nested-loops

Like we all know, it's not that easy to break from a nested loop out of an outer loop without either: a goto ( Example code. ) another condition check in the outer loop ( Example code. ) putting both loops in an extra function and returning instead of break ing ( Example code. ) Though, you gotta admit, all of those are kinda clumsy. Especially the function version lacks because of the missing context where the loops are called, as you'd need to pass everything you need in the loops as parameters. Additionally, the second one gets worse for each nested loop. So, I personally, still consider

For a group project I am trying to create a template engine for PHP for the people less experienced with the language can use tags like {name} in their HTML and the PHP will replace that tag with a predefined variable from an array. As well as supporting loops. This is well beyond the expectations of the project, but as I have experience with PHP I thought it would be a good challenge to keep me busy! My main questions are, how do I do the loop part of the parser and is this the best way to implement such a system. Before you just recommend an existing template system, I would prefer to create

The number of statically nested blocks in Python is limited to 20. That is, nesting 19 for loops will be fine (although excessively time consuming; O(n^19) is insane), but nesting 20 will fail with: SyntaxError: too many statically nested blocks What is the underlying reason for having such a limit? Is there a way to increase the limit? This limit not only applies to for loops, but to all other control flow blocks as well. The limit for the number of nested control flow blocks is defined inside of code.h with a constant named CO_MAXBLOCKS : #define CO_MAXBLOCKS 20 /* Max static block nesting

This question already has an answer here: How to break out of multiple loops in Python? 29 answers I use the following method to break the double loop in Python. for word1 in buf1: find = False for word2 in buf2: ... if res == res1: print "BINGO " + word1 + ":" + word2 find = True if find: break Is there a better way to break the double loop? Probably not what you are hoping for, but usually you would want to have a break after setting find to True for word1 in buf1: find = False for word2 in buf2: ... if res == res1: print "BINGO " + word1 + ":" + word2 find = True break # <-- break here too

You are given an unsorted array of n integers, and you would like to find if there are any duplicates in the array (i.e. any integer appearing more than once). Describe an algorithm (implemented with two nested loops) to do this. The question that I am stuck at is: How can you limit the input data to achieve a better Big O complexity? Describe an algorithm for handling this limited data to find if there are any duplicates. What is the Big O complexity? Your help will be greatly appreciated. This is not related to my coursework, assignment or coursework and such. It's from the previous year

I have a component with the following render: render() { const { policy } = this.props; let deployment = policy.Deployment; let value = policy.value; let policyLegend = deployment.policyLegend; let policyObj = this.valueToPolicy(policyLegend, value); console.log(policy); console.log(deployment); console.log(value); console.log(policyLegend); console.log(policyObj); return( <div> <Form onSubmit={ (event) => this.handleSubmit(event, this.props) }> { policyLegend.map(function(policy) { <div> <h3 key={ policy.id }>{ policy.displayName }</h3> { policy.values.map(value => { return( <Form.Field key={

I have a nested loop to create all combinations in a set of conjugated verbs. The aim to to get all possible combinations of verb, person and tense, e.g. [['to be', 'first person singular', 'future'],['to be', 'second person singular', 'future'], ...] . for v in verbs: for p in persons: for t in tenses: return [v, p, t] Is there a way of reducing the nesting, perhaps using itertools ? for v, p, t in itertools.product(verbs, persons, tenses): ... You can use itertools.product for this task: Cartesian product of input iterables. Equivalent to nested for-loops in a generator expression. For

I am trying to come up with a way to generate all possible unique strings from an alphabet of 20 characters where the order within the string doesn't matter, and the length of the string can vary. So, for instance, for a string of length 3, the possible strings would be AAA , AAB , AAC , etc., but would not include BAA or CAA . I figured out a way using itertools.product() , but it is very computationally expensive. The easiest way to do this is simply using nested for loops. For instance, to generate all strings of length four: alphabet = ["A","C","D","E","F","G","H","I","K","L", "M","N","P",

I'm trying to write a program to evenly (or as close to possible) distribute points about the surface of a sphere. I'm trying to achieve this by placing N points randomly about a unit sphere, and then running multiple steps where the points repel each other. The problem is in the loop over the points array. The code below loops over each point, and then the loop inside that, again loops over each point and calculates the repulsive force between each point pair. for point in points.iter_mut() { point.movement = Quaternion::identity(); for neighbour in &points { if neighbour.id == point.id {