nested-loops

nested loop with file1.csv and file2.csv in jmeter

独自空忆成欢 提交于 2019-12-01 04:58:30
问题 I am using Apache JMeter and I need to run function call in 2 nested loops driven by csv datafiles. There is similar Q&A at How to implement nested loop in jmeter? but it's not based on datafiles. I have 2 files: long.csv : 1 2 3 ... 100.000 and short.csv : a b c I need to run nested loop test with data from those files foreach x from long.csv foreach y from short.cvs call(x,y) and I want the calls look like this: call(1,a) call(1,b) call(1,c) call(2,a) call(2,b) call(2,c) call(3,a) call(3,b)

Parallelize these nested for loops in python

▼魔方 西西 提交于 2019-12-01 04:46:52
I have a multidimensional array ( result ) that should be filled by some nested loops. Function fun() is a complex and time-consuming function. I want to fill my array elements in a parallel manner, so I can use all my system's processing power. Here's the code: import numpy as np def fun(x, y, z): # time-consuming computation... # ... return output dim1 = 10 dim2 = 20 dim3 = 30 result = np.zeros([dim1, dim2, dim3]) for i in xrange(dim1): for j in xrange(dim2): for k in xrange(dim3): result[i, j, k] = fun(i, j, k) My question is that "Can I parallelize this code or not? if yes, How?" I'm using

g++ optimization breaks for loops

家住魔仙堡 提交于 2019-12-01 04:00:46
A few days ago, I encountered what I believe to be a bug in g++ 5.3 concerning the nesting of for loops at higher -OX optimization levels. (Been experiencing it specifically for -O2 and -O3 ). The issue is that if you have two nested for loops, that have some internal sum to keep track of total iterations, once this sum exceeds its maximum value it prevents the outer loop from terminating. The smallest code set that I have been able to replicate this with is: int main(){ int sum = 0; // Value of 100 million. (2047483648 less than int32 max.) int maxInner = 100000000; int maxOuter = 30; //

Time complexity for dependant nested for loop?

对着背影说爱祢 提交于 2019-12-01 03:10:12
问题 Can you explain me how to find time complexity for this? sum=0; for(k=1;k<=n;k*=2) for(j=1;j<=k;j++) sum++; So, i know the outer loop has time complexity of O(logn), but since the iterations of the inner loop depends on the value of the outer loop, the complexity of this algorithm is not O(nlogn). The book says it is O(n). I really dont understand how it is O(n)...Can someone please explain it... I'll be really grateful if u could go into the details btw :D A mathematical solution would help

g++ optimization breaks for loops

时光怂恿深爱的人放手 提交于 2019-12-01 00:26:04
问题 A few days ago, I encountered what I believe to be a bug in g++ 5.3 concerning the nesting of for loops at higher -OX optimization levels. (Been experiencing it specifically for -O2 and -O3 ). The issue is that if you have two nested for loops, that have some internal sum to keep track of total iterations, once this sum exceeds its maximum value it prevents the outer loop from terminating. The smallest code set that I have been able to replicate this with is: int main(){ int sum = 0; // Value

R - multiple nested loops

本小妞迷上赌 提交于 2019-11-30 23:01:20
I am trying to write a nested loop code to simulate 10 columns of data in a data frame with 101 rows. The first row of data has been assigned as starting values. Each column should be different as my matrix r is generated from random normals; however, the resulting values in each column are exactly the same. To give some context for the looping indices: tmax=100; ncol(pop_sims) = 12 (so a total of 10 iterations, 3-12); ncol(r) = 10 for (i in 1:tmax){ for (j in 3:ncol(pop_sims)){ for(k in 1:ncol(r)){ if (pop_sims[i,j]*exp(r[i,k]) <2) { pop_sims[i+1,j]<- 0} else { pop_sims[i+1,j] <- pop_sims[i,j

R - multiple nested loops

安稳与你 提交于 2019-11-30 17:35:16
问题 I am trying to write a nested loop code to simulate 10 columns of data in a data frame with 101 rows. The first row of data has been assigned as starting values. Each column should be different as my matrix r is generated from random normals; however, the resulting values in each column are exactly the same. To give some context for the looping indices: tmax=100; ncol(pop_sims) = 12 (so a total of 10 iterations, 3-12); ncol(r) = 10 for (i in 1:tmax){ for (j in 3:ncol(pop_sims)){ for(k in 1

Javascript - scope of nested for loop index

痞子三分冷 提交于 2019-11-30 17:15:44
问题 I remember variables are function scoped in Javascript. But, how is the behavior if I redefine the local variable in a loop. One common use case is nested loops. In the below code, if I change j to i, the outer for loop terminates after one iteration as the value of i in outer scope is same as inner for loop. Since I use var, I was expecting (similar to other language) it is redefined inside inner fo loop. Does this mean in JS, there is no way to redeclare and use local variable within

Creating a Christmas Tree using for loops

点点圈 提交于 2019-11-30 14:15:58
I am trying to make a christmas tree using for loops and nested for loops. For me to do that I need to be able to make a pyramids with *. I have tried countless times and I am having problems making one. Here is my code: for(int i=1;i<=10;i++){ for(int j=10;j>i;j--){ System.out.println(" "); } for(int k=1;k<=i;k++){ System.out.print("*"); } for(int l=10;l<=1;l++){ for(int h=1;h<=10;h++){ System.out.print(" "); } } System.out.println(); } What I am trying to do is: * *** ***** ******* Sourav Kanta Try this much simpler code: public class ChristmasTree { public static void main(String[] args) {

Reuse nested loops without copy and paste

流过昼夜 提交于 2019-11-30 14:05:37
Suppose I've this nested loop for (int a=1; a<MAX_A; ++a) for (int b=1; b<MAX_B; ++b) for (int c=1; c<MAX_C; ++c) { do_something(a, b ,c); } and I reuse this loop in various part of my code, changing the function do_something . It's quite boring to rewrite every time the first three lines. In python for example I would created a generator to return an iterator (1, 1, 1), (1, 1, 2), ... or something like itertools.product . In c++ the only solution I've in mind is to define a macro. Something better?e Use templates: template<typename Func> inline void do_something_loop(Func f) { for (int a=1; a