parentheses

I'm writing this code in VBScript, which I haven't used before in my life. I wrote this: Replace (strContent, st, arr (k,i), 1) And it gives me a "Can't Use Parentheses When Calling a Sub" problem. Can anyone please help? I've tried searching online but nothing helped. Thank you! Found the answer thanks to Panayot Karabakalov. We tried using a Call and doing it without parentheses: Replace strContent, st, arr (k,i), 1 But nothing worked. The solution eventually was: strContent = Replace (strContent, st, arr (k,i), 1) Thank you everyone for the quick and helpful responses! You guys never let us

It must be something very basic and obvious, because I just can't find the answer through google or on here... What difference do the parentheses make in Python when I call methods? Example code with pygame and parentheses: import pygame import sys pygame.init() screen = pygame.display.set_mode((640, 480)) running = True while running: for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() sys.exit() pygame.display.update() When I click the cross of the window, it closes with sys.exit() being the last thing called in the Traceback. When I change it to this: import pygame

I was looking at some code a friend sent me, and he said: "It compiles, but doesn't work". I saw that he used the functions without the parentheses, something like this: void foo(){ cout<< "Hello world\n"; } int main(){ foo; //function without parentheses return 0; } The first I said was "use parentheses, you have to". And then I tested that code - it does compile, but when executed doesn't work (no "Hello world" shown). So, why does it compile (no warning at all from the compiler GCC 4.7 ), but doesn't work? It surely warns if you set the warning level high enough. A function name evaluates

In perl, parentheses are used for overriding precedence (as in most programming languages) as well as for creating lists. How can I tell if a particular pair of parens will be treated as a grouping construct or a one-element list? For example, I'm pretty sure this is a scalar and not a one-element list: (1 + 1) But what about more complex expressions? Is there an easy way to tell? Three key principles are useful here: Context is king. The evaluation of your example (1 + 1) depends on the context. $x = (1 + 1); # Scalar context. $x will equal 2. Parentheses do nothing here. @y = (1 + 1); # List

I am confused with some of the examples that I have come across with C++11 lambdas. For eg: #include <iostream> #include <string> using namespace std; int main() { cout << []()->string{return "Hello World 1!";}() << endl; []{cout << "Hello World 2!" << endl;}(); string result = [](const string& str)->string {return "Hello World " + str;}("2!"); cout << "Result: " << result << endl; result = [](const string& str){return "Hello World " + str;}("3!"); cout << "Result: " << result << endl; string s; [&s](){s = "Hello World 4!";}; // does not work cout << s << endl; [&s](){s = "Hello World 4!";}();