Acces Matrix value without knowing the type opencv

问题

I am writing a function in which I need to access to a element of a Mat, but this function can receive Mat of differents types. So, if I have:

filtered.at<TypeofMat>(i) = (typeofmat) somevalue;

It only occurs to me to do something like this filtered.at<myMat.type()>(i), but obviously this does not work because type returns a int

I am stuck, Could someone give some light?

回答1:

You can convert the source matrix to a matrix of double (type CV_64F). In this way you won't lose any data due to casting. Then you can work on this matrix as usual, since you know its type. Last step is to convert back the destination image to the source type.

You need to know the number of channels of your matrices, though. A CV_assert will make sure that you're working on the correct type.

#include <opencv2/opencv.hpp>
using namespace cv;

void foo(const Mat& src, Mat& dst)
{
    // Assert number of channels
    CV_Assert(src.channels() == 3);

    // Convert to CV64F
    Mat3d _src, _dst;
    src.convertTo(_src, CV_64F);
    _dst.create(_src.size());

    // Work on _src and _dst (you know the type)
    _dst(0,0) = _src(0,0) + Vec3d(1,2,3);

    // Convert _dst to src type
    _dst.convertTo(dst, src.type());
}

int main()
{
    Mat3b img(10,10,Vec3b(0,0,0));

    Mat res;
    foo(img, res);

    // res will be CV_8UC3

    return 0;
}

There are also alternatives to this approach:

create a template function an call the appropriate specialization. See here
work on raw pointers. See here
use only OpenCV functions, that handle correctly every type. See here. This is usually the best option, if available.

回答2:

If it is a possibility, make the function receiving the openCV Mat a template function:

void f<typename T>(const Mat& m)
{
    (void) m.at<T>(0, 0);
}

use it like that:

Mat m1/* ... */;
m1.at<int>(0, 0) = 0;
f<int>(m);

来源：https://stackoverflow.com/questions/33146975/acces-matrix-value-without-knowing-the-type-opencv

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c++

OpenCV

mat