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How can I find the minimum cut on a graph using a maximum flow algorithm?

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问题 I need to find the minimum cut on a graph. I've been reading about flow networks, but all I can find are maximum flow algorithms such as Ford-Fulkerson, push-relabel, etc. Given the max flow-min cut theorem, is it possible to use one of those algorithms to find the minimum cut on a graph using a maximum flow algorithm? How? The best information I have found so far is that if I find "saturated" edges i.e. edges where flow equals capacity, those edges correspond to the minimum cut. Is that true

Is this minimalist HTML5 markup valid?

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问题 <!DOCTYPE html> <meta charset="utf-8"> <body> Hello, world! SOURCE FOR CODE If so, besides removing "Hello, world!" is there any tag that's able to be removed and it still be valid, and how do you know it's still valid? 回答1: It's not valid. To check it you can run it in W3C Validator The error is: Element head is missing a required instance of child element title. ... UPDATE As vcsjones stated the head element is optional. That's the title one is required. Credit to mootinator for pointing

Java Minimum and Maximum values in Array

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问题 My code does not give errors, however it is not displaying the minimum and maximum values. The code is: Scanner input = new Scanner(System.in); int array[] = new int[10]; System.out.println("Enter the numbers now."); for (int i = 0; i < array.length; i++) { int next = input.nextInt(); // sentineil that will stop loop when 999 is entered if (next == 999) { break; } array[i] = next; // get biggest number getMaxValue(array); // get smallest number getMinValue(array); } System.out.println("These

Get the key corresponding to the minimum value within a dictionary

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If I have a Python dictionary, how do I get the key to the entry which contains the minimum value? I was thinking about something to do with the min() function... Given the input: {320:1, 321:0, 322:3} It would return 321 . Best: min(d, key=d.get) -- no reason to interpose a useless lambda indirection layer or extract items or keys! Mark Rushakoff Here's an answer that actually gives the solution the OP asked for: >>> d = {320:1, 321:0, 322:3} >>> d.items() [(320, 1), (321, 0), (322, 3)] >>> # find the minimum by comparing the second element of each tuple >>> min(d.items(), key=lambda x: x[1])

How to scale down a range of numbers with a known min and max value

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So I am trying to figure out how to take a range of numbers and scale the values down to fit a range. The reason for wanting to do this is that I am trying to draw ellipses in a java swing jpanel. I want the height and width of each ellipse to be in a range of say 1-30. I have methods that find the minimum and maximum values from my data set, but I won't have the min and max until runtime. Is there an easy way to do this? Let's say you want to scale a range [min,max] to [a,b] . You're looking for a (continuous) function that satisfies f(min) = a f(max) = b In your case, a would be 1 and b

Get the key corresponding to the minimum value within a dictionary

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问题 If I have a Python dictionary, how do I get the key to the entry which contains the minimum value? I was thinking about something to do with the min() function... Given the input: {320:1, 321:0, 322:3} It would return 321 . 回答1: Best: min(d, key=d.get) -- no reason to interpose a useless lambda indirection layer or extract items or keys! 回答2: Here's an answer that actually gives the solution the OP asked for: >>> d = {320:1, 321:0, 322:3} >>> d.items() [(320, 1), (321, 0), (322, 3)] >>> #

How to scale down a range of numbers with a known min and max value

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问题 So I am trying to figure out how to take a range of numbers and scale the values down to fit a range. The reason for wanting to do this is that I am trying to draw ellipses in a java swing jpanel. I want the height and width of each ellipse to be in a range of say 1-30. I have methods that find the minimum and maximum values from my data set, but I won\'t have the min and max until runtime. Is there an easy way to do this? 回答1: Let's say you want to scale a range [min,max] to [a,b] . You're