问题
I am trying to create 2 tables in the same MySQL database with a PHP-script: table \'user\' with primary key \'user_id\' and table \'order\' with primary key \'order_id\' and foreign key \'user_id\' from the \'user\' table (1 to many relationship).
Table user creates successfully without problems:
$sql=\"CREATE TABLE user(
user_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
type ENUM(\'member\',\'admin\') NOT NULL,
username VARCHAR(30) NOT NULL,
email VARCHAR(80) NOT NULL,
pass VARBINARY(32) NOT NULL,
first_name VARCHAR(40) NOT NULL,
last_name VARCHAR(40) NOT NULL,
date_expires DATE NOT NULL,
date_created TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
date_modified TIMESTAMP NOT NULL DEFAULT \'0000-00-00 00:00:00\',
PRIMARY KEY (user_id),
UNIQUE (username),
UNIQUE (email)
)ENGINE=InnoDB DEFAULT CHARSET=utf8\";
However, I am not able to create table order:
$sql=\"CREATE TABLE order(
order_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
user_id INT UNSIGNED NOT NULL,
transaction_id VARCHAR(19) NOT NULL,
payment_status VARCHAR(15) NOT NULL,
payment_amount DECIMAL(6,2) UNSIGNED NOT NULL,
payment_date_time TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (order_id),
FOREIGN KEY (user_id) REFERENCES user (user_id)
)ENGINE=InnoDB DEFAULT CHARSET=utf8\";
I get the following error:
Error creating table: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near \'order( order_id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id \' at line 1
Already checked the syntax and cannot find the mistake. Could you please advise what went wrong? Thanks a lot.
回答1:
You need to escape reserved words like order
with backticks
CREATE TABLE `order` ( ...
or better use another name instead.
回答2:
order is keyword used by mysql like (select from tbl_name order by id ASC) so for escaping from using keywords you have to use quotes `` to avoid my sql error
so your query should by
$sql="CREATE TABLE `order` (
order_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
user_id INT UNSIGNED NOT NULL,
transaction_id VARCHAR(19) NOT NULL,
payment_status VARCHAR(15) NOT NULL,
payment_amount DECIMAL(6,2) UNSIGNED NOT NULL,
payment_date_time TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (order_id),
FOREIGN KEY (user_id) REFERENCES user (user_id)
)ENGINE=InnoDB DEFAULT CHARSET=utf8";
enjoy :D
来源:https://stackoverflow.com/questions/19318866/error-creating-table-you-have-an-error-in-your-sql-syntax-near-order-order-id