mean

how to calculate combined column mean value in R

喜夏-厌秋 提交于 2019-12-25 19:05:40
问题 I want to make representative combined column and calculate mean. for example, there are BILL_AMT(1,2,3,4,5,6). but i want BILL_AMT <- which includes mean value of all BILL_AMT values. how can i do? 回答1: Please provide a reproducible example of your data. Just assuming what you're trying to do: data <- data.frame(x = rep(1:10,1), y = rep(11:20, 1)) data %>% rowwise() %>% mutate(mean = mean(x + y + ...)) Based on your comment: fill in your variables for x + y + ... 来源: https://stackoverflow

How to create list from 100 elements to list of 10 [duplicate]

故事扮演 提交于 2019-12-25 18:53:53
问题 This question already has answers here : What is the most “pythonic” way to iterate over a list in chunks? (35 answers) Closed 4 months ago . I have small brain fade today and I believe it will be faster to get hint here than wondering for an hour. I have list A of 100 elements. How can I create another list(B) basing on list A, that will have 10 elements, so that each element is mean of 10 elements from list A? Thank you in advance. e.g. A = [10,10,10,10,10,20,20,20,20,20,30,30,30,30,30,40

Caching the mean of a Vector in R (list)

喜欢而已 提交于 2019-12-25 07:57:46
问题 This is a follow up to Caching the mean of a Vector in R and is specifically about the last line of code list(set = set, get = get, setmean = setmean, getmean = getmean) I am not understanding what the list is doing. The answer given at the linked question: list() returns the 'special vector' containing all of the functions just defined does not make much sense to me. I think that makeVector should be returning an object which has the approriate set and get methods, but now sure how this list

SSRS Chart w/Series and Mean

爷,独闯天下 提交于 2019-12-25 07:05:15
问题 I have a chart I'm making in SSRS. My database is returning data like this: Period Name, Question, Answer, Count, Mean, Median Nov 09, Can Haz Chezbrgr, Yes, 5, 4, 3.1 Nov 09, Can Haz Chezbrgr, No, 3, 4, 3.1 Nov 09, Can Haz Chezbrgr, DK, 2, 4, 3.1 Period Name is the primary grouping, question is the same for all rows. Answer varies as does count. The mean and median are calculated based on period name & count, but are the same for all values in each period. I have a chart in SSRS that's

how to calculate mean for every five minutes in a loop by using R?

与世无争的帅哥 提交于 2019-12-25 07:04:18
问题 I would like to calculate visibility mean every five minutes. I try to use for loop, but it is not successful. Can someone help to fix it? The data is attached time V1 harmonic_ave visibility 1 00:00 0.17652184 0 5.6650213 2 00:01 0.23150237 0 4.3196102 3 00:02 0.35068959 0 2.8515246 4 00:03 0.48666769 0 2.0547902 5 00:04 0.54693229 0 1.8283799 6 00:05 0.58146776 0 1.7197858 7 00:06 0.69513934 0 1.4385605 8 00:07 0.90809604 0 1.1012051 9 00:08 1.02237511 0 0.9781146 10 00:09 0.94165997 0 1

error: name lookup of 'i' changed for ISO 'for' scoping

不羁岁月 提交于 2019-12-25 06:58:50
问题 I have looked at other topics similar to this and still cannot find out what is wrong with my code. The following is a function in my program to find the Mean (Average) of Arrays. I get the error in the title: error: name lookup of 'i" changed for ISO 'for' scoping. following with note: if you use '-fpermissize' g++ will accept your code. double GetMean ( double Array[], int ArrayLength ) { int Sum, Mean; for ( int i = 0; i < ArrayLength; i++ ) { Sum = Sum + Array[i]; } Mean = Sum / Array[i];

aggregate data-frame by team in r

China☆狼群 提交于 2019-12-25 04:14:00
问题 I have a data-frame "dat" that this similar to the following: team a b c 1 5 6 2 1 2 8 1 1 5 10 30 2 1 3 55 2 4 4 4 2 6 11 66 3 10 1 .5 3 3 4 24 3 4 44 60 I am trying to turn this into a data-frame so that the mean of each variable (a,b, and c) is calculated for each team. So that the final result looks like: team a b c 1 4 8 11 2 3.7 6 41.7 3 5.7 16.3 28.2 They don't all have to be to 1 decimal, but the point is the same. Thank you! 回答1: We can some either dplyr/data.table or base R

R code - Pollutant Mean is producing NaNs

五迷三道 提交于 2019-12-25 03:34:39
问题 I'm pretty close to finishing this R program, but the result keeps giving me NaN. It's supposed to find the nitrate or sulfate mean across a bunch of csv files. Would anyone know where the code might be going wrong? Below is the program description. It seems pretty self explanatory, it's just I'm somewhat stumped. If you need anymore details please let me know. Thanks pollutantmean <- function(directory, pollutant, id = 1:332) { ## 'directory' is a character vector of length 1 indicating ##

create aggregate column based on variables with R [duplicate]

佐手、 提交于 2019-12-25 03:29:18
问题 This question already has answers here : Calculating statistics on subsets of data [duplicate] (3 answers) Closed 3 years ago . I apologize in advanced if this is somewhat of a noob question but I looked in the forum and couldn't find a way to search what I am trying to do. I have a training set and I am trying to find a way to reduce the number of levels I have for my categorical variables (In the example below the category is the state). I would like to map the state to the mean or rate of

R: Standardize using mean and sd functions

限于喜欢 提交于 2019-12-25 02:19:34
问题 I'm trying to do a simple transformation. I've used the following code and it worked fine: data_stdz <- transform(data_header, z.v1 = v1+2) But, I can't get the following code to work: data_stdz <- transform(data_header, z.v1 = (v1 - mean(v1))/(2*sd(v1)) I've also tried to get just the mean function to work: data_stdz <- transform(data_header, z.v1 = mean(v1) But, I keep getting the following error: Error: unexpected symbol in: "data_std2 <- transform(data_header, z.v1 = mean(v1) data_std2"