which starts first depends on OS scheduling. But what can be done to start child always before the parent? This is the pseudo code for my problem, int start_test() { pid_t pid; pid = fork(); if(pid == 0) { execv("XXX", XXX); } else if(pid > 0) { pid = fork(); if(pid == 0) { execv("XXX", XXX); } else { // Do something } } return 0; } int main() { start_test(); return 0; } I wants to make first execv execute first than parent creates new