mat

I have been through the documentation and didn't get a clear detailed description about UMat; however I think it has something to relate with GPU and CPU. Please help me out. Thank you. Perhaps section 3 of this document will help: [link now broken] https://software.intel.com/sites/default/files/managed/2f/19/inde_opencv_3.0_arch_guide.pdf Specifically, section 3.1: A unified abstraction cv::UMat that enables the same APIs to be implemented using CPU or OpenCL code, without a requirement to call OpenCL accelerated version explicitly. These functions use an OpenCL-enabled GPU if exists in the

I am creating a multi-dimensional MAT object, and would like to get the size of the object - e.g., const int sz[] = {10,10,9}; Mat temp(3,sz,CV_64F); std::cout << "temp.dims = " << temp.dims << " temp.size = " << temp.size() << " temp.channels = " << temp.channels() << std::endl; I believe the resulting MAT to be 10x10x9, and I'd like to confirm, but the COUT statement gives: temp.dims = 3 temp.size = [10 x 10] temp.channels = 1 I was hoping to see either: temp.dims = 3 temp.size = [10 x 10 x 9] temp.channels = 1 Or: temp.dims = 3 temp.size = [10 x 10] temp.channels = 9 How can I get the

Mat b = new Mat(); Bitmap bmp = getIntent().getExtras().getParcelable("image_send"); @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_display_image); Mat tmp = new Mat (bmp.getWidth(), bmp.getHeight(), CvType.CV_8UC1); Utils.bitmapToMat(bmp, tmp); Imgproc.cvtColor(tmp, tmp, Imgproc.COLOR_RGB2GRAY); //Imgproc.cvtColor(tmp, tmp, Imgproc.COLOR_GRAY2RGB, 4); Utils.matToBitmap(tmp, bmp); iv = (ImageView) findViewById(R.id.imageView1); iv.setImageBitmap(bmp); } Can't display the bmp. My app has stopped after taking a

I'm using the EmguCV 3.0.0 wrapper to the OpenCV 3.0 library. I'm using the Mat class in a few places. Here's an example of a single channel, 8x8 image made of double values: Mat image = new Mat(8, 8, DepthType.Cv64F, 1); The Image<> class provides reasonable means for getting and setting pixel values , and the method is identical for the Matrix<> class, but it doesn't seem as obvious for the Mat class. The only way I've figured out how to set individual pixel is using a mask: // set two pixel values, (0,0) to 9.0, (2, 3) to 42.0 Matrix<byte> mask = new Matrix<byte>(8,8); mask.Data[0, 0] = 1;

[UPDATED WITH PARTIAL ANSWER] Here is my code: void cbVideoPrerender(void *p_video_data, uint8_t **pp_pixel_buffer, int size) { // Locking imageMutex.lock(); videoBuffer = (uint8_t *)malloc(size); *pp_pixel_buffer = videoBuffer; } void cbVideoPostrender(void *p_video_data, uint8_t *p_pixel_buffer , int width, int height, int pixel_pitch, int size, int64_t pts) { // Unlocking imageMutex.unlock(); Mat img = Mat(Size(width,height), CV_8UC3, p_pixel_buffer); //cvtColor(img,img,CV_RGB2BGR); } int main(int argc, char ** argv) { libvlc_instance_t * inst; char smem_options[1000]; sprintf(smem_options

I searched to convert an IplImage* to Mat, but all answers were about the conversion to cvMat. How, can I do it? and what is the difference between Mat and cvMat? Thanks in advance here is a good solution Mat(const IplImage* img, bool copyData=false); For the records: taking a look at core/src/matrix.cpp it seems that, indeed, the constructor cv::Mat(IplImage*) has disappeared. But I found this alternative: IplImage * ipl = ...; cv::Mat m = cv::cvarrToMat(ipl); // default additional arguments: don't copy data. The recommended way is the cv::cvarrToMat function cv::Mat - is base data structure