nested-lists

How to create a nested-list of categories in Laravel?

别来无恙 提交于 2019-12-03 07:46:37
How can I create a nested list of categories in Laravel? I want to create something like this: --- Php ------ Laravel --------- Version ------------ V 5.7 --- Python ------ Django --- Ruby .......... My table's fields are: id | name | parent_id If I have to add another column like depth, please tell me. I am using this following code, but I think it is not the best solution for creating nested-list of categories besides, I can not pass this function to my view. function rec($id) { $model = Category::find($id); foreach ($model->children as $chield) rec($chield->id); return $model->all(); }

How to create multiple levels of indentation in Javadoc?

泪湿孤枕 提交于 2019-12-03 06:26:20
问题 Suppose, that as part of documenting your code (Javadoc) you want to indicate that the relationships between elements using deep indentation. How can I create a nested list as: some element some other element yet some other element 回答1: <ul> <li>Element</li> <ul> <li>Subelement...</li> You can pretty freely use HTML inside javadoc comments. Update: Because it came up, I tried <ul> <li>one</li> <ul> <li>one point one</li> </ul> </ul> and get one one point one I agree proper nesting is better.

Linq on a nested List - select all Id's

左心房为你撑大大i 提交于 2019-12-03 05:25:52
I have a nested list, something like this: List<Hotel> Hotels; public class Hotel { List<RoomType> RoomType; } public class RoomType { Room Room; } public class Room { int RoomId; } It's a little convoluted, sorry couldn't think of a better mockup model. The Idea is that I have many hotels, each hotels has many room types, and assume each room type has exactly one room object. Now from Hotels list, I just want to select all RoomId 's.. I am stuck here, while trying to nest all list.. right now, I am trying this: //cant do this some invalid error int[] AllRoomIds = Hotels.selectMany(x => x

Print list of lists in separate lines

拟墨画扇 提交于 2019-12-02 19:48:34
I have a list of lists: a = [[1, 3, 4], [2, 5, 7]] I want the output in the following format: 1 3 4 2 5 7 I have tried it the following way , but the outputs are not in the desired way: for i in a: for j in i: print(j, sep=' ') Outputs: 1 3 4 2 5 7 While changing the print call to use end instead: for i in a: for j in i: print(j, end = ' ') Outputs: 1 3 4 2 5 7 Any ideas? Iterate through every sub-list in your original list and unpack it in the print call with * : a = [[1, 3, 4], [2, 5, 7]] for s in a: print(*s) The separation is by default set to ' ' so there's no need to explicitly provide

removing duplicates from two 2 dimensional list

﹥>﹥吖頭↗ 提交于 2019-12-02 15:04:59
问题 i searched for a solution to remove deplicates from two 2d list in python i couldn't find so here my question: i have two lists, for example [[1,2],[3,5],[4,4],[5,7]] [[1,3],[4,4],[3,5],[3,5],[5,6]] Expected result: [[1,2],[1,3],[5,7],[5,6]] I want to remove list inside on the lists that match EXACTLY the values of the other list. my script: def filter2dim(firstarray, secondarray): unique = [] for i in range(len(firstarray)): temp=firstarray[i] for j in range(len(secondarray)): if(temp ==

Creating a separate Counter() object and Pandas DataFrame for each list within a list of lists

白昼怎懂夜的黑 提交于 2019-12-02 14:23:33
问题 All the other answers I could find specifically referred to aggregating across all of the nested lists within a list of lists, where as I'm looking to aggregate separately for each list. I currently have a list of lists: master_list = [[a,a,b,b,b,c,c,c], [d,d,d,a,a,a,c,c,c], [c,c,c,a,a,f,f,f]] I want to return a dictionary or Counter() objects for each list with a loop: counter1 = {'a': 2, 'b': 3, 'c': 3} counter2 = {'d': 3, 'a': 3, 'c': 3} counter3 = {'c': 3, 'a': 2, 'f': 3} Currently, I'm

Appending to a nested list

我的未来我决定 提交于 2019-12-02 10:51:37
I'm using a nested list to look up values in a dictionary I created. I then want to append the values found to a list. The problem I don't know how to code is how to I keep the values appended within the same nested list structure? Here's the code where the last line I'm appending the values to an empty list. #Creating a dictionary of FID: LU_Codes from external txt file import sys, arcpy, string, csv text_file = open("H:\SWAT\NC\FID_Whole.txt", "r") Lines = text_file.readlines() text_file.close() FID_LU = map(string.split, Lines) #print FID_LU FID_GC_dict = dict(FID_LU) Neighbors_file = open(

removing duplicates from two 2 dimensional list

倾然丶 夕夏残阳落幕 提交于 2019-12-02 08:44:38
i searched for a solution to remove deplicates from two 2d list in python i couldn't find so here my question: i have two lists, for example [[1,2],[3,5],[4,4],[5,7]] [[1,3],[4,4],[3,5],[3,5],[5,6]] Expected result: [[1,2],[1,3],[5,7],[5,6]] I want to remove list inside on the lists that match EXACTLY the values of the other list. my script: def filter2dim(firstarray, secondarray): unique = [] for i in range(len(firstarray)): temp=firstarray[i] for j in range(len(secondarray)): if(temp == secondarray[j]): break elif(j==(len(secondarray)-1)): unique.append(temp) for i in range(len(secondarray))

How to display a sequence of numbers in column-major order?

旧街凉风 提交于 2019-12-02 07:04:48
问题 Program description: Find all the prime numbers between 1 and 4,027 and print them in a table which "reads down", using as few rows as possible, and using as few sheets of paper as possible. (This is because I have to print them out on paper to turn it in.) All numbers should be right-justified in their column. The height of the columns should all be the same, except for perhaps the last column, which might have a few blank entries towards its bottom row. The plan for my first function is to

Extracting strings from nested lists in Python [duplicate]

南笙酒味 提交于 2019-12-02 05:43:18
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Flatten (an irregular) list of lists in Python I'm trying to use the nltk library in python, and more specifically the wordnet corpus, to extract all the words in a broad semantic category like 'animal'. I've managed to write a function that goes down through all the categories and extracts the words in them, but what I end up with is a huge jumble of lists within lists. The lists aren't of any predictable