onclick

Android : Shared preferences inside tabhost not working

六月ゝ 毕业季﹏ 提交于 2019-12-12 05:57:06
问题 I have a tabhost with three activities and I want to save the pressed state of the buttons of each activity So now How can I save the pressed state of each button in all three child activities so that when I move from one activity to the other the button pressed state will be reflected on moving back. first activity -> all 4 buttons pressed -> go to 2nd activity -> come back to first activity -> all buttons in first activity should be in pressed state When I go to second child tab and come to

onclick replace php included file

点点圈 提交于 2019-12-12 05:48:10
问题 I am not sure if what I am trying to do is possible but here it is. I have a header, inside that header is a php include for "login.php" On "login.php" is a link that takes the user to "forgot.php". What I would like to do is, instead of the user being taken to "forgot.php" is to just refresh the page with "login.php" include replaced with "forgot.php" or do some sort of content switch out, sort of like using an Iframe. I dont want to bring the user to a new page, I just want to switch out

Javascript function will not activate onClick

柔情痞子 提交于 2019-12-12 05:26:58
问题 In my page head: <script> function formula() { document.forms["inquire"]["search"].value.scrollIntoView(); } </script> In my page body: <div id="nav"> <form id="inquire" name="inquire" onSubmit="return false;"> Search or inquire here: <input type="text" id="search" name="search" value="<?php search($_GET['search']) ?>" autocomplete="off"/> <input type="button" name="btnSearch" id="btnSearch" onClick="formula();"/> </form> </div> What I want to happen here is that, when btnSearch is clicked,

Javascript random number in function onclick

老子叫甜甜 提交于 2019-12-12 05:16:52
问题 Need some help. with the below javascript. On inserting a row I need the random number t to generate a new number on each click (insert). I have to send each row to the processor as an array so that needs to be a unique number on each insert. I can get it to work the first time but of course it's just generating on load and not each click. Been at it for hours trying to figure it out... but no dice. Any help? <script type="text/javascript"> $(document).ready(function(){ var i=1; var t = Math

Javascript change input values onclick to the value on the same row which the button was clicked

时光毁灭记忆、已成空白 提交于 2019-12-12 04:59:23
问题 let's say if I select floating rate on the third row and I click on the equal sign button. The rest of the value of all the other row will change its value to floating rate. I want to apply tis function to all the other rows too. Javascript: <script type="text/javascript"> $(document).ready(function() { $('.equal').on('click', function() { $('.dropDown').val('Floating Rate'); }) }); </script> Table: <td> <select class="dropDown" style="width:150px" name="rate_value_1"> <option value="<?php

How to change mouse over to onclick

天大地大妈咪最大 提交于 2019-12-12 04:59:03
问题 How can I change this code instead of dragging you just click two elements to exchange the position of the two elements? I wanted to exchange two tiles through clicking one then another but instead, in here you need to drag the first tile to bring it to the other then they will exchange. function onPuzzleClick(e){ if(e.layerX || e.layerX == 0){ _mouse.x = e.layerX - _canvas.offsetLeft; _mouse.y = e.layerY - _canvas.offsetTop; } else if(e.offsetX || e.offsetX == 0){ _mouse.x = e.offsetX -

Don't submit unless a certain radio button is checked

我的未来我决定 提交于 2019-12-12 04:57:30
问题 I am trying to make a Jquery simple function and just want to submit a form only when the radio button value is "1". If not don't submit the form and change some things as I am showing in the code below. At the moment if the value of the radio button is "1" or "0" the form is submitting anyway. <script> $(document).ready(function() { $('.result').hide(); $('input.prettycheckbox').prettyCheckable({}); $('input.submit').on('click', function(e) { e.preventDefault(); $('input.prettycheckbox')

Jquery on event not working for Dynamic elements

社会主义新天地 提交于 2019-12-12 04:42:29
问题 $(".spanCont:first .collection_shop").on("click",function(){ var current_item = $(this); $.ajax({ url: "ajax/abc.php", type: "POST", dataType: 'html', data: {collection_id: current_item.attr("value")}, beforeSend: function(xhr) { current_item.replaceWith("<div id='temp_div'></div>"); } }).done(function(data){ $(".spanCont:first .span-2, .spanCont:first input").remove(); $("#temp_div").replaceWith(data); }); }); This code should work for all static and dynamic click of elements with class

Issue with highlighting page elements using mouseover and mouseout event listeners

核能气质少年 提交于 2019-12-12 04:39:47
问题 I am creating a Firefox extension that gets some information about an element on a webpage (say, the element's id attribute), upon clicking said element. I also would like to implement a feature in which hovering over the element will highlight it. There are some existing solutions that essentially already do this. It seems that these existing solutions (such the "Select element with mouse" feature in Firefox's "Inspector" tool) essentially make use of two event listeners: A mouseover

Changing an image while click is held

馋奶兔 提交于 2019-12-12 04:39:01
问题 I am looking to change an image of a button from when a click is held, then change back upon click release. I currently have a flat image, and I want it to change to one with an inner-shadow to make it look like a button press, but change back to the original flat image when the mouse click is released. I tried onmouseup but I think i'm using it incorrectly. I want the "item" and "item2" to hold their image when clicked, and that works correctly. However I want the "item3" to change back upon