numbers

How to remove numbers from a String in Swift [closed]

由 半世苍凉 提交于 2019-12-18 15:47:41
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . I have a String like "75003 Paris, France" or "Syracuse, NY 13205, USA" . I want to use same code to remove all those numbers out of those Strings. How can I achieve that? 回答1: You can do it with the NSCharacterSet var str = "75003 Paris, France" var stringWithoutDigit = (str

random number from -9 to 9 in C++

由 廉价感情. 提交于 2019-12-18 14:47:08
问题 just wondering, if I have the following code: int randomNum = rand() % 18 + (-9); will this create a random number from -9 to 9? 回答1: No, it won't. You're looking for: int randomNum = rand() % 19 + (-9); There are 19 distinct integers between -9 and +9 (including both), but rand() % 18 only gives 18 possibilities. This is why you need to use rand() % 19 . 回答2: Your code returns number between (0-9 and 17-9) = (-9 and 8). For your information rand() % N; returns number between 0 and N-1 :) The

How to round *down* integers in Java?

由 て烟熏妆下的殇ゞ 提交于 2019-12-18 14:05:33
问题 I'd like to round integers down to their nearest 1000 in Java. So for example: 13,623 rounds to 13,000 18,999 rounds to 18,000 etc 回答1: Simply divide by 1000 to lose the digits that are not interesting to you, and multiply by 1000: i = i/1000 * 1000 Or, you can also try: i = i - (i % 1000) 回答2: You could divide the number by 1000, apply Math.floor, multiply by 1000 and cast back to integer. 回答3: int i = Math.floorDiv(-13623, 1000) * 1000 //i => -14000 The above code will always round down

栈——表达式求值

由 丶灬走出姿态 提交于 2019-12-18 13:45:21
通过栈来实现表达式的计算 主要问题在于：运算符的优先级关系处理 算法思想： 　　1.建立并初始化 运算符栈OPTR栈 和 数值OPND栈，将表达式起始符"#"压入OPTR栈； 　　2.按序获取表达式数组中每个字符串str(假定表达式是合法有效的)： 　　　　->如果str表示数值: 　　　　　　直接压入OPND栈，进入下一次for循环； 　　　　->如果str表示运算符：　　　　 　　　　　　取出OPTR的栈顶运算符 top，比较str和top之间的优先级关系： 　　　　　　->如果优先级关系相等： 　　　　　　　　->如果top和str的均为"#": 　　　　　　　　　　整个表达式求值完毕 return OPND栈顶元素; 　　　　　　　　->如果栈顶元素是左括号"("，读入str为")": 　　　　　　　　　　那么将OPTR栈顶弹出，进入下一次for循环； 　　　　　　->如果top优先级大于str： 　　　　　　　　弹出OPND栈顶元素2个(b, a)，弹出OPTR栈顶元素(top)，然后计算:result = a top b; 　　　　　　　　将result压入OPND栈， 将当前数组的遍历下标值减一 ，进入下一次for循环； 　　　　　　->如果top优先级小于str： 　　　　　　　　将str压入OPTR栈；　　　　　　 运算符之间的优先级比较： top\str + -

Extended Precision Floating Point Library C/C++

由 和自甴很熟 提交于 2019-12-18 12:36:34
问题 I am looking for an extended precision floating point library with the following features: fixed data type size (i.e. the extended precision float takes a fixed amount of memory) no initialization required for variables specify size of both mantissa and exponent C/C++ interface support for really large floats > 10^10000 The closest I could found is the HPA library by Ivano Primi. The only problem with this library is that I cannot extend the exponent (it is fixed with 15 bits). It allows me

Why are two different numbers equal in JavaScript?

由 风流意气都作罢 提交于 2019-12-18 12:05:49
问题 I've been messing around with a JavaScript console, when I suddenly decided to try this: 0x100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 == 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF Surprisingly, they're equal: Why does it happen? They're clearly different numbers (even the 0xFFFF...FFFF is one digit shorter) If I add a F

How does C#'s random number generator work?

由 蓝咒 提交于 2019-12-18 11:44:17
问题 I was just wondering how the random number generator in C# works. I was also curious how I could make a program that generates random WHOLE INTEGER numbers from 1-100. 回答1: I was just wondering how the random number generator in C# works. That's implementation-specific, but the wikipedia entry for pseudo-random number generators should give you some ideas. I was also curious how I could make a program that generates random WHOLE INTEGER numbers from 1-100. You can use Random.Next(int, int):

Convert Java Number to BigDecimal : best way

由 て烟熏妆下的殇ゞ 提交于 2019-12-18 11:38:19
问题 I am looking for the best way to convert a Number to a BigDecimal. Is this good enough? Number number; BigDecimal big = new BigDecimal(number.toString()); Can we lose precision with the toString() method ? 回答1: This is fine, remember that using the constructor of BigDecimal to declare a value can be dangerous when it's not of type String. Consider the below... BigDecimal valDouble = new BigDecimal(0.35); System.out.println(valDouble); This will not print 0.35, it will infact be... 0

Checking if string is numeric in dart

由 岁酱吖の 提交于 2019-12-18 11:32:04
问题 I need to find out if a string is numeric in dart. It needs to return true on any valid number type in dart. So far, my solution is bool isNumeric(String str) { try{ var value = double.parse(str); } on FormatException { return false; } finally { return true; } } Is there a native way to do this? If not, is there a better way to do it? 回答1: This can be simpliefied a bit void main(args) { print(isNumeric(null)); print(isNumeric('')); print(isNumeric('x')); print(isNumeric('123x')); print

Rounding up to the second decimal place [duplicate]

由 只谈情不闲聊 提交于 2019-12-18 11:00:06
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: PHP Round function - round up to 2 dp? What my problem is: When i use ceil(3.6451895227869); i get like 4 but i want 3.65 Can you help me out? UPDATE Please remember: This should always round to ceil like while rounding 3.6333333333333 it must not be 3.63 but should be 3.64 回答1: Check out http://www.php.net/manual/en/function.round.php <?php echo round(3.6451895227869, 2); ?> EDIT Try using this custom function
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