postfix-notation

Converting a Postfix Notation to an ExpressionTree

由 二次信任 提交于 2019-12-12 01:48:21
问题 As it is said in the title I am trying to create a code which converts a postfix notation to an expression tree. Here you can check the constructor : public byte type; // 0 : operator, 1: operand (a number) public char operator; // One of '+', '-', '*', '/' public int operand; // A number ExpressionTreeNode(byte type){this.type = type; left=right=null;} and Here is my code : public static ExpressionTreeNode Postfix2ExpressionTree(String postfixExpr){ Stack s = new Stack<Object>();

Postfix evaluation using stacks and C

由 ≡放荡痞女 提交于 2019-12-11 18:06:00
问题 I was on here a while a go with a similar problem but I think with the wrong question. To give a bit of background, I a tasked with creating a C program to solve a postfix expression in the form 8 7 - 9 * = What I think my problem is, is that my prof gave as some incorrect stack code. I say this because I am constantly getting the stack overflow (lol) error and my stack is nowhere near full. If it helps I'm using visual studio 2005. Here's my code: #include <stdio.h> ` #include <stdlib.h>

Understanding Postfix-expression Evaluation in Java code using a stack

由 一笑奈何 提交于 2019-12-11 13:36:09
问题 I was given a snippet of code to decipher, explain and offer any recommendations for improvement. I was told it works and we can't run the code to test it. I pretty much understand it but just need to run it by someone to make sure what I do understand about it is correct and please get any help with explaining what I don't understand.I have been doing a ton of research and still have some questions. The code is implementing used to read a postfix expression that only uses multiplication and

infix to postfix program not working [duplicate]

由 牧云@^-^@ 提交于 2019-12-11 07:55:06
问题 This question already has answers here : Handling parenthesis while converting infix expressions to postfix expressions (2 answers) Closed 2 years ago . I am supposed to write a program to convert infix to postfix. It works for some, but other times not correctly. Especially on infix expressions containing parantheses. Could anyone give me a clue why this is wrong? For example, the infix expression ( ( 5 + 5 * ( 6 - 2 ) + 4 ^ 2 ) * 8 ) returns 5562-*42^++8*((2 . import java.io.*; import java

Convert from an infix expression to postfix (C++) using Stacks

由 旧巷老猫 提交于 2019-12-10 02:25:25
问题 My lecturer gave me an assignment to create a program to convert and infix expression to postfix using Stacks. I've made the stack classes and some functions to read the infix expression. But this one function, called convertToPostfix(char * const inFix, char * const postFix) which is responsible to convert the inFix expression in the array inFix to the post fix expression in the array postFix using stacks, is not doing what it suppose to do. Can you guys help me out and tell me what I'm

Postfix to infix with unary/binary operators

由 梦想的初衷 提交于 2019-12-08 06:29:58
问题 I am trying to make a converter from postfix to infix notation and need some help. There is already a question about infix-to-postfix conversion, which gives an example I am failing to convert back. (Note: a minus sign is missing there!) The following is the output of my converter, where the 1st "column" is postfix input, the 2nd is my infix output, and the 3rd is what I probably should get(?): 2 - = - 2 =? - 2 true 1 + 2 + = + 1 + 2 =? + 1 + 2 true 1 + 2 + + = + (+ 1 + 2) =? + 1 + + 2 false

How can I accept negative values in Postfix and Infix Notation?

由 ＊爱你＆永不变心＊ 提交于 2019-12-08 05:38:41
问题 I've written a few methods for a calculator. One, which evaluates an entered Postfix expression and another, which transfers an entered infix expression into a postfix expression. Both these methods allow multi digit integers aswell as floats for the number input types. Now for my question: I want to include the negative input in both these methods e.g. Infix: "3 * (-1)". However I'm kinda lacking an idea on how to implement this problem. Maybe someone can give me ideas or code examples. I'm

How can I accept negative values in Postfix and Infix Notation?

由 十年热恋 提交于 2019-12-07 03:27:25
I've written a few methods for a calculator. One, which evaluates an entered Postfix expression and another, which transfers an entered infix expression into a postfix expression. Both these methods allow multi digit integers aswell as floats for the number input types. Now for my question: I want to include the negative input in both these methods e.g. Infix: "3 * (-1)". However I'm kinda lacking an idea on how to implement this problem. Maybe someone can give me ideas or code examples. I'm including both methods below. A few simple methods are used in them which aren't shown here, but most

How to put postfix expressions in a binary tree?

由 ☆樱花仙子☆ 提交于 2019-12-07 00:21:39
问题 so i have a binary tree and a postfix expression "6 2 * 3 /" what is the algo to put it in a tree? like, [/] / \ [*] [3] / \ [6] [2] 回答1: To construct a tree from the expression, pretend you are evaluating it directly but construct trees instead of calculating numbers. (This trick works for many more things than postfix expressions.) Algorithm: Have a stack to store intermediate values (which are trees), and examine each token from left to right: If it is a number, turn it into a leaf node

Scala Postfix operator warning contradicts with Scaladoc

由 落爺英雄遲暮 提交于 2019-12-06 12:29:17
问题 My code: val exitStatus = url #> outfile ! scala.sys.process: new URL("http://www.scala-lang.org/") #> new File("scala-lang.html") ! Warning: postfix operator ! should be enabled [warn] by making the implicit value scala.language.postfixOps visible. [warn] This can be achieved by adding the import clause 'import scala.language.postfixOps' [warn] or by setting the compiler option -language:postfixOps. [warn] See the Scaladoc for value scala.language.postfixOps for a discussion [warn] why the
订阅 postfix-notation