parentheses

What are the parentheses for at the end of Python method names?

谁说胖子不能爱 提交于 2019-11-30 15:53:24
问题 I'm a beginner to Python and programming in general. Right now, I'm having trouble understanding the function of empty parentheses at the end of method names, built-in or user-created. For example, if I write: print "This string will now be uppercase".upper() ...why is there an empty pair of parentheses after "upper?" Does it do anything? Is there a situation in which one would put something in there? Thanks! 回答1: the parentheses indicate that you want to call the method upper() returns the

SQL Parentheses use in an OR clause

两盒软妹~` 提交于 2019-11-30 11:18:40
Was wondering whether anyone would know why do we use the parentheses in this SQL: So, the format goes as follows: Name,location and department of the service of the employees whose name starts with A or B. (A rough translation from French). I answered the following way: SELECT service.nom_serv, localite.ville, localite.departemen FROM service, localite, employe WHERE service.code_loc=localite.code_loc AND employe.service=service.code_serv AND ((employe.nom LIKE 'A%') OR (employe.nom LIKE 'B%')) Basically, where the last AND is concerned for the WHERE, couldn't I simply do without the

How can I add parentheses as the highest level of precedence in a simple grammar?

别等时光非礼了梦想. 提交于 2019-11-30 09:34:18
问题 I'm trying to add 2 things to my grammar: Unary minus sign, i.e. '-', and Parentheses Here's my grammar so far: <comp> ::= <expr> | <comp> <op0> <expr> <expr> ::= <term> | <expr> <op1> <term> <term> ::= <darg> | <term> <op2> <darg> <darg> ::= <digit> | <darg> <digit> <digit> ::= 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 <op0> ::= > | < | =< | => | = <op1> ::= + | - <op2> ::= * | / I've tried everything and can't figure this out. How can I make the unary minus sign be at the highest level of

How can I do Java annotation like @name(“Luke”) with no attribute inside parenthesis?

感情迁移 提交于 2019-11-30 07:51:22
How I can do custom Java annotation with no attribute name inside parentheses? I don't want this: @annotation_name(att=valor) . I just want like in Servlets, i.e: @WebServlet("/main") Define the annotation with an attribute named value , then the attribute name can be omitted: @interface CustomAnnotation { String value(); } This can be used like so: @CustomAnnotation("/main") // ... You specify an attribute named value: public @interface MyAnnotation { String value(); } This doesn't have to be the only attribute if they have default values: public @interface MyAnnotation { String value(); int

Single-element parethesized expressions/tuples vs common use of parentheses

半城伤御伤魂 提交于 2019-11-30 06:01:30
问题 Sorry if this is trivial - I am so new to swift, actually I have only looked at the language guide+reference for a few minutes. As far as I understand a parenthesized expression like (2,3) is used to construct a tuple, and (2) is a single-element tuple of type (Int) . But then what happens with common use of parentheses like (2+4) in expression (2+4)*5 ? Is this still a tuple of type (Int) multiplied by an Int ? 回答1: From Types in the Swift book: If there is only one element inside the

ReverseParentheses - Codefights

江枫思渺然 提交于 2019-11-30 05:30:51
I'm having a really tough time solving this problem with JavaScript You are given a string s that consists of English letters, punctuation marks, whitespace characters and brackets. It is guaranteed that the brackets in s form a regular bracket sequence. Your task is to reverse the strings in each pair of matching parenthesis, starting from the innermost one. Example For string "s = a(bc)de" the output should be reverseParentheses(s) = "acbde". Input/Output [time limit] 4000ms (js) [input] string s A string consisting of English letters, punctuation marks, whitespace characters and brackets.

C# Regex match anything inside Parentheses

北慕城南 提交于 2019-11-30 04:51:56
I want to match anything inside parentheses but the result must exclude the parentheses as well. Examples: Initialize(P90W) Brake(45X) Result: 990W 45X note results without the Parentheses. I've been trying to make this work but to no avail I tried a few variations but I know it's a simple thing I'm missing and I don't want to go using Replace to achieve it. var item = "Brake(45X)" Regex searchTerm = new Regex(@"\((.*)\)"); var value = (searchTerm.Match(item).Groups.Count > 0) ? searchTerm.Match(item).Groups[0].Value : string.Empty; Some people accuse me of using zero width assertions all the

parentheses in Python Conditionals

北慕城南 提交于 2019-11-30 04:33:11
I have a simple question regarding the use of parentheses in Python conditional statements. The following two snippets works just the same but I wonder if this is only true because of it's simplicity; >>> import os, socket >>> if ((socket.gethostname() == "bristle") or (socket.gethostname() == "rete")): ... DEBUG = False ... else: ... DEBUG = True ... >>> DEBUG and now without parentheses >>> import os, socket >>> if socket.gethostname() == "bristle" or socket.gethostname() == "rete": ... DEBUG = False ... else: ... DEBUG = True ... >>> DEBUG Could anyone help shed some light on this? Are

VBA What's the underlying difference between call Sub or Function with or without parentheses

淺唱寂寞╮ 提交于 2019-11-29 23:39:22
问题 I had an issue with passing an Array to a Sub By Reference, but the Array actually not get modified. I managed to fix that , but I want to know why. Here is the example. Private Function fCountArray(ByRef arrayVar As Variant) arrayVar(0) = 333 End Function Sub Test1() Dim changedArr As Variant Dim notChangedArr As Variant ' create 2 quick array changedArr = Array(1, 2, 33, 56, 76, 89, 10) notChangedArr = Array(1, 2, 33, 56, 76, 89, 10) 'intest = Array(3, 1, 2) fCountArray (notChangedArr)

Quickest way to change a pair of parenthesis to brackets in vim

♀尐吖头ヾ 提交于 2019-11-29 17:00:31
问题 I am new to vim and in the process of discovering tons of interesting things that one can using this powerful editor. One particular thing that I need to do very frequently is to change a pair of parenthesis in the text to square-brackets (for example to change ( (a+b+c) ) to [ (a+b+c) ] ) or vice-verso. I now do this by manually changing the two characters ( and ) to [ and ] . However, when there is a lot of text in between the parenthesis, it could be difficult to locate the pair of opening