mysqli

问题 $studentId = 57004542323382 $companyOfferId = 7 $sql = 'INSERT INTO studentPlacement (companyOfferId, studentId) VALUES (?, ?)'; if ($stmt = $db->prepare($sql)) { $stmt->bind_param("ii", $offerId, $studentId); $stmt->execute(); $insertId = $stmt->insert_id; $stmt->close(); } My problem lies with the studentId variable. Its value is too long to be stored as a standard integer so it must be stored as a bigint. When binding the parameter as an integer it simply enters '1' as the studentId value.

问题 I have a basic site with a host and as of recent the mysqli_fetch_all command has appeared to have stopped working as I receive the message: Fatal error: Call to undefined function mysqli_fetch_all() in file at line where function is used I rolled back the files on the server to a set that I know work and yet I run into the same issue even though the page is running PHP5.4+ . I cannot figure out why this has suddenly stopped working. Offline, using XAMPP, the mysqli_fetch_all command works

问题 I have a basic site with a host and as of recent the mysqli_fetch_all command has appeared to have stopped working as I receive the message: Fatal error: Call to undefined function mysqli_fetch_all() in file at line where function is used I rolled back the files on the server to a set that I know work and yet I run into the same issue even though the page is running PHP5.4+ . I cannot figure out why this has suddenly stopped working. Offline, using XAMPP, the mysqli_fetch_all command works

问题 I need help to figure out why this is error <?php class data { private $db; public $nama, $password, $alamat, $jk, $kodepos, $alasan, $email; function _construct($db) { $this->db = $db; } public function input_data() { $query = "INSERT INTO data (nama, password, alamat, jeniskelamin, kodepos, alasan, email)VALUES('$this->nama', '$this->password', '$this->alamat', '$this->jk', '$this->kodepos', '$this->alasan', '$this->email')"; $insert = mysqli_query($this->db, $query); return $insert; }

问题 I need help to figure out why this is error <?php class data { private $db; public $nama, $password, $alamat, $jk, $kodepos, $alasan, $email; function _construct($db) { $this->db = $db; } public function input_data() { $query = "INSERT INTO data (nama, password, alamat, jeniskelamin, kodepos, alasan, email)VALUES('$this->nama', '$this->password', '$this->alamat', '$this->jk', '$this->kodepos', '$this->alasan', '$this->email')"; $insert = mysqli_query($this->db, $query); return $insert; }

问题 I keep getting this error from my code Warning: mysqli_query() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Warning: mysqli_error() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Error querying database the first time Here is my code: $query = "SELECT * FROM reservations, rooms, room_type"; $query .= " WHERE reservations.room_id=rooms.room_id"; $query

问题 I keep getting this error from my code Warning: mysqli_query() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Warning: mysqli_error() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Error querying database the first time Here is my code: $query = "SELECT * FROM reservations, rooms, room_type"; $query .= " WHERE reservations.room_id=rooms.room_id"; $query

问题 I keep getting this error from my code Warning: mysqli_query() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Warning: mysqli_error() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\citizenssuites\site\pages\reservations.php on line 26 Error querying database the first time Here is my code: $query = "SELECT * FROM reservations, rooms, room_type"; $query .= " WHERE reservations.room_id=rooms.room_id"; $query

问题 I have this code for selecting fname from the latest record on the user table. $mysqli = new mysqli(HOST, USER, PASSWORD, DATABASE); $sdt=$mysqli->('SELECT fname FROM user ORDER BY id DESC LIMIT 1'); $sdt->bind_result($code); $sdt->fetch(); echo $code ; I used prepared statement with bind_param earlier, but for now in the above code for first time I want to use prepared statement without binding parameters and I do not know how to select from table without using bind_param() . How to do that?

问题 I have this code for selecting fname from the latest record on the user table. $mysqli = new mysqli(HOST, USER, PASSWORD, DATABASE); $sdt=$mysqli->('SELECT fname FROM user ORDER BY id DESC LIMIT 1'); $sdt->bind_result($code); $sdt->fetch(); echo $code ; I used prepared statement with bind_param earlier, but for now in the above code for first time I want to use prepared statement without binding parameters and I do not know how to select from table without using bind_param() . How to do that?