member

Why can't I modify class member variable outside any methods? [duplicate]

*爱你&永不变心* 提交于 2019-12-02 07:56:36
This question already has an answer here: Syntax error on token(s) “product1. ”VariableDeclaratorId expected after this token 1 answer syntax error on tokens, variableDeclarator expected instead 3 answers syntax error on addActionListener 3 answers I have an error with system.out.print and I don't know why? [closed] 7 answers Syntax error on token(s), misplaced construct(s) 4 answers I have a class with some variables. When I instantiate an object of that class in the main class. I can only access and modify member variables in a method, any method; not outside them. Why is that? I am stuck

C++ declaring a static object in a class

ぐ巨炮叔叔 提交于 2019-12-02 06:12:32
问题 I'm trying to declare a static object of a class A that I wrote in a different class B, like this: class A // just an example { int x; public: A(){ x = 4; } int getX() { return x; } }; class B { static A obj1; // <- Problem happens here public: static void start(); }; int main() { B::start(); } void B::start() { int x = obj1.getX(); } What I want to achieve is to get int x in B::start() to equal int x in class A (4). I tried googling all this for the past hour and all I understood was that C+

std::find on a vector of object pointers

蹲街弑〆低调 提交于 2019-12-02 05:28:23
I have a class A with a member which is a vector of object pointers of another class B class A { std::vector<B*> m_member_A Now I want to perform a std::find on m_member_A . E.g. if(std::find(m_member_A.begin(), m_member_A.end(), B_obj*) != m_member_A.end()) std::find doesn't make sense on such a vector. How do I achieve such a functionality? How would it change if it were a vector of objects of B (not pointer)? If you want to find a value pointer at by the pointer, instead of a given pointer, you can use std::find_if with a suitable functor: struct Foo { int i; }; bool operator==(const Foo&

_beginthreadex static member function

混江龙づ霸主 提交于 2019-12-02 05:17:26
How do I create a thread routine of a static member function class Blah { static void WINAPI Start(); }; // .. // ... // .... hThread = (HANDLE)_beginthreadex(NULL, 0, CBlah::Start, NULL, NULL, NULL); This gives me the following error: ***error C2664: '_beginthreadex' : cannot convert parameter 3 from 'void (void)' to 'unsigned int (__stdcall *)(void *)'*** What am I doing wrong? jalf Sometimes, it is useful to read the error you're getting. cannot convert parameter 3 from 'void (void)' to 'unsigned int (__stdcall *)(void *)' Let's look at what it says. For parameter three, you give it a

Why can't I change the values in a range of type structure?

主宰稳场 提交于 2019-12-02 03:09:40
This is my first post so please "Go" easy on me. :) ... I am quite familiar with many traditional programming languages but I am new to Go and having trouble understanding the use of slices and ranges. The program code and comments below illustrate my consternation. Thank you! package main import ( "fmt" "time" ) type myStruct struct { Name string Count int } Wrote my own Mod function because I could not find on in the Go libraries. func modMe(mod int, value int) int { var m int var ret int m = value / mod ret = value - m*mod return ret } func main() { mod := 4 cnt := 16 fmt.Printf("Record mod

get function member address

风格不统一 提交于 2019-12-02 02:40:14
问题 Is there any way to get the exact address of a function member? For example I have : struct foo { void print() { printf("bla bla bla"); } }; ////////////////////////////////////////////////////////////// unsigned int address = foo::print; 回答1: You can use the following syntax to declare the pointer to the member function: typedef void (foo::*address)(); address func = &foo::print; In order to call non-static member function you will need an existing instance of that class: (fooInstance.*func)

get function member address

风格不统一 提交于 2019-12-02 01:12:35
Is there any way to get the exact address of a function member? For example I have : struct foo { void print() { printf("bla bla bla"); } }; ////////////////////////////////////////////////////////////// unsigned int address = foo::print; You can use the following syntax to declare the pointer to the member function: typedef void (foo::*address)(); address func = &foo::print; In order to call non-static member function you will need an existing instance of that class: (fooInstance.*func)(); I'm not sure what you mean by "exact address". There's certainly no way of putting any address in an

C++ declaring a static object in a class

百般思念 提交于 2019-12-01 23:51:02
I'm trying to declare a static object of a class A that I wrote in a different class B, like this: class A // just an example { int x; public: A(){ x = 4; } int getX() { return x; } }; class B { static A obj1; // <- Problem happens here public: static void start(); }; int main() { B::start(); } void B::start() { int x = obj1.getX(); } What I want to achieve is to get int x in B::start() to equal int x in class A (4). I tried googling all this for the past hour and all I understood was that C++ doesn't allow static objects' declarations. Is that correct? If so, here's my question. How can I get

Private member function that takes a pointer to a private member in the same class

情到浓时终转凉″ 提交于 2019-12-01 22:45:21
问题 How can I do this? (The following code does NOT work, but I hope it explains the idea.) class MyClass { .... private: int ToBeCalled(int a, char* b); typedef (MyClass::*FuncSig)(int a, char* b); int Caller(FuncSig *func, char* some_string); } I want to call Caller in some way like: Caller(ToBeCalled, "stuff") and have Caller call ToBeCalled with whatever parameters it feels needs passing. If at all possible I want to keep everything encapsulated in the private part of my class. In reality, I

Private member function that takes a pointer to a private member in the same class

最后都变了- 提交于 2019-12-01 21:24:49
How can I do this? (The following code does NOT work, but I hope it explains the idea.) class MyClass { .... private: int ToBeCalled(int a, char* b); typedef (MyClass::*FuncSig)(int a, char* b); int Caller(FuncSig *func, char* some_string); } I want to call Caller in some way like: Caller(ToBeCalled, "stuff") and have Caller call ToBeCalled with whatever parameters it feels needs passing. If at all possible I want to keep everything encapsulated in the private part of my class. In reality, I'd have about 50 functions like ToBeCalled , so I can't see a way to avoid this. Thanks for any