问题
I would like to calculate visibility mean every five minutes. I try to use for loop, but it is not successful. Can someone help to fix it? The data is attached
time V1 harmonic_ave visibility
1 00:00 0.17652184 0 5.6650213
2 00:01 0.23150237 0 4.3196102
3 00:02 0.35068959 0 2.8515246
4 00:03 0.48666769 0 2.0547902
5 00:04 0.54693229 0 1.8283799
6 00:05 0.58146776 0 1.7197858
7 00:06 0.69513934 0 1.4385605
8 00:07 0.90809604 0 1.1012051
9 00:08 1.02237511 0 0.9781146
10 00:09 0.94165997 0 1.0619545
11 00:10 0.74532231 0 1.3417014
Here is the code
for (i in seq(from=1,to=1440,by=5)) {
AWIv<-mean(AWI1Hmean_140607$visibility[i:i+5])
}
回答1:
This will work for your sample data
#input relevant vector only
a <- c(
5.6650213,
4.3196102,
2.8515246,
2.0547902,
1.8283799,
1.7197858,
1.4385605,
1.1012051,
0.9781146,
1.0619545,
1.3417014)
# create output vector
a2 <- vector(mode= "numeric", length= length(a)/5)
# execute loop
for (i in 1:length(a2)) {
a2[i] <- mean(a[(5*i-4):(5*i)])
}
# check output
a2
[1] 3.343865 1.259924
回答2:
You can use rollapply from zoo package
Sample code
library(zoo)
data1 <- read.table(header=TRUE, text='
id time V1 harmonic_ave visibility
1 00:00 0.17652184 0 5.6650213
2 00:01 0.23150237 0 4.3196102
3 00:02 0.35068959 0 2.8515246
4 00:03 0.48666769 0 2.0547902
5 00:04 0.54693229 0 1.8283799
6 00:05 0.58146776 0 1.7197858
7 00:06 0.69513934 0 1.4385605
8 00:07 0.90809604 0 1.1012051
9 00:08 1.02237511 0 0.9781146
10 00:09 0.94165997 0 1.0619545
11 00:10 0.74532231 0 1.3417014
')
# Convert to zoo object
z <- zoo(data1$visibility, order.by=data1$time)
# Calculate mean for nonoverlapping groups of 5
# align="left": timestamp is taken from the leftmost value.
rollapply(z, 5, mean, by=5, align="left")
00:00 00:05
3.343865 1.259924
来源:https://stackoverflow.com/questions/25554565/how-to-calculate-mean-for-every-five-minutes-in-a-loop-by-using-r