mysql-error-1064

Why does MySQL report a syntax error on FULL OUTER JOIN?

僤鯓⒐⒋嵵緔 提交于 2019-11-26 08:51:13
问题 SELECT airline, airports.icao_code, continent, country, province, city, website FROM airlines FULL OUTER JOIN airports ON airlines.iaco_code = airports.iaco_code FULL OUTER JOIN cities ON airports.city_id = cities.city_id FULL OUTER JOIN provinces ON cities.province_id = provinces.province_id FULL OUTER JOIN countries ON cities.country_id = countries.country_id FULL OUTER JOIN continents ON countries.continent_id = continents.continent_id It says that You have an error in your SQL syntax;

PHP file cannot enter some part of code

ⅰ亾dé卋堺 提交于 2019-11-26 02:38:54
问题 Here is a function in my php file, which is used to serve the request of my android app. function checkin($DB, $TechID, $ClientID, $SiteID){ $dbConnection = mysql_connect($DB[\'server\'], $DB[\'loginName\'], $DB[\'password\']); if(!$dbConnection){ die(\'Error! \' . mysql_error()); } mysql_select_db($DB[\'database\'], $dbConnection); $file2 = \"C:/wamp/www/file2.txt\"; $data2 = \"ClientID:\".$ClientID.\" TechID:\".$TechID.\" SiteID:\".$SiteID; file_put_contents($file2, $data2); $result1 =

Warning about SSL connection when connecting to MySQL database

隐身守侯 提交于 2019-11-26 02:35:44
With the two classes below, I've tried connect to a MySQL database. However, I always get this error: Wed Dec 09 22:46:52 CET 2015 WARN: Establishing SSL connection without server's identity verification is not recommended. According to MySQL 5.5.45+, 5.6.26+ and 5.7.6+ requirements SSL connection must be established by default if explicit option isn't set. For compliance with existing applications not using SSL the verifyServerCertificate property is set to 'false'. You need either to explicitly disable SSL by setting useSSL=false, or set useSSL=true and provide truststore for server

Error creating table: You have an error in your SQL syntax near 'order( order_id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id ' at line 1 [duplicate]

余生颓废 提交于 2019-11-26 02:25:25
问题 This question already has an answer here : Syntax error due to using a reserved word as a table or column name in MySQL (1 answer) Closed 5 years ago . I am trying to create 2 tables in the same MySQL database with a PHP-script: table \'user\' with primary key \'user_id\' and table \'order\' with primary key \'order_id\' and foreign key \'user_id\' from the \'user\' table (1 to many relationship). Table user creates successfully without problems: $sql=\"CREATE TABLE user( user_id INT UNSIGNED

Warning about SSL connection when connecting to MySQL database

那年仲夏 提交于 2019-11-26 02:03:55
问题 With the two classes below, I\'ve tried connect to a MySQL database. However, I always get this error: Wed Dec 09 22:46:52 CET 2015 WARN: Establishing SSL connection without server\'s identity verification is not recommended. According to MySQL 5.5.45+, 5.6.26+ and 5.7.6+ requirements SSL connection must be established by default if explicit option isn\'t set. For compliance with existing applications not using SSL the verifyServerCertificate property is set to \'false\'. You need either to

How to delete from multiple tables in MySQL?

谁都会走 提交于 2019-11-26 01:25:27
问题 I am trying to delete from a few tables at once. I\'ve done a bit of research, and came up with this DELETE FROM `pets` p, `pets_activities` pa WHERE p.`order` > :order AND p.`pet_id` = :pet_id AND pa.`id` = p.`pet_id` However, I am getting this error Uncaught Database_Exception [ 1064 ]: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near \'p, pets_activities pa... I\'ve never done a cross table delete before,

How can I fix MySQL error #1064?

强颜欢笑 提交于 2019-11-25 21:52:51
问题 When issuing a command to MySQL, I\'m getting error #1064 \"syntax error\". What does it mean? How can I fix it? 回答1: TL;DR Error #1064 means that MySQL can't understand your command. To fix it: Read the error message. It tells you exactly where in your command MySQL got confused. Examine your command. If you use a programming language to create your command, use echo , console.log() , or its equivalent to show the entire command so you can see it. Check the manual. By comparing against what