process

问题 If I have 4 processes that I want to pipe: process1 | process2 | process3 | process4 do I have to make 3 individual pipes likes this int pipe1[2]; int pipe2[2]; int pipe3[2]; or can I somehow recycle pipe names like in this pseudocode: int pipe1[2]; // we use ONLY two pipe names: pipe1 int pipe2[2]; // and pipe2 pipe(pipe1); // getting 2 file descriptors here pipe(pipe2); // and 2 here for process=1 to 4 if (process==3) // getting 2 new file descriptors for pipe(pipe1); // process3|process4

问题 If I have 4 processes that I want to pipe: process1 | process2 | process3 | process4 do I have to make 3 individual pipes likes this int pipe1[2]; int pipe2[2]; int pipe3[2]; or can I somehow recycle pipe names like in this pseudocode: int pipe1[2]; // we use ONLY two pipe names: pipe1 int pipe2[2]; // and pipe2 pipe(pipe1); // getting 2 file descriptors here pipe(pipe2); // and 2 here for process=1 to 4 if (process==3) // getting 2 new file descriptors for pipe(pipe1); // process3|process4

问题 If I have 4 processes that I want to pipe: process1 | process2 | process3 | process4 do I have to make 3 individual pipes likes this int pipe1[2]; int pipe2[2]; int pipe3[2]; or can I somehow recycle pipe names like in this pseudocode: int pipe1[2]; // we use ONLY two pipe names: pipe1 int pipe2[2]; // and pipe2 pipe(pipe1); // getting 2 file descriptors here pipe(pipe2); // and 2 here for process=1 to 4 if (process==3) // getting 2 new file descriptors for pipe(pipe1); // process3|process4

问题 Problem with doing process in Swift 3, It's not working, I click and nothing is happening. let open = Process() open.launchPath = "/usr/bin/openssl" open.arguments = ["openssl enc -aes-256-cbc -d -in \"" + existing.stringValue + "\" -out \"" + new.stringValue + "/" + name.stringValue + "\""] open.launch() open.waitUntilExit() How do I create a process with arguments in Swift? 回答1: With this function, you can pass the arguments as a string. func shell(at: String, _ args: String) { let task =

问题 I closed the terminal window by mistake and I don't know the PID of the running Play process. How to find it? Or, where is the RUNNING_PID file? I am using Play 2.4.6 and running in non-production mode ( activator run ). 回答1: When using dev mode ( activator run ), no RUNNING_PID file is generated. The process won't detach and will be killed when the terminal is closed. By default the RUNNING_PID file is written to ./target/universal/stage/RUNNING_PID (inside the project's root directory) when

问题 I have following code to read and redict the output of gawk to a textfile (instead of doing this with shell-execute and using > ): var processStartInfo = new ProcessStartInfo { FileName = "gawk.exe", Arguments = $@"-F ""{separator}"" -f ""{scriptFullFileName}"" ""{inputFullFileName}""", UseShellExecute = false, WorkingDirectory = workingDirectory, RedirectStandardOutput = true, CreateNoWindow = true }; using (var process = Process.Start(processStartInfo)) { using (var streamReader = process

问题 I am working on Bryant and O'Hallaron's Computer Systems, A Programmer's Perspective . Exercise 8.16 asks for the output of a program like (I changed it because they use a header file you can download on their website): #include <stdio.h> #include <stdlib.h> #include <sys/types.h> #include <sys/wait.h> #include <errno.h> #include <unistd.h> #include <string.h> int counter = 1; int main() { if (fork() == 0){ counter--; exit(0); } else{ Wait(NULL); printf("counter = %d\n", ++counter); } exit(0)

问题 In my node script, I am waiting for the user to press enter at some point: console.log("Press enter to continue..."); await new Promise(function(resolve, reject) { process.stdin.once("data", function(data) { resolve(); }); }); The script runs fine, and continues only after the user has pressed enter. But at the end of the execution, the process does not terminate. Instead, it seems to be just pending for user input (i.e., a newline is printed every time I press enter). I'm pretty sure that

问题 I have a program where I write from several child processes to a pipe, and then attempt to read all the messages written to each process, from each pipe, and print them to the screen. With the following code (specifically, the while loop using the read system call to store the messages into buffer buf ), my program will hang and not exit, nor print all of the messages sent to the different processes. for (i = 0; i < MAXP; i++) { if(id == i) { while(read(pfds[i][0], buf, sizeof(buf)) > 0)

问题 I have a program where I write from several child processes to a pipe, and then attempt to read all the messages written to each process, from each pipe, and print them to the screen. With the following code (specifically, the while loop using the read system call to store the messages into buffer buf ), my program will hang and not exit, nor print all of the messages sent to the different processes. for (i = 0; i < MAXP; i++) { if(id == i) { while(read(pfds[i][0], buf, sizeof(buf)) > 0)